Displaying 5 results from an estimated 5 matches for "o_n".
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2013 Apr 16
3
Splitting the Elements of character vector
Dear R forum
I have a data.frame
df = data.frame(currency_type = c("EURO_o_n", "EURO_o_n", "EURO_1w", "EURO_1w", "USD_o_n", "USD_o_n", "USD_1w", "USD_1w"), rates = c(0.47, 0.475, 0.461, 0.464, 1.21, 1.19, 1.41, 1.43))
currency_type rates
1 EURO_o_n 0.470
2 EURO_o_n 0.475
3 ...
2013 Apr 23
0
Error with function
Dear R forum,
I have a data.frame as given below:
df = data.frame(tran = c("tran1", "tran2", "tran3", "tran4"), tenor = c("2w", "1m", "7m", "3m"))
Also, I define
libor_tenor_labels = as.character(c("o_n", "1w", "2w",
"1m", "2m", "3m", "4m", "5m", "6m", "7m", "8m", "9m", "10m", "11m",
"12m"))
# ________________________
> df
tran tenor
1 tran1 ...
2013 Apr 23
0
Fw: Error with function - USING library(plyr)
...7:06 AM
Dear R forum,
I have a data.frame as given below:
df = data.frame(tran = c("tran1", "tran2", "tran3", "tran4"), tenor = c("2w", "1m", "7m", "3m"))
Also, I define
libor_tenor_labels = as.character(c("o_n", "1w", "2w",
"1m", "2m", "3m", "4m", "5m", "6m", "7m", "8m", "9m", "10m", "11m",
"12m"))
# ________________________
> df
tran tenor
1 tran1 ...
2013 Apr 23
0
Fw: " PROBLEM SOLVED" - Error with function
...7:06 AM
Dear R forum,
I have a data.frame as given below:
df = data.frame(tran = c("tran1", "tran2", "tran3", "tran4"), tenor = c("2w", "1m", "7m", "3m"))
Also, I define
libor_tenor_labels = as.character(c("o_n", "1w", "2w",
"1m", "2m", "3m", "4m", "5m", "6m", "7m", "8m", "9m", "10m", "11m",
"12m"))
# ________________________
> df
tran tenor
1 tran1 ...
2004 Oct 08
0
really can't bear the pain of the broken leg
...'t bear the pain of the broken leg
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eroica 13auvoista 02 esittjstalgeriasta elokuvaajan
in love, indeed, to describe her so. Ah! Mr. Knightley, I wish