Displaying 20 results from an estimated 1029 matches for "norm".
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2009 Apr 14
1
mean fold change issues and p values
...t I am not sure.
Version 1
##t test
len_sig_test = length(sig_test)
if(len_sig_test%%2 > 0)
message("Number of groups for t-test is not paired.")
if(max(sig_test) > group)
message("Group number for t-test is out of range.")
data.norm.test = data.norm.zo #normalized data
nrow <- nrow(data.norm.test)
ncol <- ncol(data.norm.test)
p.ttest = rep(NA, nrow) #parametric test -- t test
p.wilcox = rep(NA, nrow) #non-parametric test --...
2011 Jan 14
0
Fwd: helps in data analysis
...is no insect count at all. So, I
tried fitting 'zero inflated Poisson model' to the data using cozigam
function as follows:
> chf.res1 <- cozigam(chafer ~ s(longitude, latitude) + s(PC1) + s(PC2) +
s(PC3) + s(PC4) + (year) + paddock2, family=poisson, data=df.chf09)
iteration = 2 norm = 1.023552
iteration = 3 norm = 0.4258558
iteration = 4 norm = 0.003208923
iteration = 5 norm = 0.006238185
iteration = 6 norm = 0.006029638
iteration = 7 norm = 0.005037579
iteration = 8 norm = 0.004390153
iteration = 9 norm = 0.003970208
iteration = 10 norm = 0.003670730
it...
2012 Feb 27
0
Conflict from saved implicit generics in methods package for rcond, norm, backsolve
This issue ties loosely into other recent S4 topics on this board.
The methods package defines a number of implicit generics for linear
algebra related functions (rcond, norm, backsolve) that, when used,
interfere with base package operations. Here is the cut-and-paste
version of the code the illustrates the problem:
# rcond
x1 <- cbind(1, 1:10)
rcond(x1)
setGeneric("rcond")
rcond(x1)
# norm
example(norm)
setGeneric("norm")
example(norm)
# ba...
2005 Feb 24
1
problem (bug?) with prelim.norm (package norm)
dear list members,
there seems to be a problem with the prelim.norm function (package norm)
as number of items in the dataset increases.
the output of prelim.norm() is a list with different summary statistics,
one of them is the missingness indicator matrix "r". it lists all
patterns of missing data and a count of how often each pattern occured
in the da...
2005 Nov 09
2
error in NORM lib
Dear alltogether,
I experience very strange behavior of imputation of NA's with the NORM
library. I use R 2.2.0, win32.
The code is below and the same dataset was also tried with MICE and
aregImpute() from HMISC _without_ any problem.
The problem is as follows:
(1) using the whole dataset results in very strange imputations - values
far beyond the maximum of the respective column,...
2009 Sep 24
1
col headers in read.table()
Hi,
I was trying to read in a file test.txt, which has the following data:
norm norm norm class class class
a 1 2 3 4 5 6
b 3 4 5 6 7 8
c 5 6 7 8 9 10
in my R code, I do the following:
---------------------------------------------------
> mat <- read.table('test.txt',header=T,row.names=1,sep='\t')
> mat
norm norm.1 norm.2 class class.1 class.2
a...
2003 Jan 21
1
problems when compiling package 'norm'
Dear All,
Trying to install package 'norm' under linux-mandrake8.2 I've got the
following messages:
R CMD INSTALL norm_1.0-9.tar.gz
* Installing *source* package 'norm' ...
** libs
g77 -mieee-fp -O3 -fomit-frame-pointer -pipe -mcpu=pentiumpro
-march=i586 -fno-fast-math -fno-strength-reduce -O3
-fomit-frame-pointer -pipe...
2014 Jul 11
2
outliers (Marta valdes lopez)
...brary(outliers)
filename<-"timediff.csv"
time<-read.csv(filename, sep=";",header=TRUE,dec=".") # Esto es lo que has
de cambiar
chisq.out.test(time$TimeDiff)
# Ayuda adicional
#---------------------------------------------------------------------
# Si no supones normalidad
#---------------------------------------------------------------------
time.without.outs <- data.frame(row.names= 1:dim(time)[1], dif = time )
x <- boxplot(time.without.outs$TimeDiff,range= 1.5) # Quita los outliers
que se van más de 1.5 rangos itercuartilicios. Puedes poner otro crit...
2004 Nov 24
1
reshaping of data for barplot2
Dear All,
I have the following data coming out from
s <- with(final,
summarize(norm, llist(gtt,fdiab),
function(norm) {
n <- sum(!is.na(norm))
s <- sum(norm, na.rm=T)
binconf(s, n)
}, type='matrix')
)
ie
gtt fdiab norm.norm norm.norm2 norm.norm3
18...
2011 Aug 25
1
Specifying argument values in a function
Hello all,
I am trying write a fairly simple function that provide a quick way to
calculate several distributions for a data set. I am trying to provide
a function that has a argument that specifies which distribution is
outputted (here "norm" or "cumu"). I also have a melt argument but
that seems to be working fine. I have been able to get my function
working well for just one distribution but when I add another and try
to add a "dist.type" argument (with potential values "cumu" and
"norm"),...
2004 Aug 26
1
EM norm package (NA/NaN/Inf in foreign function call (arg 2))
Greetings!
I am bootstrapping and I am using EM in the norm package to fill in missing
data for a financial time series with each step of the loop. For the most
part EM works fine for me, but the following error message is guaranteed
before I hit the 200th scenario:
Iterations of EM:
1...2...3........348...349...Error: NA/NaN/Inf in foreign function call
(...
2009 Jul 17
3
Package norm has been removed. What to use for Maximum Likelihood Missing Data Imputation?
Hello,
I apologize if an answer to my questions is available, or if I
submitted this question incorrectly. I have read the mailing lists, as
well as the R Project and CRAN homepages. However, I may have missed
something.
I noticed the package 'norm' has been removed. Its page
http://cran.r-project.org/web/packages/norm/index.html now reads:
"Package ?norm? was removed from the CRAN repository.
Formerly available versions can be obtained from the archive."
My questions are:
1. Why was norm removed? I used the package and foun...
2009 Oct 26
2
help with linear model
...n't found anything relevant to
my problem. I guess it is something simple...I just cannot see it.
I have the following data frame, named "data", which is a subset of a
microarray experiment. The columns are the samples and the rows are the
probes. I binded the first line, called "norm", which represents the
estimated output. I want to create a linear model which shows the
relationship between the gene expressions (rows) and the output (norm).
*data*
GSM276723.CEL GSM276724.CEL GSM276725.CEL GSM276726.CEL
norm 0.897000 0.590000 0.683000...
2007 Sep 21
1
A reproducibility puzzle with NORM
Hi Folks,
I'm using the 'norm' package (based on Shafer's NORM)
on some data. In outline, (X,Y) are bivariate normal,
var(X)=0.29, var(Y)=24.4, cov(X,Y)=-0.277,
there are some 900 cases, and some 170 values of Y
have been set "missing" (NA).
The puzzle is that, repeating the multiple imputation
starting from...
2007 Apr 25
1
prelim.norm() function not working
...little
green book on missing data (Sage 2002). The dataset for which I am
having problems, "usnews", can be found at:
http://www.ats.ucla.edu/stat/books/md/default.htm. I am working on a
Windows machine with R 2.5 installed, all packages up-to-date.
The problem has to do with the prelim.norm() function of the package
"norm". Specifically, I need to use this pre-processing function to
later use the EM algorithm and DA procedures in the norm package. I
am getting an error with the following code.
----------------------
> pre <- prelim.norm(usnews)
Error in as.double.d...
2006 Feb 01
3
norm package prelim.norm
Hey eveyone! I hope someone can help wiht this question. I have a matirux of all zeros and ones and I would like to indentify all unique patterns in the rows andthe number of times the pattern occurs. I changed all zeros to NA tried to use prelim.norm to identify all patterns of missing data in the rows. I got the message
Warning message:
NAs introduced by coercion
Any ideas of how to get this to work? Or are there any way to indentify all the unique patterns in a huge matrix? ( 10000 x 71)
Thanks for any suggestions!!
E...
2014 Jul 14
2
outliers (Marta valdes lopez)
...;-read.csv(filename, sep=";",header=TRUE,dec=".") # Esto es lo que
>> has de cambiar
>> chisq.out.test(time$TimeDiff)
>>
>>
>> # Ayuda adicional
>> #---------------------------------------------------------------------
>> # Si no supones normalidad
>> #---------------------------------------------------------------------
>> time.without.outs <- data.frame(row.names= 1:dim(time)[1], dif = time )
>>
>>
>> x <- boxplot(time.without.outs$TimeDiff,range= 1.5) # Quita los outliers
>> que se van más de...
2024 Jun 26
2
Ayuda para hacer una lista
...ny conditions? ")
print(paste("You have ", y , "conditions")
###########################
Esta parte para renombrar las intensidades usando x e y
###### 2
for (i in 1:y){
varnames[i] <- c(rep(paste0("gp_", i), y))
}
varnames
Group <- factor(varnames)
nu.Norm <- select_if(Norm, is.numeric)
#this part will change the columns names, do we want that?
names(nu.Norm) <- paste0(rep(varnames, each=x), "_", 1:x)
nu.Norm
##############################
Crear listas para el boxplot
###### 3
*listgp <- list(Norm[,6:(as.numeric(x)+5)],
Norm[,(a...
2011 Dec 05
1
finding interpolated values along an empirical parametric curve
Given the following data, I am plotting log.det ~ norm.beta, where the
points depend on a parameter, lambda
(but there is no functional form).
I want to find the (x,y) positions along this curve corresponding to two
special values of lambda
lambda.HKB <- 0.004275357
lambda.LW <- 0.03229531
and draw reference lines at ~ -45 degrees (or normal...
2004 Oct 10
3
some help interpreting ANOVA results, please?
On Sun, 10 Oct 2004, RenE J.V. Bertin wrote:
> Could I ask some hints/help in interpreting the following ANOVA results,
> please? This concerns an experiment where I study the incidence and
> severity of motion sickness. I have Sickness.norm, a subjective
> discomfort/sickness estimate, normalised to 0..1, the session time T
> (normalised to 0..1 and binned in 0.2 wide bins) and a qualitive
> indicator if a given Subject was sick or not. For instance, to see if
> there is an effect of time, I do
>
>
> > summar...