Displaying 11 results from an estimated 11 matches for "mentus".
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2003 Jan 30
2
Weird options(digits=n) behaviour
I noticed some very weird behaviour of the function: options(digits=n),
where n is the number of digits you would expect to get in R calculations.
Let's take a example:
> options(digits=4)
> getdata(caso.pool.k3.r3.e2)
[1] 6.053 2.641 -3.639 14.259 6.082
Which works fine... now, trying again, with different data:
> options(digits=4)
> getdata(controle.pool.k3.r3.e2)
2003 Mar 29
1
Goodness of fit tests
...ve read a lot of documentation, also tried googling for ''goodness of fit R'' but it was helpless, most of it is only about ''regression analysis''. Does anyone know if there is a simpler way to do this?
Thank you,
<Fernando Henrique Ferraz Pereira da Rosa - mentus at gmx.de>
2003 Mar 10
3
VIM Syntax Highlighting
Has anyone got vim to have syntax highlighting with R function codes? I
know there's something similar that works with emacs (ESS or something like
that), but I was wondering if anyone knew an equivalent that worked with vim.
Thank you,
--
[]'s
mentus at gmx.de
Bitte l?cheln! Fotogalerie online mit GMX ohne eigene Homepage!
2003 May 09
2
Data-mining using R
Is it possible to use R as a data-mining tool? Here's the problem I've
got. I have a couple of data sets consisting of results from a cDNA
microarray experiment - the details about the biology don't really matter here, the
same theory applies for any other data-mining task (that's why I thought it'd
be more appropriate to post this on r-user). Each of these datasets consists
2003 Jun 17
2
Paste and namespace
Hi, my doubt is very simple. I'm sure I've seen someone using something
like this before, but unfortunatelly my searches in the archives were useless.
Well, I have some objects called after a name that has a number attached to
it,
varying. Let's say I have:
> ls
poly1 poly2 poly3 poly4 poly5 poly6 ...
I would like to access these objects using a for(), in which I could do
2003 Jun 19
2
Subseting by more than one factor...
Is it possible in R to subset a dataframe by more than one factor, all at
once?
For instance, I have the dataframe:
>data
p1 p2 p3 p4 p5 p6 p7 p8 p9 p10 pred
1 0 1 0 0 0 0 0 0 0 0 0.5862069
4 0 0 0 0 0 0 0 0 0 1 0.5862069
5 0 0 0 0 0 0 1 0 0 0 0.5862069
6 0 0 0 0 0 0 0 1 0 0 0.5862069
7 0 0 1 0 0 0 0 0 0
2009 Jun 01
1
installing sn package
...omain Francois <romain.francois@dbmail.com>
Subject: Re: [R] no internal function "int.unzip" in R 2.9.0 for
Windows
To: "Carson, John" <John.Carson@shawgrp.com>
Cc: r-help@r-project.org, EricLecoutre@gmail.com, Fernando Henrique
Ferraz Pereira da Rosa <mentus@gmail.com>
Message-ID: <4A1D85A6.5090808@dbmail.com>
Content-Type: text/plain; charset=ISO-8859-1; format=flowed
Hi,
I'll try to fix this soon. Could you log a bug request here:
http://r-forge.r-project.org/tracker/?atid=1643&group_id=405&func=browse
Regards,
Romain
Carson...
2003 Jun 01
1
Simulating a variable following an arbitrary distribution
Hi, I'd like to know if there's anything in R that could help me do
that. Let's suppose I have a density function of a random variable, for example
f(x) = (x^3)/4 0 < x < 2 and I would like to simulate it. For the common
distributions (exponencial, gamma, cauchy) there are the r-functions (rgamma,
rexp, runif, rcauchy, and so on).. But when the variable I want to simulate is
not
2004 Aug 20
0
Proposed (minor) change to plot.TukeyHSD
Attached follows a patch to a minor change in the plot method of
the TukeyHSD class (package stats). Basically it defines main= and xlab=
as formal arguments of the plot function, with reasonable default
values, passing them to title(), instead of using hard-coded only values
for main= and xlab=. This way it's possible to change the title and xlab
of the plots created using plot.TukeyHSD().
2004 Sep 07
1
Contrast matrices for nested factors
Hi, I'd like to know if it's possible to specify different
contrast matrices in lm() for a factor that is nested within another one. This
is useful when we have a model where the nested factor has a different
number of levels, depending on the main factor.
Let me illustrate with an example to make it clearer. Consider
the following data set:
set.seed(1)
y <-
2003 Jan 25
7
Plotting coloured histograms...
Hi, I am having some trouble trying to plot a histogram in more than one
colour. What I want to do is, plot two vectors in the same histogram, but
with different colours, for instance:
> x <- rnorm(1000,20,4);
> y <- rnorm(1000,10,2);
Then I'd like to have x and y ploted on the same hist (I can do that
already doing w <- c(x,y) then hist(w)) but the bars