search for: schalk

...unning ldapadd against a ldif file which contains only posix related attrs, I thought, running smbpasswd -a would add the necessary samba attrs, but that's not the case. I see this problem: $ ldapadd -x -D "cn=Manager,dc=tuxgeek,dc=de" -f /tmp/posix.ldif -W adding new entry "uid=schalke,ou=users,dc=tuxgeek,dc=de" $ ldapsearch -xLLL uid=schalke dn: uid=schalke,ou=users,dc=tuxgeek,dc=de uid: schalke objectClass: account objectClass: posixAccount cn: schalke uidNumber: 10100 gidNumber: 10023 homeDirectory: /home/TUXGEEK/schalke loginShell: /bin/bash [root at tiffy openldap]$...

...tates that this is based on the method as published by Hartigan (found this paper: http://www.jstor.org/pss/2284710 through wikipedia). What is the relationship (if any) between the "heatmap" function in R and this technique? Is there an alternative function to use? Thanks for the help! Schalk Heunis

Hi all, When using form_for it is easy to add an id to the form using :html => {:id => ''someid''} However, how would one accomplish the same when using the form_tag ? Thank you in advance, Schalk --~--~---------~--~----~------------~-------~--~----~ You received this message because you are subscribed to the Google Groups "Ruby on Rails: Talk" group. To post to this group, send email to rubyonrails-talk-/JYPxA39Uh5TLH3MbocFFw@public.gmane.org To unsubscribe from this group, send...

Hi I have made a 2 shared directories on my Samba Server, then I have made the one read only and the other one access to a spesific user, but now I want to hide the one directory so that only that user can see it. How do I do that . Thanks Schalk

...ib/ruby/gems/1.8/gems/rails-2.2.2/lib/initializer.rb:112:in `run'' ... 29 levels... from C:/InstantRails/ruby/lib/ruby/site_ruby/1.8/rubygems/custom_require.rb:31:in `require'' from ./script/server:3 from -e:2:in `load'' from -e:2 Any help and pointers appreciated, Schalk --~--~---------~--~----~------------~-------~--~----~ You received this message because you are subscribed to the Google Groups "Ruby on Rails: Talk" group. To post to this group, send email to rubyonrails-talk-/JYPxA39Uh5TLH3MbocFFw@public.gmane.org To unsubscribe from this group, send...

Does anyone have any suggestions for a best practice implementation of Recaptcha (or other captchas - if you recommend going another route, I''m all ears)? I''ve found the recaptcha gem and a plugin but I don''t know which is the best implementation, and I haven''t found a thorough tutorial plus example code for either. Thanks -- Posted via

Hi all, I am new to R and I have got a question in regards to factors. Say I have a simple dataset like the following: Name Time Value a 1:00 1.25 a 2:00 1.26 b 1:00 1.29 b 2:00 1.28 c 1:00 1.21 c 1:30 1.20 c 2:00 1.23 I want to write a script that automatically plot value against time for a, b and c.

...should allow the other Services, in this order: sshd : myhomepc : allow exim : ALL : allow httpd : ALL : allow ftpd : ALL : allow ALL : ALL : deny What kind of protection does FreeBSD need by Default? Since OpenBSD goes around saying: "SECURE BY DEFAULT" !? Just asking..... Regards Schalk Erasmus Incredible Networks Windhoek, Namibia

R helpers   Please help me combine the simulated data to a form of table where: Hypermarket have 10 rows, supermarket have 15 rows,......., spazashops with 35 rows.   Hypermarket <- rnorm(10, mean=20000, sd=7000) Supermarket <- rnorm(15, mean=12000, sd=4000) Minimarket   <- rnorm(20, mean=10000, sd=4000) Cornershop  <- rnorm(20, mean= 8000, sd=3000) Spazashop   <- rnorm(35, mean=

How would I make a histogram using R from a table in excel that has 4 variables, but I only want to use 2 of the columns to make the histogram? [[alternative HTML version deleted]]

Hello, How can I make xtable print a comma as decimal separator? Setting the option OutDec isn't enough for xtable: library(xtable) options(OutDec = ",") x <- c(1.1, 1.2, 1.3) y <- c(2.3, 2.2, 2.1) d <- data.frame(x, y) d print(xtable(d)) Thanks! Jakson Aquino

Hi, I'm trying to use a list of symbols as one of the values to be substituted in a substitute expression, but I can't figure out how to write the correct expression for my problem. Let me illustrate a simple example of what I'm trying to do. The following code snippet will evaluate to '5': symname <- 'foo' foo <- 5 expr <- substitute(c(expr), list(expr =

Hi, data.frame(x1=1:11,x2=2:12,x3=3:13,y=4:14) I want to extract all the columns that with the name 'x?'. Is there a general way to do this in R? Regards, Peng

Hi, I want to plot the residuals of a least-squares regression. plot(lm(y~x), which=1) does this, but it plots the y-axis of my data on the x-axis of the residuals plot. That is, it plots the residual for each y-value in the data. Can I instead use the x-axis of my data as the x-axis of the residuals plot, showing the residual for a given x? Thanks! Jason Priem University of North

I was wondering if anyone could help me with a problem. I need to randomly select, say 500 subjects from the 5000 cases I have and then need to run a test to create 500 sample means and graph the means in a histogram. Does anyone know how to do this. I'm not that familiar with R so please be patient with me. Thanks a lot! Mike Hollingsworth -- View this message in context:

Hi, I've been trying to set the directory for choose.files as follows: [R2.9.0 running on XP] setwd("C:/Documents and Settings/2/Data") getwd() infile2 = choose.files(filters = Filters[c("txt","All"),], caption = "Choose ECD datafile") #<...do a bunch of stuff...> It appears the working directory isn't updated until after choose.files()

Hi, How do I access the index number of a field given I only know the field name? eg - I want to set the probability of the field 'species' higher than the other fields to use in sampling. > colprob <- array(dim=NCOL(iris)) > for(i in 1:NCOL(iris)){colprob[i]=0.5} > colprob[iris$species] = 1 #this doesn't work > colprob [1] 0.5 0.5 0.5 0.5 0.5 -- View this

Dear all, I have following two list object, both are basically collection of matrices : dat1 <- matrix(rnorm(25*6), ncol=6) dat1 <- split(dat1, seq(5,25,by=5)) dat1 <- lapply(dat1, matrix, ncol=6) dat2 <- matrix(rnorm(25*4), ncol=4) dat2 <- split(dat2, seq(5,25,by=5)) dat2 <- lapply(dat2, matrix, ncol=4) Now I want to replace last 4 columns of each matrix at "dat1"

Hi there everyone, Does anyone know if there is a different location for the Rakismet plugin? When I run: script/plugin install git://github.com/jfrench/rakismet I get a message stating that the plugin could not be found. Thanks, Schalk --~--~---------~--~----~------------~-------~--~----~ You received this message because you are subscribed to the Google Groups "Ruby on Rails: Talk" group. To post to this group, send email to rubyonrails-talk-/JYPxA39Uh5TLH3MbocFFw@public.gmane.org To unsubscribe from this group, send...

I just learned that vectors can't contain vectors, which frankly simply confuses me (can you imagine arrays or lists in any other language not being able to contain arrays or lists?). At any rate, I need to create a data structure (size to be determined at runtime) which I will instantiate and then fill with vectors using a for loop. Clearly I'm new to the R game. Data Frame doesnt seem to