search for: nielsrichardhansen

...to bring the rows of a data frame into the same order as the levels of a factor. Thanks, Niels -- Niels Richard Hansen Web: www.math.ku.dk/~richard Associate Professor Email: Niels.R.Hansen at math.ku.dk Department of Mathematical Sciences nielsrichardhansen at gmail.com University of Copenhagen Skype: nielsrichardhansen.dk Universitetsparken 5 Phone: +45 353 20783 (office) 2100 Copenhagen ? +45 2859 0765 (mobile) Denmark

...eq_len' always return an integer vector. as there are no seq_length function? Best, Niels -- Niels Richard Hansen Web: www.math.ku.dk/~richard Associate Professor Email: Niels.R.Hansen at math.ku.dk Department of Mathematical Sciences nielsrichardhansen at gmail.com University of Copenhagen Skype: nielsrichardhansen.dk Universitetsparken 5 Phone: +45 353 20783 (office) 2100 Copenhagen ? +45 2859 0765 (mobile) Denmark

...] Matrix_0.999375-45 lattice_0.19-13 loaded via a namespace (and not attached): [1] grid_2.12.0 -- Niels Richard Hansen Web: www.math.ku.dk/~richard Associate Professor Email: Niels.R.Hansen at math.ku.dk Department of Mathematical Sciences nielsrichardhansen at gmail.com University of Copenhagen Skype: nielsrichardhansen.dk Universitetsparken 5 Phone: +1 510 502 8161 2100 Copenhagen ? Denmark

...track = track)] myFunction(10) stopInspection(myFunction) Is this already around? Best, Niels -- Niels Richard Hansen Web: www.math.ku.dk/~richard Associate Professor Email: Niels.R.Hansen at math.ku.dk Department of Mathematical Sciences nielsrichardhansen at gmail.com University of Copenhagen Skype: nielsrichardhansen.dk Universitetsparken 5 Phone: +1 510 502 8161 2100 Copenhagen ? Denmark

Dear R-help list, Sorry to trouble everyone. This seems like it could be achieved with a single command (? variant of apply), but I am not quite seeing it. I am trying to multiply one vector (a1 below) by corresponding values in a3 (as determined by matching element in a vector a2). The example below might be clearer. a1 <- c(4,3,4,6,8,9,2,3,4,6,7,4) a2 <-

...8 attached base packages: [1] stats graphics grDevices utils datasets methods base -- Niels Richard Hansen Web: www.math.ku.dk/~richard Associate Professor Email: Niels.R.Hansen at math.ku.dk Department of Mathematical Sciences nielsrichardhansen at gmail.com University of Copenhagen Skype: nielsrichardhansen.dk Universitetsparken 5 Phone: +45 353 20783 (office) 2100 Copenhagen ? +45 2859 0765 (mobile) Denmark

...foreach_1.3.0 codetools_0.2-6 iterators_1.0.3 (or other attached packages: [1] spatial_7.3-2) -- Niels Richard Hansen Web: www.math.ku.dk/~richard Associate Professor Email: Niels.R.Hansen at math.ku.dk Department of Mathematical Sciences nielsrichardhansen at gmail.com University of Copenhagen Skype: nielsrichardhansen.dk Universitetsparken 5 Phone: +1 510 502 8161 2100 Copenhagen ? Denmark

..., would there be any problems with having such a copyright notice in the package? Thanks, Niels -- Niels Richard Hansen Web: www.math.ku.dk/~richard Associate Professor Email: Niels.R.Hansen at math.ku.dk Department of Mathematical Sciences nielsrichardhansen at gmail.com University of Copenhagen Skype: nielsrichardhansen.dk Universitetsparken 5 Phone: +1 510 502 8161 2100 Copenhagen ? Denmark

Hello all, I came across a behavior of R with environments that I'm not sure what is causing it. It involves changing variables that are found through using model.frame on a formula inside a function. I wonder if it's a "bug" or a "feature". And in either case, how it might be managed. Here is a simple example: # let's say we have an x and y variables: temp_x

Dear all, This problem came up initially while debugging a function, but it seems to be a more general problem of R. I hope I'm wrong, but I can't find another explanation. Let me illustrate with the raster package. For an object "RasterLayer" (which inherits from Raster), there is a method xyValues defined with the signature

This is some interesting: > -8^(1/3) [1] -2 > x=(-8:8) > y=x^(1/3) > y [1] NaN NaN NaN NaN NaN NaN NaN NaN 0.000000 1.000000 [11] 1.259921 1.442250 1.587401 1.709976 1.817121 1.912931 2.000000 So, can anybody explain this?! (Why is x[1]^(1/3)=y[1]=NaN, but -8^(1/3)=-2?) Thx!!! [[alternative HTML version deleted]]

Hi all I was playing with termplot(), and came across what appears to be an inconsistency. It would appreciate if someone could enlighten me: > # First, generate some data: > y <- rnorm(100) > x <- runif(length(y),1,2) > # Now find the log of x: > logx <- log(x) > > # Now fit two models that are exactly the same, but specified differently: > m1 <-

Hi guys, My concern is to create an automated process from the beginning to the end. I want to copy all my code together in one piece and paste it to R console and sit back and relax :) except one moment in which the program should ask me to enter a number.. and only then (only after getting a valid number from me) it should continue to read and process the rest of the code. I tried lots of