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Estimad en s, Abajo están dos ofertas de trabajos para Novartis España en Barcelona. Los candidatos deben enviar su candidatura a jimena.aldasoro-ext en novartis.com. Saludos, Marco ######################################################################### - Puesto: Data Manager Estadístico Marketing - Número de plazas: 1 - Tipo de contrato: Temporal -...

Dear All, I have been asked to forward to you this job advert. The advert is in Spanish as the role require knowledge of Spanish. If interested please contact Jimena at jimena.aldasoro-ext at novartis.com. Regards, Marco ######################################################################### - Puesto: Data Manager Estad?stico Marketing - N?mero de plazas: 1 - Tipo de contrato: Temporal - Inicio: Agosto 2008 - Duraci?n m?nima esperada de: 6 meses - Jornada: 8 horas - Perfil solicita...

Dear all - My group at Novartis is looking for statisticians, bioinformaticians, or R programmers to support molecular diagnostics, with open positions in Cambridge MA, USA (priority) and in Basel Switzerland (possible). We do a range of data analyses across product lifecycle (research, tech dev, clin dev, market...

Multiple internship opportunities at Novartis Integrated Quantitative Sciences are available for outstanding graduate students. Positions include: A. Decision Support Tool: Under guidance, build a live real-world decision support tool for users. Requirements: Facility with R/Shiny and Javascript; statistical or operational modeling. Relatio...

Is there a function in R, which would return index of maximum value in a vector ? e.g. > v <- round(10*rnorm(8)) > v [1] 6 -3 -6 15 7 9 0 -19 > max(v) [1] 15 ??? index.max(v) ??? 4

In e1071 package/svm default epsilon value is set to 0.1 and not 0.5 as documentation says. R

...management strategy that incorporates someone's favorite IT risk mitigation approach. With respect to Bert's points about 21CFR Part 11, please read the documents on the R WWW with respect to such things for a pretty informed opinion as to what is really happening. I may not speak for Novartis, but it is possible that we'll be using a non-commercial version of R at some point in the future and we've been looking into the risk management strategies. Some people are annoyed at the packages we will not let people use, but code review suggests that we really don't want peop...

Greetings - I'm finally finished review, here's what I heard: ============ from Tobias Verbeke: anthony.rossini@novartis.com wrote: > Greetings! > > After a quick look at current programming tools, especially with regards > to unit-testing frameworks, I've started looking at both "butler" and > "RUnit". I would be grateful to receieve real world development > experience...

I have a data frame (df) with colums x, y and z. e.g. df <- data.frame(x = sample(4), y = sample(4), z = sample(4)) I can extract column z by: df$z or df[3] I can also extract columns x,y by: df[1:2] or by df[-3]. Is it possible to extract x,y columns in a "symbolic" fashion i.e. by equivalent of df[-z] (which is illegal) ??? Or alternativeley, is there an equivalent of

I don't know the details of pls (in the pls.pcr package, I assume), but if you use validation="CV", that says you want to use CV to select the best number of components. Then why would you specify ncomp as well? Andy > From: ryszard.czerminski at pharma.novartis.com > > When I try to use ncomp parameter in pls procedure I get > following error: > > > library(pls.pcr) > > m <- pls(x, y, validation = "CV", niter = 68, ncomp = 16) > Error in inherits(x, "data.frame") : subscript out of bounds > > Wi...

And on that note, here is a function that I use to get around it: -----Original Message----- From: r-help-bounces at stat.math.ethz.ch [mailto:r-help-bounces at stat.math.ethz.ch] On Behalf Of Jeffrey Horner Sent: Friday, November 03, 2006 10:01 AM To: ryszard.czerminski at novartis.com Cc: r-help at stat.math.ethz.ch Subject: Re: [R] R CMD BATCH: unable to start device PNG ryszard.czerminski at novartis.com wrote: > Dear r-helpers: > > Any ideas how to avoid problem described below? > I am having the same problem when I run R remotly (not from cgi script); >...

How can I remove columns with NaN entries ? Here is my simple example: > data <- read.csv("test.csv") > xdata <- data[3:length(data)] > xs <- lapply(xdata, function(x){(x - mean(x))/sqrt(var(x))}) > x <- data.frame(xs) > x C D E F 1 -0.7071068 NaN -0.7071068 -0.7071068 2 0.7071068 NaN 0.7071068 0.7071068

How can I select random subsets (rows!) from a data set ? If I generate simple data set > a <- data.frame(x=1:2, y = NaN, z = 2:1) > a x y z 1 1 NaN 2 2 2 NaN 1 I can select random subsets (colums) very easily using sample function: > sample(a, 2) z y 1 2 NaN 2 1 NaN I expected that using transpose of a would do the same for rows, but I am getting rather unexpected

Hello, What version of LIBEAY32.DLL has Ordinal 968 defined? I have searched many versions of this dll and see that this ordinal has been deprecated. Where can I find the latest version of this dll that has this ordinal defined? Thanks, Michael Allen Novartis Pharmaceuticals Corporation Senior Technologist Novartis Pharmaceuticals Corporation One Health Plaza East Hanover, NJ 07936-1080 USA Phone: +1 862 7783177 Email : michael.allen at novartis.com

I am trying to produce rather mundane output of the form e.g. pi, e = 3.14 2.718 The closest result I achieved so far with print() is: > print (c(pi, exp(1)), digits = 3) [1] 3.14 2.72 > print(c("pi, e =", pi, exp(1)), digits = 3) [1] "pi, e =" "3.14159265358979" "2.71828182845905" I understand that c() promotes floats to strings and

Consider this: > y <- matrix(1:8, ncol=2) > is.matrix(y[-c(1,2),]) [1] TRUE > is.matrix(y[-c(1,2,3),]) [1] FALSE > is.matrix(y[-c(1,2,3,4),]) [1] TRUE It seems like an inconsistent behaviour: - with 2 or more rows we have a matrix - with 1 row we do not have a matrix and - with 0 rows we have a matrix again I just stumbled on this behaviour, because I had a problem with my

The following is not what I expected in sorting characters (single letters and the same letters with preceding spaces). Can someone enlighten me as to why the following might be a correct result for sorting? ; x <- c(LETTERS[1:3], paste(" ", LETTERS[1:3], sep="")) ; x [1] "A" "B" "C" " A" " B" " C" ; sort(x)

Apparently row names are dropped when I extract single column from a data frame. Why this behaviour ? > y <- as.matrix(df[,1:2]); length(row.names(y)) [1] 324 > y <- as.matrix(df[,1:1]); length(row.names(y)) [1] 0 Best regards, Ryszard

When printing a table it is broken at some point (depending how long are the associated names) >>> see example below. Is there a way to control number of columns being printed for a given chunk of the table? Best regards, Ryszard > z5 AAAAAAA BBBBBBB CCCCCCC DDDDDDD EEEEEEE FFFFFFF GGGGGGG HHHHHHH IIIIIII AAAAAAA 1.00 -0.69 -0.54 -0.88 NA NA NA

Full_Name: Ryszard Czerminski Version: 1.8.1 OS: GNU/Linux Submission from: (NULL) (205.181.102.120) prcomp(..., scale = TRUE) does not work correctly: $ uname -a Linux 2.4.20-28.9bigmem #1 SMP Thu Dec 18 13:27:33 EST 2003 i686 i686 i386 GNU/Linux $ gcc --version gcc (GCC) 3.2.2 20030222 (Red Hat Linux 3.2.2-5) > a <- matrix(rnorm(6), nrow = 3) > sum((scale(a %*% svd(cov(a))$u, scale