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Dear R users, I want to aggregate all *d *data from all combination of n *plots* taken by k. Thank very much! My data is like that: plot d 1 14 1 13 1 12 1 14 1 18 1 20 1 21 1 43 1 108 1 43 2 41 2 61 2 83 2 61 2 84 2 45 2 21 2 12 2 11 ... 100 10 100 12 -- --- Catalin-Constantin ROIBU Forestry engineer, PhD Forestry Faculty of Suceava

Thanks. This is exactly the doubt I had. Rui Barradas ?s 05:26 de 05/08/2018, Kenny Bell escreveu: > This should more clearly illustrate the issue: > > c(1, 2, 3, 4)[-seq_len(4)] > #> numeric(0) > c(1, 2, 3, 4)[-seq_len(3)] > #> [1] 4 > c(1, 2, 3, 4)[-seq_len(2)] > #> [1] 3 4 > c(1, 2, 3, 4)[-seq_len(1)] > #> [1] 2 3 4 > c(1, 2, 3, 4)[-seq_len(0)]

Dear all. I am searching for KMeans ++ for R. I cannot find it. Do you know any package with it? Best regards, Rui

?s 15:51 de 04/08/2018, I?aki ?car escreveu: > El s?b., 4 ago. 2018 a las 15:32, Rui Barradas > (<ruipbarradas at sapo.pt>) escribi?: >> >> Hello, >> >> Maybe I am not understanding how negative indexing works but >> >> 1) This is right. >> >> (1:10)[-1] >> #[1] 2 3 4 5 6 7 8 9 10 >> >> 2) Are these right? They

I have a problem about reading data into R. There is a "\n" between each pair of data, like: -155.65 -155.77 -155.40 -155.46 -155.52 -155.34 ... Could anyone tell me how to read in such data? Thanks! Rui

Short question: Is it possible to use statistical tests, like the Augmented Dickey-Fuller test, in functions with for-loops? If not, are there any alternative ways to scale measures? Detailed explanation: I am working with time-series, and I want to flag curves that are not stationary and which display pulses, trends, or level shifts. >df DATE ID VALUE2012-03-06 1

Hi Rui, > so I'd like to be an owner of the new linkers (both for ELF and COFF), ... Sounds good to me. Do you mind if I add myself as a code owner for LLD Core / MachO, since I'll be continuing to work on that? Cheers, Lang. On Wed, Jul 15, 2015 at 2:17 AM, Renato Golin <renato.golin at linaro.org> wrote: > On 15 July 2015 at 00:08, Rui Ueyama <ruiu at google.com>

Hello, I'm cc'ing R-Help. Sorry but your question was asked 3.5 years ago, I really don't remember it. Can you please post a question to R-Help, with a reproducible example that describes your problem? Rui Barradas ? Citando catalin roibu <catalinroibu at gmail.com>: > Dear Rui, > ? > I helped me some time ago with a code..... regarding aggregated data >

Hello, I have a matrix with values, with columns c1..cn. I need the values to be normalized between 0 and 1 by column. Therefor, the 0 should correspond to the minimum value in the column c1 and 1 should correspond to the maximum value in the column c1. The remaining columns should be organized in the same way. Does a function in R exists for this purpose? Thanks, Rui [[alternative HTML

Hi, I have a small problem with the function split() and would appreciate your help. I have a table called ?XXX? with 2 columns and 49 rows. The 49 rows belong to 8 different levels (electrode1, ...,electrode8). I want to split the table always at the row where ?electrode1? starts again so that I can export 7 individual dataframes (numbered ?dataframe1? to ?dataframe7?) which contain always

>From looking at the headers in John Sorkin's mail, my guess is that he just replied to the other thread rather than starting a fresh email, and in his attempts to hide that, was outsmarted by Outlook. This is based on references to domains such as yahoo.com, dcn.davis.ca.us, and precheza.cz in the header, which were all involved in the certification thread. -Deepayan On Fri, Jan 27,

I am lousy at simple regex and I have not found a solution to a simple problem. I have a vector with some character values that I want to split. Sample data dd1 <- c( "XXY (mat harry)","XXY (jim bob)", "CAMP (joe blow)", "ALP (max jack)") Desired result dd2 <- data.frame( xx = c("XXY", "XXY", "CAMP",

Good afternoon. I am a master student in University of Porto in Portugal. At this moment I’m starting to use R, so I have some doubts. The aim of my analysis is: calculate a pairwise FST matrix from fasta file and creat a principal component analyses with adegenet package (I use seqinr and ape package to read this file, then I convert this file into a genind object with DNA2genind function

Hi, I am trying to use LLVM LTO. I read http://llvm.org/docs/GoldPlugin.html and have some questions. Could anyone help? 1. Can LLVMgold.so work with BFD LD instead of gold? In the description of changes in binutils 2.20, "* The plugin target has been added to bfd. It can load the same shared objects used by gold and uses them to provide basic support for new file formats.".

Hello, This is very basic and very frustrating. Suppose this: >A=5 >B=5 >C=10 > ls() "A" "B" "C" I would like this >xpto() 5 5 10 How can I do xpto()? Thanks Rui [[alternative HTML version deleted]]

Hi everyone, now I am trying to finish writing the code (I had asked for assistance on subtracting arrays) This is what I what I am running in R: > source("/home/ie/Documents/TTU/GA_Research/GLUE/R-Project/R_GLUE_Example/NSEr.R") NSEr <- function (obs, sim) { {jjh <- (as.vector(obs) - sim)^2 Xjjhs <- apply(Xjjh, 2, sum) Yii <- (obs - mean(obs))^2 Yiis <- apply(Yii, 2,

Hello, This is the sort of question that could interess others, so you should have CCed it to the list. As for the question, from the package vignette, section 3.3.6: "writeWorksheetToFile() is a wrapper function, calling loadWorkbook(), createSheet() and saveWorkbook() functions subsequently. It therefore allows for writing data into worksheets of an Excel file in one call." To

?s 22:54 de 11/06/2023, javad bayat escreveu: > Dear Rui; > Many thanks for your email. I used one of your codes, > "data2$LU[which(data2$Layer == "Level 12")] <- "Park"", and it works > correctly for me. > Actually I need to expand the codes so as to consider all "Levels" in the > "Layer" column. There are more than hundred

The new linker is quickly becoming more than just an experiment. 64-bit COFF linker is mostly feature complete, and now we are having a direct translation of the COFF linker for ELF. Historically LLD has been suffered by over-designing and over-engineering. I don't want to repeat that again in the new codebase, so I'd like to be an owner of the new linkers (both for ELF and COFF), so that

El dom., 5 ago. 2018 a las 6:27, Kenny Bell (<kmbell56 at gmail.com>) escribi?: > > This should more clearly illustrate the issue: > > c(1, 2, 3, 4)[-seq_len(4)] > #> numeric(0) > c(1, 2, 3, 4)[-seq_len(3)] > #> [1] 4 > c(1, 2, 3, 4)[-seq_len(2)] > #> [1] 3 4 > c(1, 2, 3, 4)[-seq_len(1)] > #> [1] 2 3 4 > c(1, 2, 3, 4)[-seq_len(0)] > #>