search for: orderby

...m search 1-form for search by date When searching for a team for instance, the url returned will be: /rushing_offenses?search=Florida When searching by date, the url returned will be: /rushing_offenses?compiled_on=2009-07-02 Pagination has a show all button: /rushing_offenses?numteams=120&orderby=rank&sortby=asc Pagination has a show simple button: /rushing_offenses?orderby=rank&sortby=asc If I click on each page number within will paginate the URL changes to: /rushing_offenses?compiled_on=2009-07-02&orderby=rank&page=2&sortby=asc My table helper functions for sorti...

Ok, I''m sure this has to be something stupid that I''m doing (or not doing), but I can''t seem to get things to order by the specified column. class List < ActiveRecord::Base has_many :list_items, :order => "orderby" The error I get back when trying to save the link is: Unknown column ''position'' in ''order clause'': SELECT * FROM list_items WHERE (list_id = 9) ORDER BY position DESC LIMIT 1 So it looks like its just defaulting to ''position'', and...

...06-07-01 682 CAO0070694 2007-09-13 685 CAO0070694 2006-08-22 695 CAO0072477 2003-06-04 696 CAO0072477 2004-07-05 718 CAO0073505 1998-09-15 720 CAO0073505 1989-09-18 725 CAO0073505 2000-11-22 727 CAO0073505 1991-08-23 I have managed to order it by PROCHI number using orderBy(PROCHI, data=dd) what I need to do is order by PROCHI then by date of admission so that date of admission is ascending by PROCHI ascending. PROCHI date_admission 2 CAO0000713 1999-10-25 4 CAO0000713 1999-12-11 21 CAO0001743 1987-09-17 25 CAO0001743 1989-05-04...

...e the first record of traits "NA" by the mean of "BSPy01-10". I have ever tried to solve this problem by using doBy package. But, I failed. I ask for the right solutions by using doBy package or not. The commands used and the output I got are as followed: library(doBy) df<-orderBy(~group,data=df) # succeeded f1<-function(x){m<-mean(x, na.ram=TRUE); x[is.na(x)]<-m; x} # succeeded datatraits<-lapplyBy(traits~group,data=df, FUN=f1(traits)) # failed errors: mean(x, na.ram = TRUE), can not find 'traits'. Thanks in advance. Sincerely, Mao J-F [[alternati...

...ery useful doBy package, and specifically, the transformBy() function?with the lag() and diff() functions. ?It is often useful to lag or difference data within a panel, i.e., within a by-group. ?Is the following code a safe use of transformBy? Is there an alternative? First, does the initial "orderBy" statement guarantee that the Time order will be preserved in the "transformBy" statement? Second, is there an alternative to explicitly padding the differenced series with NA's? ?I received an error without c(NA,...) but maybe there is a better way. Third, the lag() function ge...

...f "BSPy01-10" in the dummy dataframe. I have ever tried to solve this problem by using doBy package. But, I failed. I ask for the advice on how to use "lapplyBy" function of "doBy" package. The commands used and the output I got are as followed: library(doBy) df<-orderBy(~group,data=df) # succeeded f1<-function(x){m<-mean(x, na.ram=TRUE); x[is.na(x)]<-m; x} # succeeded datatraits<-lapplyBy(traits~group,data=df, FUN=f1(traits)) # failed errors: mean(x, na.ram = TRUE), can not find 'traits'. dummy dataframe: > df group traits 1 BSPy0...

...2 2 4 using the "reshape" command. But when I try reshaping I don't get the desired structure: > DF.L <- reshape(DF, varying = 2:5, idvar="sub", v.names = c("x1", "x2"), times=c(1,2), direction="long") > library(doBy) > orderBy(~sub, data=DF.L) sub time x1 x2 1.1 1 1 1 2 1.2 1 2 3 4 2.1 2 1 1 2 2.2 2 2 3 4 3.1 3 1 1 2 3.2 3 2 3 4 4.1 4 1 1 2 4.2 4 2 3 4 5.1 5 1 1 2 5.2 5 2 3 4 I can get the desired result by rearranging the original dataframe, lik...

...;b1", "b2", "b2", "b2", "c1", "c2", "c2", "c2", "c3", "d1", "d2", "d3", "d4", "d4"), n1 = 1:20, n2 = 21:40 ) testDF <- orderBy( ~ v1+v2, data = testDF) rownames(testDF) <- NULL > testDF v1 v2 n1 n2 1 a a1 1 21 2 a a1 2 22 3 a a1 3 23 4 a a2 4 24 5 a a3 5 25 6 b b1 6 26 7 b b1 7 27 8 b b2 8 28 9 b b2 9 29 10 b b2 10 30 11 c c1 11 31 12 c c2 12 32 13 c c2 13 33 14 c c2 14 34 15 c c3...

Hi Folks, After loading a data set, I run the following: > kSum <- orderBy(~group,(summaryBy(DP_Level~F2 +group,data=kdata,FUN=c(mean,sd),na.rm=T))) kSum looks like this: > kSum F2 group DP_Level.mean DP_Level.sd 1 1.0 N -1.55186475 11.022245 4 2.0 N -2.48013300 10.624583 7 3.0 N -12.47671250 11.104792 10 4.0 N -13.72430950...

Dear R-users, is there some way how to pass various colnames to the following code for sorting data.frames? mydf.ordered<-with(mydf, mydf[order(colname1,colname2, colnameX, decreasing = TRUE), ]) I was trying something like Afunction<-function (mydf,colnames,decreasing=T){ mydf.ordered<-with(mydf, mydf[order(colnames, decreasing = decreasing), ]) } but it didnt work please

Hi, I want to sort a matrix by a specific variable without changing the row binding between variables. Ex. Name Sex Age Fred M 24 John M 18 Mary F 21 ordered by Age Name Sex Age John M 18 Mary F 21 Fred M 24 Thanks Angelo

*Hola!!! resulta que tengo unos datos de divisas ordenados por fechas (días) los que he convertido a formato tipo YYYY-MM-DD donde DD siempre es 01:* * * * EUR.resto$date<-as.Date(EUR.resto$date) EUR.resto$mo <- substr(EUR.resto$date,6,7) EUR.resto$yr <- substr(EUR.resto$date, 1,4)

...project.org> > Subject: Re: [R-es] Ordenar vectores correlativos > Message-ID: > <BB3B87345736EE45843CC0ADF9EEEB0D2B0D985212@hermes2.imim.es> > Content-Type: text/plain; charset="iso-8859-1" > > Hola Eva, > Otra función útil para ordenar datos es la función orderBy del paquete doBy. > > Saludos, > > Klaus. > ________________________________________ > Von: r-help-es-bounces@r-project.org [r-help-es-bounces@r-project.org] im Auftrag von Eva Prieto Castro [evapcastro@yahoo.es] > Gesendet: Dienstag, 20. September 2011 12:57 > An: r-help-...

Hello, I have the go ahead to fix documentation. For starters I will clean all extraneous crap from the markup. Then fix any errors and typos. If anyone sees any gramatical errors or typos or needed clarifications or expansions or whatever, please post them here. Or additional FAQ entries, etc, all will be considered. I hope to keep most of this conversation on the shorewall-devel list. Any

...r-help@r-project.org, Paul Geeleher <paulgeeleher@gmail.com> Message-ID:     <5c62e0070905270936s41d29926g9cb5185bc5ecc799@mail.gmail.com> Content-Type: text/plain See also this tip on the R wiki: http://wiki.r-project.org/rwiki/doku.php?id=tips:data-frames:sort Also available as the orderBy function in the doBy package. Kevin Wright On Wed, May 27, 2009 at 11:19 AM, Linlin Yan <yanlinlin82@gmail.com> wrote: > It's a very interesting problem. I just wrote a function for it: > > order.matrix <- function(m, columnsDecreasing = c('1'=FALSE), rows = > 1...