Displaying 8 results from an estimated 8 matches for "mu4".
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2010 Jun 13
1
using latticeExtra plotting confidence intervals
...0,2)
sample2<-rnorm(100,50,3)
sample3<-rnorm(100,20,2)
sample4<-rnorm(100,40,1)
mu1<-mean(sample1)
ci.upper1<-mu1+2*2
ci.lower1<-mu1-2*2
mu2<-mean(sample2)
ci.upper2<-mu2+2*3
ci.lower2<-mu2-2*3
mu3<-mean(sample3)
ci.upper3<-mu3+2*2
ci.lower3<-mu3-2*2
mu4<-mean(sample4)
ci.upper4<-mu4+2*1
ci.lower4<-mu4-2*1
categories<-c("A","B")
mu<-cbind(mu1,mu2,mu3,mu4)
ci.upper<-cbind(ci.upper1,ci.upper2,ci.upper3,ci.upper4)
ci.lower<-cbind(ci.lower1,ci.lower2,ci.lower3,ci.lower4)
segplot(mu~ci.upper+ci.lower|ca...
2009 Oct 31
1
Help me improving my code
...lt;- pennw$inuidur1
> fw <- factor(wage)
> Ik <- model.matrix(~fw-1)
> I1 <- Ik[,1]
> I2 <- Ik[,2]
> I3 <- Ik[,3]
> I4 <- Ik[,4]
> I5 <- Ik[,5]
> yelmon <- function(theta,x){
+ mu1 <- theta[1]
+ mu2 <- theta[2]
+ mu3 <- theta[3]
+ mu4 <- theta[4]
+ mu5 <- theta[5]
+ beta <- theta[6]
+ logL <-
sum((Ik*log((exp(mu2-(x*beta))/(1+exp(mu2-(x*beta))))-(exp(mu1-(x*beta))/(1+exp(mu1-(x*beta))))))+(Ik*log((exp(mu3-(x*beta))/(1+exp(mu3-(x*beta))))-(exp(mu2-(x*beta))/(1+exp(mu2-(x*beta))))))+(Ik*log((exp(mu4-(x*beta))/(1+exp...
2009 Mar 30
0
Problem in S4 object displaying from within a Java application using JRI
...ary(methods)", true);
re.eval("mu1 <- c(59.73, 27.94,89.67, 62.44)", true);
re.eval("mu2<- c(57.81, 72.67, 82.97, 62.44)", true);
re.eval("mu3<- c(45.66, 49.19, 53, 64.39)", true);
re.eval("mu4<- c(70.39, 80.41, 89.67, 80)", true);
re.eval("delta.C <- 1", true);
re.eval("Acp <- rbind (c(mu4,mu2,delta.C), c(mu2,mu3,delta.C),
c(mu3,mu1,delta.C))", true);
re.eval("wt <- c(0.3,0.3,0.25,0.15)/1", true);...
2010 Mar 20
2
EM algorithm in R
Please help me in writing the R code for this problem. I've been solving this
for 4 days. It was hard for me to solve it. It's a simulation problem in R.
The problem is
My true model is a normal mixture which is given as
0.5 N(-0.8,1) + 0.5 N(0.8,1). This model has two components.
I will get a random sample of size 100 from this model. I will do this 300
times.
That means, I will have
2003 Aug 06
1
Standard error of standard deviation: bootstrap or theoretical results?
...randomly. For these 100 subsamples, I use the following 3
methods to calculate the standard error of standard deviation:
1. From book "Handbook of applicable mathematics", Walter Ledermann (chief
editor) Volumn VI: Statistics, Part A, Lloyd, John Wiley & Sons.
Page 30-32:
var(S) = (mu4 - mu2^2)/(4 * mu2 * n)
mu4 = E(X - mu)^4, mu2 = E(X - mu)^2, S^2 = sum(X - mu)^2/n
The results are about: 0.00090
2. From http://davidmlane.com/hyperstat/A19196.html
The results are about 0.00066
3. From http://mathworld.wolfram.com/StandardDeviationDistribution.html
The results are about 0....
2008 Jul 28
1
Mixed model question.
...comprehension)
on 6 separate occasions. Initially (square zero) I want to treat the
test time as a factor (with 6 levels). The students are of course
``random effects''. Later I want to look at reduced models, with the
means at the 6 times following patterns:
(mu1, mu2, mu2, mu3, mu3, mu4)
or
(mu1, mu1+theta, mu1+theta, mu1+2*theta, mu1+2*theta, mu1+3*theta)
the idea begin that the tests are given ``in pairs'' at the beginning
and
end of the school year. Progress is expected over the school year, no
progress over the two intervening summers. The summers fall between...
2007 Oct 29
1
VGAM and vglm
...Error t value
##(Intercept):1 -1.1527 0.33113 -3.4810
##(Intercept):2 -1.2657 0.34139 -3.7073
##(Intercept):3 -0.6633 0.29854 -2.2218
##(Intercept):4 -1.3863 0.35355 -3.9210
##
##Number of linear predictors: 4
##Names of linear predictors: logit(mu1),
## logit(mu2), logit(mu3), logit(mu4)
but that seems to be going to greater lengths than
one should need to!
Any comments and suggestions will be welcome!
Best wishes to all,
Ted.
--------------------------------------------------------------------
E-Mail: (Ted Harding) <Ted.Harding at manchester.ac.uk>
Fax-to-email: +44 (0)...
2008 Jun 30
4
Rebuild of kernel 2.6.9-67.0.20.EL failure
Hello list.
I'm trying to rebuild the 2.6.9.67.0.20.EL kernel, but it fails even without
modifications.
How did I try it?
Created a (non-root) build environment (not a mock )
Installed the kernel.scr.rpm and did a
rpmbuild -ba --target=`uname -m` kernel-2.6.spec 2> prep-err.log | tee
prep-out.log
The build failed at the end:
Processing files: kernel-xenU-devel-2.6.9-67.0.20.EL
Checking