search for: rgb

...;d like to put a screenshot here but didn't find any option to. I'm using gentoo, ati-drivers-10.9 and the version of kernel is 2.6.35. Other games like Anno or WoW (with opengl) work fine. Here's the output which I was able to copy of starting the game: Code: xture to reload it as srgb fixme:d3d_surface:IWineD3DSurfaceImpl_LoadLocation 0xa933028: Downloading rgb texture to reload it as srgb fixme:d3d_surface:IWineD3DSurfaceImpl_LoadLocation 0xa9327c8: Downloading rgb texture to reload it as srgb fixme:d3d_surface:IWineD3DSurfaceImpl_LoadLocation 0xa933028: Downloading rgb texture...

Is there a means to split a vector into its individual elements without going the brute-force route for arguments to a predefined function call? offred.rgb <- c(1, 0, 0) * 0.60; ## Brute force style offred.col <- rgb(offred.rgb[1], offred.rgb[2], offred.rgb[3], names = "offred") ## Desired style offred.col <- rgb(silver.bullet(offred.rgb),...

...quot;> <g> <g id="id1" class="Slide" clip-path="url(#presentation_clip_path)"> <g class="Page"> <g class="com.sun.star.drawing.CustomShape"> <g id="id3"> <path fill="rgb(114,159,207)" stroke="none" d="M 4350,3000 L 3000,3000 3000,2100 5700,2100 5700,3000 4350,3000 Z"/> <path fill="none" stroke="rgb(52,101,164)" d="M 4350,3000 L 3000,3000 3000,2100 5700,2100 5700,3000 4350,3000 Z"/> &lt...

Based on reading 'rgb' documentation, I would have thought the following would have produced identical results. Can someone explain how to make this happen? I need to be able to specify an array of rgb values for the 'col' parameter. colnames.col <- c("black", "red", "blue"...

A quick question: Is there anywhere a listing of the RGB components of the named colours listed by colors()? For example, where would I find the RGB for "orange1" or "salmon"? When I look at an EPS file from R where I have used these colours, it seems that for: "salmon": 0.9804 0.5020 0.4471 rgb "orange1": 1 0....

...quot;> <g> <g id="id1" class="Slide" clip-path="url(#presentation_clip_path)"> <g class="Page"> <g class="com.sun.star.drawing.CustomShape"> <g id="id3"> <path fill="rgb(114,159,207)" stroke="none" d="M 4350,3000 L 3000,3000 3000,2100 5700,2100 5700,3000 4350,3000 Z"/> <path fill="none" stroke="rgb(52,101,164)" d="M 4350,3000 L 3000,3000 3000,2100 5700,2100 5700,3000 4350,3000 Z"/> <...

...ude <stdio.h> //#include <stdlib.h> //#include <sys/types.h> //#include <time.h> #define ACC_SIZE 1024 /* * Definitions */ typedef union { struct { unsigned short b; unsigned short g; unsigned short r; unsigned short a; } RGB; struct { unsigned short u; unsigned short v; unsigned short y; unsigned short a; } YUV; } GenefxAccumulator; extern void Xacc_blend_invsrccolor( int , GenefxAccumulator* , GenefxAccumulator , GenefxAccumulator* ); extern void Dacc_premultiply( int...

Hello all, I'm now using image() to show image data (in my case dumps of SOM weights) but would like to show RGB colour data, not just single "z" colour values. I've currently been using seq() to skip 4 values, so I can show the R, G or B channels separately as "z". But is there a way I can show all three channels simultaneously as a proper colour image? Thanks, B. Bogart

...create transparent colour ramps? I am attempting to map shaded relief under elevation data. I know I can use the terrain.colors() with the alpha option, but I would prefer to create my own colour ramp using more vibrant colours. My most recent attempt at doing this involved generating multiple rgb colours with transparency (alpha = 0.5) and then combining these colours using colorRampPalette(). I am able to use the resulting colour ramp, but it has no transparency. # Make terrain colour ramp rgb7 <- rgb(red=0, green=255, blue=77, alpha = 0.5, maxColorValue = 255) rgb8 <-...

...ude <stdio.h> //#include <stdlib.h> //#include <sys/types.h> //#include <time.h> #define ACC_SIZE 1024 /* * Definitions */ typedef union { struct { unsigned short b; unsigned short g; unsigned short r; unsigned short a; } RGB; struct { unsigned short u; unsigned short v; unsigned short y; unsigned short a; } YUV; } GenefxAccumulator; extern void Xacc_blend_invsrccolor( int , GenefxAccumulator* , GenefxAccumulator , GenefxAccumulator* ); extern void Dacc_premultiply( int...

Everyone, I'm working with scatter plots with different colored symbols (via lattice). I'm currently using these colors for points and lines: col1 <- c(rgb(1, 0, 0), rgb(0, 0, 1), rgb(0, 1, 0), rgb(0.55482458, 0.40350876, 0.04166666), rgb(0, 0, 0)) plot(seq(along = col1), pch = 16, col = col1, cex = 1.5) I'm also using these with transparency (alpha between .5-.8 depending on the number of points). I'd like to make...

...iates, so when these dots are scattered all around, I want them to be somewhat transparent. But it seems clear that transparency isn't additive. For example, four dots with transparency set to .25 don't add to complete opacity: x = c(1,1,1,1) y = c(1,1,1,1) w = .25 plot(x,y,pch=16,col=rgb(0,0,1,.25,maxColorValue=1),cex=3,xlim=c(.8,2)) My question is the following: what function would I transform "w" by to make it so that 4*f(w) = fully opaque? The following would suggest f(w) = w^.5, but I'd appreciate if someone could confirm for applications outside this little e...

...lm(y~offset(log(t))+x1+x2+x3,poisson) f2<-gam(update.formula(as.formula(f1),~.+s(d)),poisson) anova(f1,f2) summary(f2) plot(f2) #the solid line s(d) dat<-data.frame(t,d,x1,x2,x3) datn<-transform(dat,d=0) dif<-predict(f2)-predict(f2,datn) cdif<-dif-mean(dif) points(d,cdif,cex=0.5,col=rgb(0,1,0,0.2)) #another approach to the solid line s(d) devAskNewPage(ask=T) plot(f2) premat2<-PredictMat(f2$smooth[[1]],data=dat) dim(premat2) pars<-f2$coef pars2<-pars[5:13] pars2<-as.matrix(pars2,9,1) pars2 points(d,premat2%*%pars2,cex=0.5,col=rgb(0,0.6,0.3,0.2)) #premat2%*%pars2 = cdi...

There are a lot of ways to specify colours in R plot functions (number from the palette, by name, etc.). I'd like to pass a colour from an R function to an external function, and I'd like it to have the same flexibility. To avoid having to interpret all possible colour specifications myself, I need a function to convert a general colour specification into a standard form (e.g. r,g,b

Hi, I am working on barplot. I need to plot x-axis but scale on x axis is very upto 15 while my data is upto 19. pdf("image.pdf", width=10 , height =13) par(mar=c(5,22.5,2,2)) barplot(t(data[,2:3]), beside=TRUE, col=c(rgb(.537, .769, .933),rgb(.059, .412, .659)), width = 1, horiz=TRUE,cex.names=.9, border ="white",las=1, cex.axis= 1, cex.lab=1.2) legend("topright", c("X","Y"), cex=1.5, bty="n", fill = c(rgb(.059, .412, .659),rgb(.537, .769, .933))); abline(v = 0, lwd...

On Mon, May 9, 2016 at 12:04 PM Andrey Bokhanko via cfe-dev < cfe-dev at lists.llvm.org> wrote: > Thanks Jason (and Chandler) to tell Chandler's opinion, though it still > doesn't answer my original question: > > > > Both SE and libomptarget are libraries that handle offloading, not > parallelism. I understand other libraries, to be added in the future, might

Hi All, In function "rgb", alpha parameter is supposed to set the transparency value. But in my following two examples, it didn't work: plot(1,col = rgb(1,0,0,alpha =0.8)) # as long as alpha < 1, there is no point in the plot. plot(1,col = rgb(0,0,255, alpha=254, maxColorValue=255)) # as long as alpha < 25...

I want to get a lighter shade of a color...I have a lot of colored objects and want each one printed as a foreground against a slightly lighter background. I thought I could try something like changing the alpha channel by first converting it to rgb. But prior to trying that, I'm stuck with how to get the color after converting using col2rgb() to be interpreted again as a color, rather than a simple vector? Anyone have any help/ or alternative suggestion... Thanks, -c ---------------------- TRYING WITH A SINGLE COLOR: mycol<-"...