search for: perpendicularly

Hi, I am trying to draw a perpendicular line from a point to two points. Mathematically I know how to do it, but to program it, I encounter some problem and hope can get help. Thanks. I have points, A, B and C. I calculate the slope and intercept for line drawn between A and B. I am trying to check whether I can draw a perpendicular line from C to line AB and get the x,y value for the point D

I am trying to use the angle option in polygon to create polygons filled with horizontal and vertical lines. The polygons I am crating are irregular and it the angle function appears to set the angle of the shading perpendicular to the polygon sides rather than perpendicular to the axes. Is there any way to set the angle relative to the axes rather than relative to the polygon sides?

Tena koe Simon plot(1:10, 1:10, type='n') polygon(c(2,3,6,8), c(2,5,5,3), density=20, angle=90) polygon(c(2,3,6,8), 5+c(2,5,5,3), density=20, angle=0) I don't understand your problem. Perhaps if you "provide[d] commented, minimal, self-contained, reproducible code" it would help. HTH .... Peter Alspach -----Original Message----- From: R-help [mailto:r-help-bounces at

Thanks for the question. Here is a sample of the code for my plot: Top = c(34, 39, 42, 45, 46, 41, 41, 40, 43, 38, 33, 33) Bottom = c(24, 29, 32, 36, 32, 34, 32,41, 40, 39, 29, 24) plot(1,1, col = "white", xlim = c(1.3,11.7), ylim = c(0,80), axis = FALSE, xaxt = "n") axis(1, at = c(1:12)) polygon(c(c(1:12),c(12:1)), c(top, bottom), col =

Hey, Does anyone know of an equivalent to the LaTeX \perp (perpendicular) symbol for adding to R plots? Parallel is easy enough ("||"), but I haven't been able to find a way of adding perpendicular. The plotmath documentation doesn't mention how to do it, so I'm inclined to think that it doesn't exist - but surely there must be some way of achieving the desired result,

Hi, The following command: axis(1, at= 1:50, labels= sampleNames(data)) produces an X-axis with 50 ticks and labels drawn from the sampleNames namespace. Problem is the labels at each tick are printed parallel to the x-axis and thus run into each other. How do I specify for the labels to be printed perpendicular to the x-axis? Thanks in advance. Anjan -- =================================== anjan

The angle is not based on the polygon edges, but it can seem that way if you do not use the asp=1 argument in your plot. Try this example, > plot(1:10, 1:10, type='n') > x <- c(1, 3, 5, 3) > y <- c(3, 5, 3, 1) > polygon(x, y, angle=0, density=10) > polygon(x, y + 4.5, angle=45, density=10) > polygon(x + 4.5, y + 4.5, angle=90, density=10) > polygon(x + 4.5, y,

Filling polygons with lines is a throwback to the time when the height of quality graphics was the mechanical pen plotter (a device that used a pen in a mechanical arm to draw the plot on a piece of paper). Computing and printing technology has advanced quite a bit from that day, so you may want to reconsider why you want polygons filled with lines instead of just a solid color (and I consider

Dear R users, I need to plot to perpendicular straight lines. However, although I set the coefficients so that the lines are perpendicular, they do not look to be so in the plot. Here is a minimal working example: plot(x=c(-1, 1), y=c(-1, 1)); abline(a=0, b=1/sqrt(2)); abline(a=0, b=-1/sqrt(2)) Please tell me if the same problem is valid by you. I am running R-2.10.1 on Linux. Is there a way

I would like to make my horizontal barplot vertical axis labels perpendicular to the axis. I tried las=1, srt=90; I even tried yaxt='n' thinking I'd put the labels in using mtext, but the axis continued to be drawn. Can anyone help me with this? My barplot() statement looks like this: barplot(height=foo$rebint[o1], names=foo$Unit[o1], horiz=TRUE, col=mycolors[foo$type[o1]],

Hi R-users: We need to place the y label horizontally on a plot. Instead of | l | a | b | e | l | |__________ we want | | label | | | |______________ We thank you any advice. Yours, Juan Carlos Correa, Ph.D. Profesor Asociado Escuela de Estadística Universidad Nacional-Sede Medellín

Hi! I have a question that is probably very basic, but I cannot figure out how to do it. I simply need to compare the significance of a regression slope against a slope of 1, instead of the default of zero. I know this topic has been posted before, and I have tried to use the advice given to others to fix my problem. I tried the offset command based on one of these advice threads as follows:

I seem to remember this coming up before, but I can't find it any messages I've saved or in the archives (searching by subject). I want to rotate mtext so that it's perpendicular to the right side. I tried srt=90 and lots of other values, but it seems to be ignored. Is there a way to do this? ______________________________________________________________________ Stuart Luppescu

Hi all, Given a number of points (x,y) in a plane, I'd like to plot a map of polygons, so that 1) each polygon contains exactly one point 2) the polygon defines the area for which this specific point is closer than any other point. It's a bit like a map of areas "influenced" by that point, and it's obviously a matter of intersecting the perpendicular bisectors

Hello, I want to know how to draw a line connecting each point to the x-axis perpendicularly (i.e. a vertical line). abline(v=...) seems not to work for my purpose, because it runs over the data point. Can anyone help? Thanks. Anny [[alternative HTML version deleted]]

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I'm trying to fit a simple linear regression of just Y ~ X, but both X and Y are noisy. Thus instead of fitting a standard linear model minimizing vertical residuals, I would like to minimize orthogonal/perpendicular residuals. I have tried searching the R-packages, but have not found anything that seems suitable. I'm not sure what these types of residuals are typically called

Dear all, Our quite basic function mtext() does wrong adjustments in some parameter configurations. This gets obvious when using multi line texts: There is no way to properly adjust text perpendicular to axis 2, for example. Best Jens Oehlschl?gel m <- matrix(1:9, 3) colnames(m) <- c("several\nlines", "several\nlines", "several\nlines") par(mfrow=c(2,2))

Yes! You are right ! It is perpendicular to the axis. Thank you very much! Could I choose the angle ,such as 45 degree? Best Regards! Ivy Li YMS in Production & Testing Semiconductor Manufactory International(ShangHai) Corporation #18 ZhangJiang Road, PuDong New Area, Shanghai, China Tel: 021-5080-2000 *11754 Email: Ivy_Li at smics.com -----orig--- Hi Ivy, How about x <-

Hello! I have two question that rose from trying to tacle the same problem in two differnet ways. What I want to do is to plot axes (only values or labels, no tick marks) in such a way that 'cex' can be very small, text can be perpendicular to the axis (as in axis(las=2) ) and the text is stil at the right position. Let me demonstrate with a small example: