Displaying 20 results from an estimated 120 matches for "presenation".
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2024 Mar 29
1
Output of tapply function as data frame: Problem Fixed
?s 01:43 de 29/03/2024, Ogbos Okike escreveu:
> Dear Rui,
> Thanks again for resolving this. I have already started using the version
> that works for me.
>
> But to clarify the second part, please let me paste the what I did and the
> error message:
>
>> set.seed(2024)
>> data <- data.frame(
> + Date = sample(seq(Sys.Date() - 5, Sys.Date(), by = "1
2024 Mar 29
2
Output of tapply function as data frame: Problem Fixed
Dear Rui,
Thanks again for resolving this. I have already started using the version
that works for me.
But to clarify the second part, please let me paste the what I did and the
error message:
> set.seed(2024)
> data <- data.frame(
+ Date = sample(seq(Sys.Date() - 5, Sys.Date(), by = "1 days"), 100L,
+ TRUE),
+ count = sample(10L, 100L, TRUE)
+ )
>
> # coerce
2006 Apr 19
2
PRI caller ID
Below is a snipped debug on our PRI. We are getting number only for the
CallerID but the telco says they are sending us Name and Number. We are
getting the Name in a second frame but Asterisk is not passing it to the
device it rings. The message below says "Presenation allowed of network
provided number" which leads me to believe Asterisk thinks it should not
be displaying it. Can anyone interpret this for me and maybe shed some
light on why I am not getting the caller ID name displayed? I have
asreceived in my Zapata.conf file.
< Facility (len=23...
2009 Nov 08
1
rd doc truncated with R 2.10.0
Hi,
I am routinely compiling a package and since I have moved to R 2.10.0,
it troncates some section texts in the doc:
With the following section in the rd file:
\details{
The function calls gpsbabel via the system. The gpsbabel program must
be present and on the user's PATH for the function to work see
<http://www.gpsbabel.org/>. The function has been tested on the
following
2024 Feb 23
2
help - Package: stats - function ar.ols
Hello,
Thanks for the reply Rui and for pointing out that I forgot to attach
my code. Please find attached in this email my code and data.
Thanks in advance.
Best regards, Pedro Gerhardt Gavronski.
On Fri, Feb 23, 2024 at 5:50?AM Rui Barradas <ruipbarradas at sapo.pt> wrote:
>
> ?s 16:34 de 22/02/2024, Pedro Gavronski. escreveu:
> > Hello,
> >
> > My name is Pedro
2024 Feb 23
1
help - Package: stats - function ar.ols
?s 16:34 de 22/02/2024, Pedro Gavronski. escreveu:
> Hello,
>
> My name is Pedro and it is nice to meet you all. I am having trouble
> understanding a message that I receive when use function ar.ols from
> package stats, it says that "Warning message:
> In ar.ols(x = dtb[2:6966, ], demean = FALSE, intercept = TRUE,
> prewhite = TRUE) :
> model order: 2
2023 Dec 07
1
Convert character date time to R date-time variable.
?s 16:21 de 07/12/2023, Sorkin, John escreveu:
> Colleagues,
>
> I have a matrix of character data that represents date and time. The format of each element of the matrix is
> "2020-09-17_00:00:00"
> How can I convert the elements into a valid R date-time constant?
>
> Thank you,
> John
>
>
>
> John David Sorkin M.D., Ph.D.
> Professor of
2024 Feb 02
1
gathering denominator under frac
?s 10:01 de 02/02/2024, Troels Ring escreveu:
> Hi friends - I'm plotting a ratio of bicarbonates i ggplot2 and
>
> ylab(expression(paste(frac("additive BIC","true BIC")))) worked OK - but
> now I have been asked to put the chemistry instead - so I wrote
>
>
2024 Jun 02
1
R code for overlapping variables -- count
?s 18:34 de 02/06/2024, Leo Mada via R-help escreveu:
> Dear Shadee,
>
> If you have a data.frame with the following columns:
>
> n = 100; # population size
> x = data.frame(
> ??????Sex = sample(c("M","F"), n, T),
> ??????Country = sample(c("AA", "BB", "US"), n, T),
> ??????Income = as.factor(sample(1:3, n, T))
> )
2024 Jul 13
1
Obtaining predicted probabilities for Logistic regression
?s 12:13 de 13/07/2024, Christofer Bogaso escreveu:
> Hi,
>
> I ran below code
>
> Dat = read.csv('https://raw.githubusercontent.com/sam16tyagi/Machine-Learning-techniques-in-python/master/logistic%20regression%20dataset-Social_Network_Ads.csv')
> head(Dat)
> Model = glm(Purchased ~ Gender, data = Dat, family = binomial())
> head(predict(Model,
2024 Apr 21
1
x[0]: Can '0' be made an allowed index in R?
?s 08:55 de 21/04/2024, Hans W escreveu:
> As we all know, in R indices for vectors start with 1, i.e, x[0] is not a
> correct expression. Some algorithms, e.g. in graph theory or combinatorics,
> are much easier to formulate and code if 0 is an allowed index pointing to
> the first element of the vector.
>
> Some programming languages, for instance Julia (where the index for
2024 Sep 19
1
Inquiry About R Packages for Specific Research Areas
Hello,
There is a CRAN Task View: Epidemiology that should be or have what you
are looking for.
[1] https://CRAN.R-project.org/view=Epidemiology
Hope this helps,
Rui Barradas
?s 06:29 de 19/09/2024, Aleena Shaji escreveu:
> Dear R Support Team,
>
> I hope this email finds you well.
>
> I am writing to inquire about the specific R packages that would best suit
> our
2024 Feb 02
1
gathering denominator under frac
... or if I understand correctly, simply
expression(frac(additive ~ HCO[3]^"-",
true ~ HCO[3]^"-" )))
Cheers,
Bert
On Fri, Feb 2, 2024 at 3:06?AM Rui Barradas <ruipbarradas at sapo.pt> wrote:
> ?s 10:01 de 02/02/2024, Troels Ring escreveu:
> > Hi friends - I'm plotting a ratio of bicarbonates i ggplot2 and
> >
> >
2024 Sep 17
1
(no subject)
Hmmm... typos and thinkos ?
Maybe:
mean_narm<- function(x) {
m <- mean(x, na.rm = T)
if (is.nan (m)) NA else m
}
-- Bert
On Mon, Sep 16, 2024 at 4:40?PM CALUM POLWART <polc1410 at gmail.com> wrote:
>
> Rui's solution is good.
>
> Bert's suggestion is also good!
>
> For Berts suggestion you'd make the list bit
>
> list(mean = mean_narm)
>
2024 Apr 07
1
Question regarding reservoir volume and water level
?s 13:27 de 07/04/2024, javad bayat escreveu:
> Dear all;
> I have a question about the water level of a reservoir, when the volume
> changed or doubled.
> There is a DEM file with the highest elevation 1267 m. The lowest elevation
> is 1230 m. The current volume of the reservoir is 7,000,000 m3 at 1240 m.
> Now I want to know what would be the water level if the volume rises to
2024 Jul 18
1
ggplot two-factor legend
?s 16:27 de 18/07/2024, SIBYLLE ST?CKLI via R-help escreveu:
> Hi
>
> I am using ggplot to visualise y for a two-factorial group (Bio: 0 and 1) x
> = 6 years. I was able to adapt the colour of the lines (green and red) and
> the linetype (solid and dashed).
> Challenge: my code produces now two legends. One with the colors for the
> group and one with the linetype for the
2024 Jun 15
2
code for year month day hr format
Thank you Rui. I ran the following script
df1 <- read.table("solar_hour", header = TRUE)
df1$date <- as.Date(paste(df1$year, df1$hour),
format = "%Y %j",
origin = "2012-08-01-0")
df2 <- df1[c("date", "IMF", "SWS", "SSN", "Dst", "f10")]
head(df1)
#To display all the rows
print(df2).
It gave me this
2024 Feb 23
1
help - Package: stats - function ar.ols
The data came through fine, the program was a miss. Can you paste the program into a ".txt" document like a notepad file and send that? You could also paste it into your email IF your email is configured to send text and NOT html.
TIm
-----Original Message-----
From: R-help <r-help-bounces at r-project.org> On Behalf Of Pedro Gavronski.
Sent: Friday, February 23, 2024 5:00 AM
To:
2024 Jul 18
1
ggplot two-factor legend
?s 17:43 de 18/07/2024, Rui Barradas escreveu:
> ?s 16:27 de 18/07/2024, SIBYLLE ST?CKLI via R-help escreveu:
>> Hi
>>
>> I am using ggplot to visualise y for a two-factorial group (Bio: 0 and
>> 1) x
>> = 6 years. I was able to adapt the colour of the lines (green and red)
>> and
>> the linetype (solid and dashed).
>> Challenge: my code
2024 Jun 16
2
code for year month day hr format
?s 21:42 de 15/06/2024, Jibrin Alhassan escreveu:
> Thank you Rui. I ran the following script
> df1 <- read.table("solar_hour", header = TRUE)
> df1$date <- as.Date(paste(df1$year, df1$hour),
> format = "%Y %j",
> origin = "2012-08-01-0")
> df2 <- df1[c("date", "IMF", "SWS", "SSN", "Dst",