Displaying 20 results from an estimated 3591 matches for "satisfy".
2012 Dec 21
2
how to recode an ordered factor
Dear R helpers,
I'm trying to recode an ordered factor to reverse its scale, but I can't
figure out how to make it. I am using the Recode function provided by the
Car package.
I've created an ordered variable:
data$o.var1 <- ordered(data$var1, levels=c(1,2,3,4), labels =c("very
satisfied", "fairly satisfied", "not very satisfied", "not at all
5.1 - kernel-2.6.18-53.el5.centos.plus.i686.rpm: [Errno -1] Package does not match intended download
2007 Dec 04
1
5.1 - kernel-2.6.18-53.el5.centos.plus.i686.rpm: [Errno -1] Package does not match intended download
Thank you for the great CentOS.
When trying to update from 5.0 to 5.1, I get an error regarding the
centos.plus kernel and headers, "[Errno -1] Package does not match
intended download".
What'd I do?
The end of the yum update results below:
Transaction Summary
=============================================================================
Install 11 Package(s)
Update
2005 Apr 02
3
OpenSSH and Smartcard
Hi,
I am not sure if this the right place for the question. Sorry if not ...
My System:
SuSE 9.2
OpenSSH 3.9p1
I have trouble to use a Smartcard with openssh. If i try to connect
directly to the Smartcard, it fails:
ssh -I 0:45 localhost
card-etoken.c:175:etoken_check_sw: required access right not granted
card-etoken.c:631:do_compute_signature: returning with: Security status
not satisfied
2008 Jul 01
2
if one of 4 conditions is not satisfied
I'm trying to do realize the following:
I have 4 condtions.
If all conditions are satisfied I will paste("PASS")
If any of these is not satisfied I will paste("FAIL"). But I have to paste
the corresponding failure.
ifelse is a good solution but for a 2 conditions. Maybe switch or something
like this.
Does anyone have an idea how to do?
Thanks in advance.
Adel
--
View
2007 Dec 06
1
Prevent kernel upgrade unless given dependencies satisfied
Dear List Members,
Is there a way to prevent a kernel from being upgraded unless
a list of given dependencies are satisfied?
What I am getting at is sometimes updated kernels are available
before the upgraded versions of the kernel modules in 'extras'
are (ie drbd).
If there were a way to list these modules as dependencies that
must be satisfied before a kernel upgrade can be
2011 May 19
6
ConfBridge - Failed to find a bridge technology to satisfy capabilities
Hi,
I am trying to use ConfBridge application, but it throws "Failed to
find a bridge technology to satisfy capabilities 0x4 (ulaw)" error.
Please see console output below.
-- Executing [501 at services:9] ConfBridge("SIP/OpenSER-00000005",
"1001") in new stack
[May 19 13:36:05] DEBUG[7452]: app_confbridge.c:404
join_conference_bridge: Trying to find conference bridge '1...
2014 May 30
3
nodejs, epel, SCL
Hello,
?With SCL and epel repositories enabled, some dependencies for the package
name 'nodejs' get satisfied with libs from SCL which are placed in paths
that are not part of my user's environment. Is there a method to make sure
that nodeJS from epel dependencies are only satisfied from epel?
For example, the http parser dependency gets satisfied by
2004 Jul 06
2
Generate a matrix Q satisfying t(Q)%*%Q=Z and XQ=W
Hello,
I have a question that is not directly related to R ... but I try to do it
in R ;-) :
I would like to generate a matrix Q satisfying (for a given Z, X and W) the
two following conditions:
t(Q)%*%Q=Z (1)
XQ=W (2)
where:
Q is m rows and r columns
X is p rows and m columns
D is p rows and r columns
C is r rows and r columns
with m>p,r
e.g:
m=6,
p=2
r=3
Z=matrix(c(1,.2,.5,.2,1,.45,.5,.45,1),3,3)
X=matrix(c(.1,.3,.5,.6,....
2007 Mar 18
2
subset by multiple columns satisfying the same condition
Hi All,
I have a very simple question. Suppose I had a data frame with 100 columns,
now I wanted to select rows with the values of some columns satisfying the
same condition, like all equal to "Tom". I know I can use the 'and' operator
"&", but it's painful if there were many columns.
Can anyone give me some advice? Thanks in advance,
FD
[[alternative HTML version deleted]]
2008 Mar 05
2
satisfying netdirector package dependencies
Hello,
we're looking at packaging up our current NetDirector bug fix release
and we want it available as .rpm
at this moment, the maintainers don't have a test environment for Centos
does anyone know whether the latest versions of and Centos can satisfy
Tomcat 5 and Java 1.4 JDK as dependencies?
thanks in advance!
--
Greg Wallace
Project: www.netdirector.org
Blog: www.jocsflorals.blogspot.com
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2012 Apr 20
3
xe CLI: Error code: MEMORY_CONSTRAINT_VIOLATION - trial XenServer 6.0.2 image has a bug
2003 Mar 24
1
how to show a section of a matrix neatly (or row by row) that satisfies some condition
Hi all,
I want to show the rows of a matrix (100x3) of which some of its elements satisfy a certain condition. In particular, how can I display the 2 rows of my matrix one after the
other and not all all elements of column 1 first, then column 2 and so on. See the following.
> finest[finest[,1] > 10^3]
[1] 4.960632e+13 3.612619e+04 7.668204e+12 1.001911e+04 8.886153e-01
[6] 6....
2003 Mar 24
0
how to show a section of a matrix neatly (or row by row ) that satisfies some condition
...Edmond Ng [mailto:Edmond.Ng at lshtm.ac.uk]
Sent: Monday, March 24, 2003 2:40 PM
To: r-help at stat.math.ethz.ch
Subject: [R] how to show a section of a matrix neatly (or row by row) that
satisfies some condition
Hi all,
I want to show the rows of a matrix (100x3) of which some of its elements
satisfy a certain condition. In particular, how can I display the 2 rows of
my matrix one after the
other and not all all elements of column 1 first, then column 2 and so on.
See the following.
> finest[finest[,1] > 10^3]
[1] 4.960632e+13 3.612619e+04 7.668204e+12 1.001911e+04 8.886153e-01
[6] 6....
2009 Nov 23
1
Re moving rows which do not satisfy a condition
...x(1:10,5,2)
a=rep(0,5);
b=rep(0,5);
for (i in 1:5))
{
for (k in 1:2)
{
a[i,k]=a[i,k]+(Data[i,k])^2
}
b[i,j]=(a[i,j])^0.5 # distance from the origin
}
Thank you,
Jin
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2013 May 25
1
Generating random numbers satisfying specific regression equation
Hello everybody
Sorry if such a question has already been posted somewhere, but I wasn’t able to find an answer yet.
I’m trying to generate random numbers for illustration purposes.
The random numbers should satisfy a multiple regression equation, for example:
z = 0.3 + 0.05 * x + 1.5 * y + 3 * xy
I was playing around with mvrnorm (MASS), but since I’m still a newbie to R and not an educated statistician and wasn’t able to solve this.
Thanks for any suggestions or hints.
Best
Tobias
[[alternative HTML ver...
2013 Feb 10
3
Constrained Optimization in R (alabama)
Dear List,
I'm trying to solve this simple optimization problem in R. The parameters
are the exponents to the matrix mm. The constraints specify that each row
of the parameter matrix should sum to 1 and their product to 0. I don't
understand why the constraints are not satisfied at the solution. I must be
misinterpreting how to specify the constrains somehow.
library(alabama)
ff <-
2006 Aug 16
3
Question RE Rails associations
...using a movies_studios table)
The question I want to answer is, given an actor_id and studio_id, how
do I find all related movies? Or, stated differently, how do I find all
movies for a given studio/actor combination?
I have come up with several possible alternatives, but none of them
really satisfy-- or, at least, I think it should be able to be done
better. My possible choices are:
1. Use straight SQL -- disregarded as not the "Ruby Way"
2. Use find_by_sql -- ditto (although, perhaps less so)
3. Do the following:
Movie.find_by_studio_id(<studio id>).collect do |movie|...
2011 Jul 21
2
Find pattern in matrix
Hello all,
I'm trying to find all combinations of 4 numbers that satisfy 4 criteria,
inside of a matrix (62 x 25). I've found a way to do this using for loops,
but it is extremely slow because it involves checking every possible
combination of numbers (567300) to see if the criteria are satisfied. Do
you think there is a faster method of doing this? Or some funct...
2009 Apr 08
1
Trouble with 5.2==>5.3 upgrade
I've updated two 5.2 systems without a hitch. But this third one is
giving me some grief. See errors below.
Googling for "Package does not match intended download" turns up a bunch
of hits, but none of them (that I've seen) offers any working solution.
Can someone suggest how to overcome the following error(s)
Thanks a bunch!
Downloading Packages:
(1/1): kernel-2.6.18-128.
2008 Mar 08
1
Deleting rows satisfying a certain condition (sum of some colums>2)
...if (SS[i,j]+SS[i,j+nt]> ms){
SS=SS[-i,]
nr=dim(SS)[1] #this doesn't update nr in the outer for loop. why?
print(nr) }
}
# i=i-1 #this doesn't help to avoid skipping rows
}
SS;
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