Displaying 20 results from an estimated 1053 matches for "qued".
Did you mean:
quad
2020 Sep 21
2
Help with the Error Message in R "Error in 1:nchid : result would be too long a vector"
Hello everyone,
I am using *mlogit* to analyse my choice experiment data. I have *3
alternatives* for each individual and for each individual I have *9
questions*. I have a response from *516 individuals*. So it is a panel of
9*516 observations. I have arranged the data in long format (it contains
100 columns indicating different variables and identifiers).
In mlogit I tried the following
2011 Jan 10
2
Step command failing for lm function
Hi,
I have a fairly simple linear regression using the lm function. There
are about 100 variables and 30,000 rows of data. It runs fine and
produces a decent looking R2 value. I'm interested in performing a
stepwise variable selection to see if things can be cleaned up a bit.
Calling the step function returns ONE iteration (all the variables) and
then stops. No errors are reported.
2016 Apr 14
4
Bug in by() function which works for some FUN argument and does not work for others
Dear Sirs,
I am Professor at Indira Gandhi Krishi Vishwavidyalaya, Raipur,
Chhattisgarh, India.
While taking classes, I found the *by() *function producing following error
when I use FUN=mean or median and some other functions, however,
FUN=summary works.
Given below is the output of the example I used on a built-in dataset
"mtcars", along with error message reproduced herewith:
>
2016 Apr 14
0
Bug in by() function which works for some FUN argument and does not work for others
I think you are not using the best function for what your intentions are.
Try:
> by(data=mtcars, INDICES=list(as.factor(mtcars$am)), FUN=colMeans)
: 0
mpg cyl disp hp drat wt
qsec vs
17.1473684 6.9473684 290.3789474 160.2631579 3.2863158 3.7688947
18.1831579 0.3684211
am gear carb
0.0000000
2009 Aug 30
2
error with summary(vector)??
Hello,
I get
> summary(E)
level nodes ave_nodes time
Min. : 1 Min. : 1.00 Min. : 10.71 Min. : 0.0000
1st Qu.: 237414 1st Qu.: 2.00 1st Qu.: 19.70 1st Qu.: 0.0100
Median : 749229 Median : 3.00 Median : 27.01 Median : 0.0100
Mean : 767902 Mean : 49.85 Mean : 98.89 Mean : 0.2296
3rd
2004 Mar 11
3
widen the screen place
I have this problem: my screen seems not wide enough in R. My true
computer monitor is very wide, so I wish that I can line up the text
when I stretch it wide. i.e.:
This is typical R returns:
> summary(a)
V1 V2 V3 V4
F:625 Min. :20020103 EMC : 34 Min. : 9300300
L:944 1st Qu.:20020530 BRW : 27 1st Qu.: 9323865
2016 Apr 15
4
Bug in by() function which works for some FUN argument and does not work for others
Dear All,
Thanks for your help. However, I would like to draw your attention to the
following:
Actually, I was replicating the Example 2.3, using the dataset
"brainsize.txt" given in Section 2.3.3 ("Summarize by group") at page 55,
of a famous book "R by Example" written by "Jim Albert and Maria Rizzo"
published in Springers (2012) in a Use R! Series. The
2006 Feb 21
1
feature not available
Hi
I am working with this data:
my data summary is:
> summary(spi)
open high low close volume
Min. :4315 Min. :4365 Min. :4301 Min. :4352 Min. :
0
1st Qu.:4480 1st Qu.:4497 1st Qu.:4458 1st Qu.:4475 1st
Qu.:11135
Median :4609 Median :4631 Median :4594 Median :4614 Median
:14439
Mean :4620
2006 Dec 14
5
Nicely formatted tables
If I use latex(summary(X)) where X is a data frame with four
variables I get something like
Rainfall Education Popden Nonwhite
Min. :10.00 Min. : 9.00 Min. :1441 Min. : 0.80
1st Qu.:32.75 1st Qu.:10.40 1st Qu.:3104 1st Qu.: 4.95
Median :38.00 Median :11.05 Median :3567 Median :10.40
Mean :37.37 Mean :10.97 Mean :3866
2015 May 08
3
pregunta
Estimados
Al dirigir la lectura de un folder tYA1.csv me da este error y no me percato del motivo, adjunto archivo. Espero su ayuda
Saludos
Jos?
> setwd("D:/Public/Documents/R/bioimpedancia")
> a<-read.csv("tYA1.csv",header=TRUE, sep=",", dec=".")
Error in read.table(file = file, header = header, sep = sep, quote = quote, :
more
2016 Apr 15
0
Bug in by() function which works for some FUN argument and does not work for others
> On Apr 15, 2016, at 1:16 AM, Akhilesh Singh <akhileshsingh.igkv at gmail.com> wrote:
>
> Dear All,
>
> Thanks for your help. However, I would like to draw your attention to the
> following:
>
> Actually, I was replicating the Example 2.3, using the dataset
> "brainsize.txt" given in Section 2.3.3 ("Summarize by group") at page 55,
> of a
2008 Mar 17
1
summary of summaries
Hi,
I have a few hundreds files with numerical information of different length
but with the same column structure. I use the following code to get summary
statistics
fplist <- list.files(pattern=".*analysis")
for (fp in fplist){
x2 <- read.delim(fp)
summary(x2)
}
Summary gives something like:
summary (x2)
V1 V2
2016 Apr 16
2
Bug in by() function which works for some FUN argument and does not work for others
Dear All,
I have got your core message, that it is my responsibility to determine
whether any particular function in my version of R satisfies the language
requirements at the time of your use. Jim Albert and Maria Rizzo must have
used their code, which was permitted in the R-code of their time (2012).
Therefore, I have now modified my R-code, as per R-3..2.4 version,
according to my requirement
2006 Jan 04
1
Difficulty with 'merge'
Dear R-helpers,
Happy New Year to all the helpful members of the list.
Here is the behavior I'm looking for:
> v1 <- c("a","b","c")
> n1 <- c(0, 1, 2)
> v2 <- c("c", "a", "b")
> n2 <- c(0, 1 , 2)
> (f1 <- data.frame(v1, n1))
v1 n1
1 a 0
2 b 1
3 c 2
> (f2 <- data.frame(v2, n2))
2012 Jun 13
1
How to calculate the statistcs for extracted region?
I have a binary file(a) with size of (360 720 )for the globe.I wrote the code
given below to read and extract an area (south america)from that file. when
I use summary for the whole file I got:
summary(a, na.rm=FALSE)
Min. 1st Qu. Median Mean 3rd Qu. Max. NA's
0.00 1.00 3.00 4.15 7.00 20.00 200083 .
But when I used summary for the region(b) which I extracted, I got
2005 Mar 10
2
Logistic regression goodness of fit tests
I was unsure of what suitable goodness-of-fit tests existed in R for logistic regression. After searching the R-help archive I found that using the Design models and resid, could be used to calculate this as follows:
d <- datadist(mydataframe)
options(datadist = 'd')
fit <- lrm(response ~ predictor1 + predictor2..., data=mydataframe, x =T, y=T)
resid(fit, 'gof').
I set up a
2016 Apr 17
0
Bug in by() function which works for some FUN argument and does not work for others
> On Apr 16, 2016, at 2:03 AM, Akhilesh Singh <akhileshsingh.igkv at gmail.com> wrote:
>
> Dear All,
>
> I have got your core message, that it is my responsibility to determine whether any particular function in my version of R satisfies the language requirements at the time of your use. Jim Albert and Maria Rizzo must have used their code, which was permitted in the R-code
2009 Aug 05
0
get NA from outlier{randomForest}
Hi
I have a data frame like this:
V1 V2 V3 V4
Min. :0.01146 Min. :0.0006714 Min. :0.004912 Min. : 0
1st Qu.:0.03938 1st Qu.:0.0072805 1st Qu.:0.052719 1st Qu.:1150
Median :0.04224 Median :0.0077581 Median :0.056388 Median :1150
Mean :0.04010 Mean :0.0074669 Mean :0.052602 Mean :1173
3rd
2009 Dec 19
3
DROP and KEEP statements in R
What is equivalent to DROP or KEEP statements of SAS in R?
--
This message was sent on behalf of sarjinder at yahoo.com at openSubscriber.com
http://www.opensubscriber.com/messages/r-help at r-project.org/topic.html
2011 Jul 25
1
lme convergence error
Hello, I am working from a linux 64 machine on a server with R-2.12 (I can't
update to 2.13). I am iterating through many linear mixed models for
longitudinal data and I occasionally receive the following convergence
error:
> BI.lme <- lme(cd4 ~ time + genBI + genBI:time + C1 + C2 + C11 + C12,
random =~ 1 + time | IID, data = d)
Error in lme.formula(cd4 ~ time + genBI + genBI:time +