Displaying 11 results from an estimated 11 matches for "numi".
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2007 Jan 23
1
How to generate 'minor' ticks in lattice (qqmath)
Dear group,
I tried to generate labels for every second tick in lattice (qqmath).
Version: 0.14-16
Date: 2006/12/01
R version 2.4.1 (2006-12-18)
An example:
library(lattice)
numy=100
y=runif(numy,min=0,max=1)
sig=0.05
numsig=length(which(y<sig))
tck.no=11 # number of ticks
tcks=1:tck.no
labl=as.character(0.1*tcks-0.1) # label for all ticks
labl[seq(2,tck.no-1,2)]="" # delete
2011 Aug 25
2
within-groups variance and between-groups variance
...leveli <- levels[i]
levelidata <- variable[groupvariable==leveli,]
levelilength <- length(levelidata)
# get the mean and standard deviation for group i:
meani <- mean(levelidata)
sdi <- sd(levelidata)
numi <- (levelilength - 1)*(sdi * sdi)
denomi <- levelilength
numtotal <- numtotal + numi
denomtotal <- denomtotal + denomi
}
# calculate the within-groups variance
Vw <- numtotal / (denomtotal - numlevels)
return(...
2011 Jul 05
1
How to translate string to variable inside a command in an easy way in R
I want to write a function that get 2 strings y and z and does the following
R command.
temp<-qq1[qq1$z==y,]
for example if it get y="AMI" and z="PrimaryConditionGroup"
It should do the following
temp<-qq1[qq1$PrimaryConditionGroup=="AMI",]
I could do it by the following function that is ugly and I wonder if there
is an easier way to do it espacielly when temp
2012 Mar 12
1
Speeding up lots of calls to GLM
...quot;")
df = cbind(df,gtypes)
names(df) = c("sid", "status", snps)
times = c()
for(i in seq(10,100, by=5)){
if(i==100){Rprof()}
time = system.time((pvals = getInteractions2(df[,1:i], 3, 2)))
print(time)
times = rbind(times, time)
if(i==100){Rprof(NULL)}
}
numI = function(n){return(((n^2)-n)/2)}
timings = cbind(seq(10,100,by=5), sapply(seq(10,100,by=5), numI),times)
--
David Kavanagh
Nephrology Research, Centre of Public Health, Queen's University Belfast, A
floor, Tower Block,
City Hospital, Lisburn Road, BT9 7AB, Belfast, United Kingdom
[[alte...
2013 Jul 18
2
001: RELIABILITY FIX: March 15, 2013
...this. It could be the source of some issues I am seeing with
mpirun/mpiexec.hydra/ssh (post earlier today), and information about
what it leads to (and any signatures) would be helpful. Thanks.
--
Professor Laurence Marks
Department of Materials Science and Engineering
Northwestern University
www.numis.northwestern.edu 1-847-491-3996
"Research is to see what everybody else has seen, and to think what
nobody else has thought"
Albert Szent-Gyorgi
2013 Jul 18
2
Any way to over-ride the "-q" option to debug a possible race condition?
...nches a series of mpi tasks via a ssh connection.
N.B., if there are some known issues with that ssh version that may be
relevant, information would be useful as I could push on the
sys_admin.
--
Professor Laurence Marks
Department of Materials Science and Engineering
Northwestern University
www.numis.northwestern.edu 1-847-491-3996
"Research is to see what everybody else has seen, and to think what
nobody else has thought"
Albert Szent-Gyorgi
2005 May 25
0
Error with user defined split function in rpart (PR#7895)
Full_Name: Bill Wheeler
Version: 2.0.1
OS: Windows 2000
Submission from: (NULL) (67.130.36.229)
The program to reproduce the error is below. I am calling rpart with a
user-defined split function for a binary response variable and one continuous
independent variable. The split function works for some datasets but not
others.
The error is:
Error in "$<-.data.frame"(`*tmp*`,
2008 May 28
1
calling C function from R
Hi,
I am reading the source code of rpart. I have problems understand the following code and would appreciate for any helps. In rpart.s, there is a line:
rpfit <- .C(C_s_to_rp,
n = as.integer(nobs),
nvarx
2002 Aug 28
0
user defined function in rpart
Hi,
I am trying to use the rpart library with my own set of functions on a
survival object. I get an immeadiate segmentation fault when i try
calling rpart with my list of functions. I get the same problem with the
logrank example from Therneau,s S-rpart library though their anova
example works. Should I report this as a bug, as even if my functions
are structured improperly, that should lead to
2005 Aug 26
1
Help in Compliling user -defined functions in Rpart
I have been trying to write my own user defined function in Rpart.I
imitated the anova splitting rule which is given as an example.In the
work I am doing ,I am calculating the concentration index(ci) ,which
is in between -1 and +1.So my deviance is given by
abs(ci)*(1-abs(ci)).Now when I run rpart incorporating this user
defined function i get the following error message:
Error in
2013 Jul 20
7
Failure to Launch (was override -q option)
...liable
indicating that the issue really is ssh related, but since the problem only
occurs for 0.1-0.2 % of the connections I need to let 10 jobs run for a day
or so more before I can be certain.
--
Professor Laurence Marks
Department of Materials Science and Engineering
Northwestern University
www.numis.northwestern.edu 1-847-491-3996
"Research is to see what everybody else has seen, and to think what
nobody else has thought"
Albert Szent-Gyorgi