Displaying 3 results from an estimated 3 matches for "sherreal".
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etherreal
2011 May 26
2
What am I doing wrong with sapply ?
...is the same thing with statement 11 and
I get the answer I'm looking for.
9 : s <-sapply(unlist(v[c(1:length(v))]), max)
11: for(i in 1 :length(v)) v1[i] <- max(unlist(v[i]))
Shouldn't I get the same answer ?
library(XML)
rm(list=ls())
url <-
"http://webapp.montcopa.org/sherreal/salelist.asp?saledate=05/25/2011"
tbl <-data.frame(readHTMLTable(url))[2:404, c(3,5,6,8,9)]
names(tbl) <- c("Address", "Township", "Parcel", "SaleDate", "Costs");
rownames(tbl) <- c(1:length(tbl[,1]))
x <-tbl
v <- gregexpr("...
2011 Jul 05
2
Stuck ...can't get sapply and xmlTreeParse working
...sapply and is at the bottom of the code. Other stuff above line 24 works
correctly including the first couple of lines of the function hm. Should I
be using a different apply function or am I doing something wrong with
xmlTreeParse ?
library(XML)
url.montco <-
"http://webapp.montcopa.org/sherreal/salelist.asp?saledate=07/27/2011"
tbl <-data.frame(readHTMLTable(url.montco))[, c(3,5,6,8,9)]
tbl <-tbl[2: length(tbl[,1]),]
names(tbl) <- c("Address", "Township", "Parcel", "SaleDate", "Costs");
rownames(tbl) <- NULL
v <- gregex...
2011 May 15
1
Need help with text processing / string split
I used screen scraping to extract some information and put it into a table
called tbl. Now I want to modify the table a bit so the data can be more
useful. Here's the code I used:
library(XML)
rm(list=ls())
url <-
"http://webapp.montcopa.org/sherreal/salelist.asp?saledate=05/25/2011"
tbl <-data.frame(readHTMLTable(url))[2:405, c(3,5,6,8,9)]
names(tbl) <- c("Address", "Township", "Parcel", "Sale Date", "Costs")
tbl is attached as txt for your convenience. Entries in the last column of...