Displaying 4 results from an estimated 4 matches for "nminim".
Did you mean:
minim
2008 Aug 05
1
optimize simultaneously two binomials inequalities using nlm( ) or optim( )
...2,beta) points. Some adjacency compromise is commonly required,
achieved by searching a more precise OC curve with respect to one of the
points.
I?m using Mathematica 6 but it is a Trial, so I would like use R intead (or
better, I need it)!
To exemplify, In Mathematica I call the function using NMinimize passing
the restriction and parameters:
/* function name "findOpt" and parameters... */
restriction = (1 - alpha) <= CDF[BinomialDistribution[sample_n, p1], c]
&& betha >= CDF[BinomialDistribution[sample_n, p2], c]
&& 0 < alpha < alphamax &&am...
2008 Jul 29
0
optimize simultaneously two binomials inequalities using nlm
...2,beta) points. Some adjacency compromise is commonly required,
achieved by searching a more precise OC curve with respect to one of the
points.
I?m using Mathematica 6 but it is a Trial, so I would like use R intead (or
better, I need it)!
To exemplify, In Mathematica I call the function using NMinimize passing
the restriction and parameters:
/* function name "findOpt" and parameters... */
restriction = (1 - alpha) <= CDF[BinomialDistribution[sample_n, p1], c]
&& betha >= CDF[BinomialDistribution[sample_n, p2], c]
&& 0 < alpha < alphamax &&am...
2008 Jul 21
0
optimize function help!!
...mple_n, p2], c] &&
0 < alpha < alphamax && 0 < betha < bethamax &&
1 < sample_n <= lot_Size &&
0 <= c < amostra &&
p1 < p2 < p2max ;
fcost = sample_n/lot_Size;
result = NMinimize[{fcost, restriction}, {sample_n, c, alpha, betha,
p2max},
Method -> "NelderMead", AccuracyGoal -> 10];
example:
findOpt[0.005, 1000, 0.05, 0.05, 0.04] ==> and I got the return of
values of; "n", "c",
alpha and betha, computed.
{0.51...
2006 Nov 26
2
Quadratic Optimization
Hi,
I need to solve an optimization problem in R having linear objective function and quadratic constraints(number of variables is around 80). What are the possible choices to do this in R.
optim() function only allows box constrained problems. Is it possible in nlm()? Or please tell me if there is any other routine.
Thanks
Amit