search for: se_coef

Hi, I'm trying to build a Forest Plot using the second and fourth columns in the table (test.csv) below. My code is the following: curated <- data.frame("test.csv") tmp <- curated$coef tmp1 <- curated$se_coef plt <- metaplot(tmp, tmp1, xlim = c(-.45, .45)) I keep getting the following error at the last line and am not sure why: Error in if (is.na(lower[i] + upper[i])) next : argument is of length zero For the metaplot() function, the help page looks like at a minimum I need to input the point est...

...intercept; beta_intercept, beta_slope and age) OR.naive = exp(1.6*coef(naive)) (till here works, the problem is with the confidence interval) I tried to get the Standard error from the variance, but I?m not sure if this can be done as I?ve done. Var_coef <- 1.6^2*var(coef(naive)) SE_coef <- Var_coef/sqrt(nsample) ########## I thi k this is correct OR.naive.inf <- exp(OR.naive - (1.96 * SE_coef)) OR.naive.sup <- exp(OR.naive + (1.96 * SE_coef)) if I used logit link I would get the CI with confint(na?ve) command, but with probit I don't think so...

...t; > > > (till here works, the problem is with the confidence interval) > > > > I tried to get the Standard error from the variance, but I?m not sure if > this can be done as I?ve done. > > > > > > Var_coef <- 1.6^2*var(coef(naive)) > > SE_coef <- Var_coef/sqrt(nsample) ########## I thi k > this is correct > > > > OR.naive.inf <- exp(OR.naive - (1.96 * SE_coef)) > > OR.naive.sup <- exp(OR.naive + (1.96 * SE_coef)) > > > > if I used logit link I would get the CI with confi...

The 3.2.4-revised version turned out to give trouble for some of CRAN's subsystems. Accordingly, a rebadged version 3.2.5 is now released; it only differs in the version number and a few clean-up items. If you have a working install of 3.2.4-revised there should be no reason to upgrade it. You can get the source code from http://cran.r-project.org/src/base/R-3/R-3.2.5.tar.gz or wait for it