search for: quickref

Hi Users, I have daily series of data from 1962 - 2000, with the data for February 29th in leap years excluded, leaving 365 daily values for each year. I wish to convert the daily series to monthly series. How can I do this using the zoo package or any other package? Thanks ZABLONE OWITI GRADUATE STUDENT Nanjing University of Information, Science and Technology College of International

...unction needs to be exported for useRs/developeRs of other packages, please let us know. - By default read.zoo() does not try to produce regular series anymore. The previous version could result in misleading computations for daily financial data, affecting especially also the zoo-quickref vignette. (Thanks to Ajay Shah for pointing this out.) The old behaviour can be restored by setting `regular = TRUE'. For general introductions to the package see: vignette("zoo", package = "zoo") vignette("zoo-quickref", package = "zoo") Best w...

...unction needs to be exported for useRs/developeRs of other packages, please let us know. - By default read.zoo() does not try to produce regular series anymore. The previous version could result in misleading computations for daily financial data, affecting especially also the zoo-quickref vignette. (Thanks to Ajay Shah for pointing this out.) The old behaviour can be restored by setting `regular = TRUE'. For general introductions to the package see: vignette("zoo", package = "zoo") vignette("zoo-quickref", package = "zoo") Best w...

I have a vector that contains month and year in the format YYYYMM (e.g.“200701”, “200702”) I wish to do to things: 1. I need to convert to a date that is the last calendar day of each month. 2. I need to convert this to a date that is the last U.S. stock-exchange trading day of each month. Any advice is appreciated, mymonths <- c(200701, 200702)

I have time series observation on daily frequencies : library(zoo) SD=1 date1 = seq(as.Date("01/01/01", format = "%m/%d/%y"), as.Date("12/31/02", format = "%m/%d/%y"), by = 1) len1 = length(date1); data1 = zoo(matrix(rnorm(len1, mean=0, sd=SD*0.5), nrow = len1),  date1) plot(data1) Now I want to calculate 1. Quarterly statistics like mean, variance etc

Dear list members I have a rather large vector (part of a data frame) giving the time (date + time, POSIXct) of observations. The times are irregular (with both small and large jumps) but increasing, and there are several millions of them. I now wish to reduce my data set, so that I only have observations which are at least (for example) 60 seconds apart. Basically, I need (all) the indices

Hello all, What Ruby reference is everybodies favorite? When I''ve been looking around for documentation I haven''t found any that quite compares to php.net''s and cppreference.com''s function references. I''ve been using the one found on rubycentral, but I think that it is missing quite a bit and doesn''t have very good examples. ri is fine, but

Does anyone have flow charts or digit/key cards for some of the more popular voicemail systems out there? (shows which digits/keys to press, where it takes you, etc.) I need to create some of the new voicemail system. Send 'em my way if you have them. nt_jnewman at yahoo.com Justin ____________________________________________________________________________________ Looking for last

I have a dataframe as follows: Date time value 20110620 11:18:00 7 20110620 11:39:00 9 20110621 11:41:00 8 20110621 11:40:00 6 20110622 14:05:00 8 20110622 14:06:00 6 For every date, I want to extract the row that has the greatest time. Therefore, ending up like: 20110620 11:39:00 9 20110621 11:41:00 8 20110622 14:07:00 6 I am using for loops (for every date, find largest time value) to do

Is anyone using Pdf::Writer? I don know how to insert html tags in a pdf using Pdf::Writer, except <b> and <i> I think an idea is with Pdf::TechBook but i hadn''t seen any example till now. -- Cheers, ioana k&a http://boulangerie.wordpress.com/ -------------- next part -------------- An HTML attachment was scrubbed... URL:

...ot;its" objects have been added for creating trellis time series graphs. The functions are still under development and suggestions for improvement are welcome. For general introductions to the package see: vignette("zoo", package = "zoo") vignette("zoo-quickref", package = "zoo") Best wishes, Z _______________________________________________ R-packages mailing list R-packages at stat.math.ethz.ch https://stat.ethz.ch/mailman/listinfo/r-packages

Hi: I been having a lot of trouble trying to plot multiple time series on the same plot. What I want to do is the following: I have a table with sales per day on different states and what i would like to do is plot time series for all the diferents states in the same plot (divided in small squares, not all the time series together) so I can visualize the data; but I do not know how to do this, im

Hi R users, I have a time series variable that is only available at a monthly level for 1 years that I need to decompose to a weekly time series level - can anyone recommend a R function that I can use to decompose this series? eg. if month1 = 1200 I would to decompose so that the sum of the weeks for month1 equals 1200, etc.. Many thanks in advance for any help. -- View this message in

Hi all, I am trying to convert all the dates (all days that are not Friday) in data frame into dates to next Friday. The following works but the result is returned as vector rather than the original class. It would be greatly apprecited if you could provide any solution to this problem. Many thanks in advance. # Define arbitrary initial date value ini <- as.Date("2010/1/1",

I built some reasonably successful tools in a graphical database for reconstructing the developmental turning points for feedback loop driven natural processes. I'm trying to move it to R and am having difficulty with the very basics, i.e. a) defining time series using time as a natural number rather than a place in a table. I was also hoping b) someone might have built some of the

...lazy loading ** help *** installing help indices ** building package indices ** installing vignettes 'Rcpp-FAQ.Rnw' 'Rcpp-attributes.Rnw' 'Rcpp-extending.Rnw' 'Rcpp-introduction.Rnw' 'Rcpp-modules.Rnw' 'Rcpp-package.Rnw' 'Rcpp-quickref.Rnw' 'Rcpp-sugar.Rnw' 'Rcpp-unitTests.Rnw' ** testing if installed package can be loaded Error in dyn.load(file, DLLpath = DLLpath, ...) : unable to load shared object '/usr/local/lib/R/library/Rcpp/libs/Rcpp.so': ld.so.1: R: fatal: relocation error: file /usr/...

Hello, I'm very new to R, and so my question is simple. I have data record with 80 years of daily temperatures in one long string. The dates are also recorded, in YYMMDD format. I'd like to learn an elegant simple way to pull out the annual averages. (Obviously, every 4th year has 366 days.) I know I can set up a formal loop to create annual records and then average. But R

Hi all, Thanks a lot for anyone's help in advance. I am trying to find a way to compute the day-to-day return (log return) from a n x r matrix containing, n different stocks and price quotes over r days. The time series of prices are already split by using unstack function. For the result, I would like to see a n x (r-1) matrix, where by each entry is the day-over-day return of

...lazy loading ** help *** installing help indices ** building package indices ** installing vignettes ?? 'Rcpp-FAQ.Rnw' ?? 'Rcpp-attributes.Rnw' ?? 'Rcpp-extending.Rnw' ?? 'Rcpp-introduction.Rnw' ?? 'Rcpp-modules.Rnw' ?? 'Rcpp-package.Rnw' ?? 'Rcpp-quickref.Rnw' ?? 'Rcpp-sugar.Rnw' ?? 'Rcpp-unitTests.Rnw' ** testing if installed package can be loaded Error in dyn.load(file, DLLpath = DLLpath, ...) : ? unable to load shared object '/usr/local/lib/R/library/Rcpp/libs/Rcpp.so': ? ld.so.1: R: fatal: relocation error: file /usr/...

Hello all, I'm hoping to convert a decimal value for week of the year back to a date object. Eg: strptime(paste(2010,1:52,sep=" "),format="%Y %W") I expected (hoped?) this would give me the date for Monday of each week. Instead, it's giving me 52 values of today's date. Where am I erring? Thanks Michael _______________________________________________________