Displaying 3 results from an estimated 3 matches for "seqa".
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seq
2005 Jan 13
1
(no subject)
...efers to in the plot. I wrote:
leg.txt<-c("control people", "radiated ill people", "radiated healthy
people",
"pesticide exposed people")
leg.col<-c("lightblue", "gray", "lightcyan","lavender")
grA<-barplot(seqA, type = "h", col = c(colors),legend.text =
c(leg.txt),main = " Number of breaks occured on cluster A bands on
patients' sample", xlab = "patient ID", ylab = "breaks number")
but I don't know how to assign the right colors to legend's items.
Tha...
2012 Sep 13
1
problem creating an array
...is pasted below:
#========================================================================
#landscape changes
#========================================================================
##generate 3 sequences, each of length n=21; sequences named theta"n"_set1
theta1_set1=c(seq(0,1,0.005))
seqa=c(seq(0,0.50,0.005))
seqb=c(seq(0.495,0,-0.005))
theta2_set1=c(seqa,seqb)
seqc=c(seq(1,0,-0.01))
seqd=c(rep(0,100))
theta3_set1=c(seqc,seqd)
sum=numeric()
for (i in 1:201)
{ sum[i]= theta1_set1[i]+theta2_set1[i]+theta3_set1[i]
}
sum
#"n" designates the number of random #'s to be gener...
2005 Jan 13
0
(no subject)
...efers to in the plot. I wrote:
leg.txt<-c("control people", "radiated ill people", "radiated healthy
people",
"pesticide exposed people")
leg.col<-c("lightblue", "gray", "lightcyan","lavender")
grA<-barplot(seqA, type = "h", col = c(colors),legend.text =
c(leg.txt),main = " Number of breaks occured on cluster A bands on
patients' sample", xlab = "patient ID", ylab = "breaks number")
but I don't know how to assign the right colors to legend's items.
Tha...