search for: rara

Hi, How to rbind these vectors from a list?: > l <- list(a = c(1, 2), b = c(1, 2, 3)) > l $a [1] 1 2 $b [1] 1 2 3 > do.call(rbind, l) [,1] [,2] [,3] a 1 2 1 b 1 2 3 Warning message: In function (..., deparse.level = 1) : number of columns of result is not a multiple of vector length (arg 1) > -J

Hi, In fileio.c, function write_sparse() there is a bug that can lead to corrupt copies if the write() call only completes partially. for (l1 = 0; l1 < len && buf[l1] == 0; l1++) {} for (l2 = 0; l2 < len-l1 && buf[len-(l2+1)] == 0; l2++) {} sparse_seek += l1; if (l1 == len) return len; if (sparse_seek)

My intention is to give a presentation about R programming language for software developers. I would like to ask, what are the things that make R different from other programming languages? What are the specific cases where Java/C#/Python developer might say "Wow, that was neat!"? What are the things that are easy in R, but very difficult in other programming languages (like Java)?

I have a string like this st <- "SELECT COUNT(empid), COUNT(mgrid), COUNT(empname), COUNT(salary), FROM Employees" How can I remove the last comma before the FROM statement? -J

I would like to learn AsciiDoc. Is there any good examples how to use AsciiDoc with R? I know that there is packages called ascii to do this, but it would be nice to see some examples how AsciiDoc works with R. Is there an AsciiDoc distribution for Max OS X? -Johannes

Colegas: Tengo una pregunta rara, y ofrezco mis disculpas si es una tonteria. Estoy tratando de hacer unos graficos con datos recolectados cada 24 horas, con varias replicas por cada periodo de tiempo. La mejor representacion que he encontrado es hacer boxplots haciendo el tiempo una variable categorica. Sin embargo, me gustaria...

...ia en que segundo se alcanza el valor máximo, es decir, qu em ede la siguiente respuesta: a 4 40 b 2 38 c 3 63 Para ello he creado el siguiente codigo: maximo<-tapply(datos$Valor,datos$Tiempo,function(x){c(grep(max(datos$Valor),datos$Valor),max(x)}) Pero me devuelve cosas raras. Alguna idea?? gracias!!! [[alternative HTML version deleted]]

I have a vector like this: a <- c("thisIsName", "thisIsAlsoName", "andThisName") How to break this into pieces and produce a vector with unique parts: this Is Name Also and This -J

Hi, Is there an efficient way recoding variables in a data.frame using base R? My purpose is to create new variables and attach them into old data.frame. The basic idea is shown below, but how to create recoding for A, B and C and assing them into new variables? df <- data.frame(A = c(1:5), B = c(3,6,2,8,10), C = c(0,15,5,9,12)) df$A[df$A <= 3] <- "x" df$A[df$A > 3 &

...##### > library(foreign) > sashome <- "C:/Program Files/SAS Institute/SAS/V8" > folder_for_datafiles <- "M:/sasuser" > read.ssd(folder_for_datafiles, "testfile", sascmd=file.path(sashome, "sas.exe")) SAS failed. SAS program at C:\DOCUME~1\jrara\LOCALS~1\Temp\RtmpAAxO3X\file41bb5af1.sas The log file will be file41bb5af1.log in the current directory NULL Warning message: In read.ssd(folder_for_datafiles, "testfile", sascmd = file.path(sashome, : SAS return code was 2 > ################################## This temporary SAS f...

...lp/2007-March/128671.html Lo he comprobado en muchas ejecuciones y es así. Otra posibilidad que se menciona también en las consultas que he buscado ( https://www.google.es/search?q=kmeans+not+give+same+output+different+runs) es pasarle los centroides al algoritmo, pero esto no siempre -mejor dicho, raras veces- es factible. Otra cosa es el algoritmo kmeans que elijas, y aquí lanzo también una pregunta por si alguien lo conoce: probando el kmeans estándar y el bigkmeans de biganalytics (creedme que es una pequeña maravilla que divide el tiempo de ejecución por 2 ó 3 al menos, y permite manejar obj...

Hi, file.info is producing data.frame with ctime variable. Help file says that on Unix this is 'last status change' and on Windows 'creation time'. Is there a way to get 'last status change' on Windows using some R function? Thanks, Johannes

Hi, Is there a way to get different colour based on group when plotting stripchart? mydata <- data.frame(val1 = c(1.1, 3.2, 4.1, 2.5, 6.2, 5.3, 4.5, 2.2, 4.7, 2.7), val2 = c(4.2, 5.3, 3.4, 2.6, 5.3, 6.2, 7.7, 4.8, 3.4, 2.1), group = rep(0:1, 5)) mydata.stack <- stack(mydata, select=-group) stripchart(values ~ ind, data=mydata.stack, vertical=T, at=c(1.25,

Hi, How can I attach chart/plot to a excel file? I would like to create a plot in R eg. plot(1) and save it into a Excel file, eg. test.xls in a same working directory. Regrads, -J

I have timestamps from mysql database: > dput(tstamp) c(1225221868L, 1225221906L, 1225221906L, 1225230997L, 1225231000L, 1225231003L, 1225231152L, 1225231348L, 1225231351L, 1225231400L ) How to convert these into normal dates? Thanks, jrara

Hi, How do you people avoid copy-pasting and manual editing of the code posted in this list? I mean that if some one post a solution for an answer like this: > a <- 1:10 > a [1] 1 2 3 4 5 6 7 8 9 10 > a[1:5] [1] 1 2 3 4 5 > I have to copy-paste it to e.g. Tinn-R and remove "> " part of the line to try it in my R. When you keep doing this it gets quite

Hi, I'm trying to use Sweave in my .tex-documents using \usepackage{Sweave} notation. I have this line in my .bash_profile export TEXINPUT=.:/Users/jrara/Library/Frameworks/R.framework/Resources/share/texmf:$TEXINPUTS When trying to typeset this .tex document, I get an error message saying ERROR: LaTeX Error: File `Sweave.sty' not found. I tried to google this problem but could not find a solution. -Johannes > sessionInfo() R version 2.9...

Hi, I have dates in this kind of format (day, month, year): > dput(head(dates, 10)) c("6.4.7", "29.12.98", "19.10.91", "20.6.92", "2.9.3", "23.6.3", "13.7.93", "23.3.7", "26.6.95", "15.2.10") So, as you can see, there is no century. How can I change this character data into dates? Any help

I have a large dataset and I would like to make some kind of flowchart from this dataset. The idea is to show rowcounts from data subsets: data1 rows= 100000 | / \ / \ males females, rows=500000 rows=500000 /\ / \

Hi, R contains many good datasets which would be valuable in other platforms as well. My intention is to use R datasets on SQL Server as a sample tables. Is there a package that would do automatic conversion from the dataset "schema" into a SQL Server CREATE TABLE statement (and INSERT INTO statements)? For example. > str(cars) 'data.frame': 50 obs. of 2 variables: $