search for: satisfi

Displaying 20 results from an estimated 3583 matches for "satisfi".

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2012 Dec 21
2
how to recode an ordered factor
...ear R helpers, I'm trying to recode an ordered factor to reverse its scale, but I can't figure out how to make it. I am using the Recode function provided by the Car package. I've created an ordered variable: data$o.var1 <- ordered(data$var1, levels=c(1,2,3,4), labels =c("very satisfied", "fairly satisfied", "not very satisfied", "not at all satisfied")) Now, I'd like to have a new variable ranging from 4 = Very satisfied to 1= not at all satisfied. I've tried with the following: data$or.var1 <- Recode(data$o.var1, "1 = 4; 2 =...
2007 Dec 04
1
5.1 - kernel-2.6.18-53.el5.centos.plus.i686.rpm: [Errno -1] Package does not match intended download
...icann.org/centos/5.1/centosplus/i386/RPMS/kernel-2.6.18-53.el5.centos.plus.i686.rpm: [Errno -1] Package does not match intended download Trying other mirror. http://centos-distro.cavecreek.net/centos/5.1/centosplus/i386/RPMS/kernel-2.6.18-53.el5.centos.plus.i686.rpm: [Errno 9] Requested Range Not Satisfiable Trying other mirror. (1/2): kernel-2.6.18-53.e 100% |=========================| 15 MB 00:00 ftp://repo.bioinformatics.upenn.edu/pub/centos/5.1/centosplus/i386/RPMS/kernel-2.6.18-53.el5.centos.plus.i686.rpm: [Errno -1] Package does not match intended download Trying other mirror. http://ftp...
2005 Apr 02
3
OpenSSH and Smartcard
...uSE 9.2 OpenSSH 3.9p1 I have trouble to use a Smartcard with openssh. If i try to connect directly to the Smartcard, it fails: ssh -I 0:45 localhost card-etoken.c:175:etoken_check_sw: required access right not granted card-etoken.c:631:do_compute_signature: returning with: Security status not satisfied card-etoken.c:175:etoken_check_sw: required access right not granted card-etoken.c:631:do_compute_signature: returning with: Security status not satisfied card-etoken.c:175:etoken_check_sw: required access right not granted card-etoken.c:631:do_compute_signature: returning with: Security stat...
2008 Jul 01
2
if one of 4 conditions is not satisfied
I'm trying to do realize the following: I have 4 condtions. If all conditions are satisfied I will paste("PASS") If any of these is not satisfied I will paste("FAIL"). But I have to paste the corresponding failure. ifelse is a good solution but for a 2 conditions. Maybe switch or something like this. Does anyone have an idea how to do? Thanks in advance. Adel --...
2007 Dec 06
1
Prevent kernel upgrade unless given dependencies satisfied
Dear List Members, Is there a way to prevent a kernel from being upgraded unless a list of given dependencies are satisfied? What I am getting at is sometimes updated kernels are available before the upgraded versions of the kernel modules in 'extras' are (ie drbd). If there were a way to list these modules as dependencies that must be satisfied before a kernel upgrade can be performed it would prevent a l...
2011 May 19
6
ConfBridge - Failed to find a bridge technology to satisfy capabilities
Hi, I am trying to use ConfBridge application, but it throws "Failed to find a bridge technology to satisfy capabilities 0x4 (ulaw)" error. Please see console output below. -- Executing [501 at services:9] ConfBridge("SIP/OpenSER-00000005", "1001") in new stack [May 19 13:36:05] DEBUG[7452]: app_confbridge.c:404 join_conference_bridge: Trying to find conference
2014 May 30
3
nodejs, epel, SCL
Hello, ?With SCL and epel repositories enabled, some dependencies for the package name 'nodejs' get satisfied with libs from SCL which are placed in paths that are not part of my user's environment. Is there a method to make sure that nodeJS from epel dependencies are only satisfied from epel? For example, the http parser dependency gets satisfied by nodejs010-http-parser-2.0-5.20121128gitcd01361....
2004 Jul 06
2
Generate a matrix Q satisfying t(Q)%*%Q=Z and XQ=W
...atrix(c(.1,.3,.5,.6,.2,.1,.8,1,.4,.2,.2,.9),2,6) W=matrix(c(0,.8,.4,.6,.2,0),2,3) #Create a matrix satisfying (1) is easy: A=matrix(runif(18),6,3) Q1=svd(A)$u%*%chol(Z) #For the second condition (2), a solution is given by Q2=A%*%ginv(X%*%A)%*%W I do not know how to create a matrix Q that satisfies the two conditions. I have try to construct an iterative procedure without success (no convergence): eps=10 i=0 while(eps>.5) { Q1=svd(Q2)$u%*%chol(Z) Q2=Q1%*%ginv(X%*%Q1)%*%W eps=sum(abs(Q1-Q2)) cat(i,":",eps,"\n") i=i+1 } Perhaps someone could have any idea to solve...
2007 Mar 18
2
subset by multiple columns satisfying the same condition
Hi All, I have a very simple question. Suppose I had a data frame with 100 columns, now I wanted to select rows with the values of some columns satisfying the same condition, like all equal to "Tom". I know I can use the 'and' operator "&", but it's painful if there were many columns. Can anyone give me some advice? Thanks in advance, FD [[alternative HTML
2008 Mar 05
2
satisfying netdirector package dependencies
Hello, we're looking at packaging up our current NetDirector bug fix release and we want it available as .rpm at this moment, the maintainers don't have a test environment for Centos does anyone know whether the latest versions of and Centos can satisfy Tomcat 5 and Java 1.4 JDK as dependencies? thanks in advance! -- Greg Wallace Project: www.netdirector.org Blog:
2012 Apr 20
3
xe CLI: Error code: MEMORY_CONSTRAINT_VIOLATION - trial XenServer 6.0.2 image has a bug
2003 Mar 24
1
how to show a section of a matrix neatly (or row by row) that satisfies some condition
Hi all, I want to show the rows of a matrix (100x3) of which some of its elements satisfy a certain condition. In particular, how can I display the 2 rows of my matrix one after the other and not all all elements of column 1 first, then column 2 and so on. See the following. > finest[finest[,1] > 10^3] [1] 4.960632e+13 3.612619e+04 7.668204e+12 1.001911e+04 8.886153e-01 [6]
2003 Mar 24
0
how to show a section of a matrix neatly (or row by row ) that satisfies some condition
...ows. You want: finest[finest[,1] > 10^3,] Hope this helps, Matt Wiener -----Original Message----- From: Edmond Ng [mailto:Edmond.Ng at lshtm.ac.uk] Sent: Monday, March 24, 2003 2:40 PM To: r-help at stat.math.ethz.ch Subject: [R] how to show a section of a matrix neatly (or row by row) that satisfies some condition Hi all, I want to show the rows of a matrix (100x3) of which some of its elements satisfy a certain condition. In particular, how can I display the 2 rows of my matrix one after the other and not all all elements of column 1 first, then column 2 and so on. See the following....
2009 Nov 23
1
Re moving rows which do not satisfy a condition
Hello, Considering 5 points in X-Y plain. Data is a 5*2 matrix (5 rows for samples & 2 columns for X and Y) With a distance from the origin, if a distance < 7, remove the row from the Data. After calculating the distance for each point, I can't forward because of this "Removing" problem. Anyone can help me? Data=matrix(1:10,5,2) a=rep(0,5); b=rep(0,5); for (i in
2013 May 25
1
Generating random numbers satisfying specific regression equation
Hello everybody Sorry if such a question has already been posted somewhere, but I wasn’t able to find an answer yet. I’m trying to generate random numbers for illustration purposes. The random numbers should satisfy a multiple regression equation, for example: z = 0.3 + 0.05 * x + 1.5 * y + 3 * xy I was playing around with mvrnorm (MASS), but since I’m still a newbie to R and not an educated
2013 Feb 10
3
Constrained Optimization in R (alabama)
Dear List, I'm trying to solve this simple optimization problem in R. The parameters are the exponents to the matrix mm. The constraints specify that each row of the parameter matrix should sum to 1 and their product to 0. I don't understand why the constraints are not satisfied at the solution. I must be misinterpreting how to specify the constrains somehow. library(alabama) ff <- function (x) { mm <- matrix(c(10, 25, 5, 10), 2, 2) matx <- matrix(x, 2, 2) -sum(apply(mm ^ matx, 1, prod)) } ### constraints heq <- function(x) { h <- rep(NA, 1)...
2006 Aug 16
3
Question RE Rails associations
Hi, I am new to Ruby and Rails programming and am having difficulty with the following scenario... Consider the following model: class Studio < ActiveRecord::Base has_many :movies has_and_belongs_to_many :actors end class Movie < ActiveRecord::Base belongs_to :studio has_and_belongs_to_many :actors end class Actor < ActiveRecord::Base has_and_belongs_to_many :studios
2011 Jul 21
2
Find pattern in matrix
Hello all, I'm trying to find all combinations of 4 numbers that satisfy 4 criteria, inside of a matrix (62 x 25). I've found a way to do this using for loops, but it is extremely slow because it involves checking every possible combination of numbers (567300) to see if the criteria are satisfied. Do you think there is a faster method of doing this? Or some functions that might help me out? The matrix is of species abundances, with each row representing a species (A,B,C...) and each column representing a site (1,2,3...). The numbers in the matrix tell the abundance of the species at t...
2009 Apr 08
1
Trouble with 5.2==>5.3 upgrade
...MB 05:41 http://centos.mirror.nac.net/5.3/updates/i386/RPMS/kernel-2.6.18-128.1.6.el5.i686.rpm: [Errno -1] Package does not match intended download Trying other mirror. http://ftp.lug.udel.edu/pub/centos/5.3/updates/i386/RPMS/kernel-2.6.18-128.1.6.el5.i686.rpm: [Errno 9] Requested Range Not Satisfiable Trying other mirror. http://mirrors.rit.edu/centos/5.3/updates/i386/RPMS/kernel-2.6.18-128.1.6.el5.i686.rpm: [Errno 9] Requested Range Not Satisfiable Trying other mirror. http://mirror.newnanutilities.org/pub/centos/5.3/updates/i386/RPMS/kernel-2.6.18-128.1.6.el5.i686.rpm: [Errno 9] Requested...
2008 Mar 08
1
Deleting rows satisfying a certain condition (sum of some colums>2)
I have a huge matrix and need to delete certain rows. What I need to do is: 1.In each row, calculate the sum of jth column and (J+2)th column 2. If the sum is greater than 2 then that row needs to be deleted. I have a sample matrix and my codes here. It does remove some rows but when it does, it skips the next row and each time it deletes a row, the dimension changes so it gets out of bound. I