search for: p69

Displaying 5 results from an estimated 5 matches for "p69".

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2011 May 01
1
Longitudinal data with non-randomized subjects
...ay to estimate the treatment effect? (i.e., after joining the study, some patients may have to wait for a period of time before receiving the treatment, i.e., the situation of patient with id == 2 for the following data) Data format is like the stanford heart transplant data (Therneau et al 2000, p69), but the patients were not randomized in selection and the covariate balance is not achieved: id time censor tx x1 x21 (0,10] 1 0 x11 x122 (0,8 ] 0 0 x21 x222 (9,19] 1 1 x21 x223 (0,13] 0 1 x31 x32 Is counting process form of a Cox model (coxph with start, stop, censoring status ~ tx + x1 + x2 cov...
2007 Apr 11
1
Programming Problem (for loop, random # control, 3 dimentional graph)
...5=g(-0.5,2) p46=g(-0.5,3) p47=g(-0.5,4) p48=g(-0.5,5) p49=g(0,-0.5) p50=g(0,0) p51=g(0,.5) p52=g(0,1) p53=g(0,2) p54=g(0,3) p55=g(0,4) p56=g(0,5) p57=g(0.5,-.5) p58=g(0.5,0) p59=g(0.5,.5) p60=g(0.5,1) p61=g(0.5,2) p62=g(0.5,3) p63=g(0.5,4) p64=g(0.5,5) p65=g(1,-.5) p66=g(1,0) p67=g(1,.5) p68=g(1,1) p69=g(1,2) p70=g(1,3) p71=g(1,4) p72=g(1,5) p73=g(2,-.5) p74=g(2,0) p75=g(2,.5) p76=g(2,1) p77=g(2,2) p78=g(2,3) p79=g(2,4) p80=g(2,5) p81=g(3,-.5) p82=g(3,0) p83=g(3,.5) p84=g(3,1) p85=g(3,2) p86=g(3,3) p87=g(3,4) p88=g(3,5) p89=g(4,-.5) p90=g(4,0) p91=g(4,.5) p92=g(4,1) p93=g(4,2) p94=g(4,3) p95=g(4,...
2006 May 05
2
can you do global match regular expressions?
I cant figure out how to do global regular expressions in ruby. Im not even sure if its possible. In the "Programming Ruby" book there is no mention of it. Can you do this? text = "aaa1 bbb2 ccccc3 dddddd4 eee5" re = /\w+\d{1}/ matches = re.match text m[0] = "aaa1" m[1] = nil m[2] = nil and so on.... Is there any way to get an array of all the matches??
2000 Jan 16
2
beginner question
Hello, I recently compiled Samba 2.06 on my SCO open server box. Besides one minor warning, not real problems there. It's running, I can use the swat interface but I can not get it to do the one simple thing I need it to do. I want to have one share on my SCO box. Accessible from both windows 95 and 98. I want absolutely no security. Right now I can see the SCO box in my network
2003 Sep 25
1
Winbind ldap samba 3 BDC getent passwd answer don't retrieve domain users, can't login on the domain with users that are not on /ect/passwd + typo error ?
...ion for user [test1] -> [test1] FAILED with error NT_STATUS_N O_SUCH_USER [2003/09/25 11 Do I must create the user in local ? I want to use winbind to avoid it. Any help would be greatly appreciated. Ps Maybe , there is a typo error on the "Samba Project Documentation". P69 idmapbackend = ldapsam:ldap://slave-ldap.quenya.org If use ldapsam instead of ldap I have [2003/09/25 13:25:25, 0] sam/idmap.c:idmap_init(136) idmap_init: could not load remote backend 'ldapsam'.