search for: permn

Dear R-Users, I'm relativley new to R and have the following problem. I need all permutations of the vectors created by the collumns of a matrix. I will give a small example: p=3 n=2^p-1 #number of obtainable vectors mat=matrix(0,p,p) for(i in 1:p) { mat[i:1,i]=1/i } mat is now a

...e the given threshold 'q'. In other words, how often each weight is decisive in raising the cumulative sum above 'q'? Here is what I do: w <- c(3,2,1) # vector of weights q <- 4 # theshold # computes which coordinate of w is decisive in each permutation res <- sapply( permn(w), function(x) which(w == x[min(which(cumsum(x) >= q))]) ) # complies the frequencies prop.table( tabulate( res )) The problem I have is that when the weights are not unique, the which() function returns a list as opposed to a vector. I don?t know how to proceed when this happens, as tabu...

...ys and so on. I finally used the function combn([0 1],3) that I found at the following link http://www.mathworks.com/matlabcentral/fileexchange/loadFile.do?objectId=7147&objectType=FILE written by Jos van der Geest in Matlab which generated the above. How can I do this is R? I have looked at permn and combn in the combinat library and permutations and combinations in the gtools library and I am still confused as to how to get it to work. Any suggestions will be truly appreciated. Thank you Nameeta ------------------------------------------------- This email is intended only for the use...

...arias veces incrementando el largo del arreglo "MuestraS". El inconveniente esta en que al hacer las permutaciones con este arreglo de 12 espacios ya tengo problemas al parecer de memoria y posiblemente el arreglo deba ir hasta 100. Al ejecutar el siguiente código: MuestraP<-permn(MuestraS) Genera el siguiente error: Warning in vector("list", gamma(n + 1)) : Reached total allocation of 3991Mb: see help(memory.size) Es importante resaltar que en ningún momento le pido al programa que me muestra la matriz de permutaciones. Agradezco me puedan a...

...help me. I want to divide n objects in k classes and need an output with all (n+1)(n+2)/2 possibilities. For example n=4, k=3: That would be: 4 0 0 3 1 0 3 0 1 2 2 0 2 1 1 2 0 2 1 3 0 1 2 1 1 1 2 1 0 3 0 3 1 0 2 2 0 1 3 0 0 4 I tried to you use permn() or sample() but I don't know how to solve. Please help me! Best regards, Maja -- "Feel free" ? 10 GB Mailbox, 100 FreeSMS/Monat ...

...listers, I am giving part of my R code : ########################################################### n=15 m=1 library("partitions") library("gregmisc") library("combinat") x = t(restrictedparts(n-m,m)) l = length(x[,1]) for(u in 1:l){ A= unique(matrix( unlist(permn(x[u,])), ncol=m, byrow=TRUE )) } ########################################################### when I put m=1 error shows : Error in vector("list", gamma(n + 1)) : vector size specified is too large . But it works fine with other values of m (< n). Any suggestion will be highly a...

Is there a simple function or process that will create a matrix of permutations with replacement? I know that using the combinat package ###### begin R code ###### > library(combinat) > m <- t(array(unlist(permn(3)), dim = c(3, 6))) # we can get the permutations, for example 3!=6 # gives us > m [,1] [,2] [,3] [1,] 1 2 3 [2,] 1 3 2 [3,] 3 1 2 [4,] 3 2 1 [5,] 2 3 1 [6,] 2 1 3 ###### end R code ########## I'd like to include the "with r...

...CORE las respondería al igual que responde a logaritmos en > cualquier base, determinantes e inversas de matrices. > > Pero no, hay que instalar paquetes adicionales. > > Buscando encontré que el paquete *combinat* incluye dos de estas funciones > > - *combn(m,n)* > - *permn(n)* > - *e incluso mCn(m,n)* > > N es solo que haga el cálculod e cuantas son sino que las escribe todas, > por ejemplo > > > combn(4,2) > [,1] [,2] [,3] [,4] [,5] [,6] > [1,] 1 1 1 2 2 3 > [2,] 2 3 4 3 4 4 > > > per...

Dear R users, I want to perform an exact permutation of multisets. I have looked at the coin package, but it doesn't seem to offer what I am looking for. I want to perform permutations (exact - without duplications) on multisets of scalars (e.g., the multiset 0,0,1,2,2). I want to output all the possible permutations into a data frame so that each multiset permutation occupies a row (or

...uier base, determinantes e inversas de matrices. > > > > > > Pero no, hay que instalar paquetes adicionales. > > > > > > Buscando encontré que el paquete *combinat* incluye dos de estas > funciones > > > > > > - *combn(m,n)* > > > - *permn(n)* > > > - *e incluso mCn(m,n)* > > > > > > N es solo que haga el cálculod e cuantas son sino que las escribe > todas, > > > por ejemplo > > > > > > > combn(4,2) > > > [,1] [,2] [,3] [,4] [,5] [,6] > > > [1,] 1 1 1 2 2 3...

Buena tarde amigos, En días pasados hice algunas consultas y ya pude salir de las dudas que tenia en ese momento, ahora requiero de su colaboración con lo siguiente: Tengo un vector dicotomico (Binario) con la siguiente información que me surgio de algunos procesos anteriores: > MuestraS [1] 1 1 1 1 0 1 1 0 1 1 Ahora necesito hallar todas las posibles combinaciones que se puedan hacer con

...tests. I have a loop version of the program working, but it would take a few weeks to complete the job and I was hoping that someone could tell me how to do it faster? thank you kindly, Matthew Finkbeiner -------------------------------- "Sample" "C1" "C2" "PermN" 1 5 8 perm1 1 4 3 perm1 1 6 4 perm1 2 2 6 perm1 2 3 1 perm1 2 7 4 perm1 1 8 5 perm2 1 3 4 perm2 1 6 4 perm2 2 6 2 perm2 2 1 3 perm2 2 7 4 perm2 1 5 8 perm3 1 3 4 perm3 1 6 4 perm3 2 2 6 perm3 2 1 3 perm3 2 7 4 perm3 1 8 5 perm4 1 4 3 perm4 1 4 6 perm4 2 6 2 perm4 2 3 1 perm4 2 4 7 perm4 1 5 8...

...uier base, determinantes e inversas de matrices. > > > > > > Pero no, hay que instalar paquetes adicionales. > > > > > > Buscando encontré que el paquete *combinat* incluye dos de estas > funciones > > > > > > - *combn(m,n)* > > > - *permn(n)* > > > - *e incluso mCn(m,n)* > > > > > > N es solo que haga el cálculod e cuantas son sino que las escribe > todas, > > > por ejemplo > > > > > > > combn(4,2) > > > [,1] [,2] [,3] [,4] [,5] [,6] > > > [1,] 1 1 1 2 2 3...

Hello all, Let say I have 2-way contingency table: Tab <- matrix(c(8, 10, 12, 6), nr = 2) and the Chi-squared test could not reject the independence: > chisq.test(Tab) Pearson's Chi-squared test with Yates' continuity correction data: Tab X-squared = 1.0125, df = 1, p-value = 0.3143 However I want to get all possible contingency tables under this independence

En relación con lo que comenta Carlos, por ejemplo para el caso de las Variaciones sin Repetición, puede ser instructivoenseñar como se construye como por ejemplo: VsinR <- function(m, n){ return (factorial(m)/factorial(m-n))} VsinR(9,3) ------------------------- Creo que con la función factorial que viene por defecto en R puedes construir siguiendo este modelo rápidadmentecasi cualquier

...>> > > > Pero no, hay que instalar paquetes adicionales. >> > > > >> > > > Buscando encontré que el paquete *combinat* incluye dos de estas >> > funciones >> > > > >> > > > - *combn(m,n)* >> > > > - *permn(n)* >> > > > - *e incluso mCn(m,n)* >> > > > >> > > > N es solo que haga el cálculod e cuantas son sino que las escribe >> > todas, >> > > > por ejemplo >> > > > >> > > > > combn(4,2) >> >...

Question 1. I would calculate all the permutations of numbers (23,46,70,71,89) How can I write correctly the code? (Load gregmisc) > permutations (..?...) ______________________ Question 2. It's possible permute a string? ..for example: EIGER EGIER EREGI etc..etc.. Thanks, E. -- View this message in context: http://www.nabble.com/permutations-tp25834463p25834463.html Sent from the R

Hi all, I have a vector, e.g., A = c(10, 20, 30, 40). This 4 numbers have 4! = 24 different combination. I want to generate a matrix with one combination in one row, so the output would be B = 10 20 30 40 10 40 20 30 ... Does anyone know how to do this easily in R? Thank you very much. Wendy -- View this message in context:

Dear R People: Suppose I have the 4 numbers: 1,2,3,4. I would like to create a listing of the permutations of 4 items taken 4 at a time. Is there a built in function for that, please? Thanks in advance! R 2-3-1 for Windows or Linux Sincerely, Erin Hodgess Associate Professor Department of Computer and Mathematical Sciences University of Houston - Downtown mailto: hodgess at gator.uhd.edu

Hello, Suppose I have a matrix a where a= sp1 sp2 sp3 sp4 sp5 sp6 site1 1 0 1 1 0 1 site2 1 0 1 1 0 1 site3 1 1 1 1 1 1 site4 0 1 1 1 0 1 site5 0 0 1 0 0 1 site6 0 0 1 0 1 0 And I want to pack that matrix so that the upper left corner contains most of the ones and the bottom right corner contains most of the zeros so that matrix b is b= sp3 sp6 sp4 sp1 sp2 sp5 site1 1 1 1 1 0 0 site2