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Is length(unique()) what you are looking for? Andy > From: Christoph Lehmann > > Hi I have a question concerning aggregation > > (simple demo code S. below) > > I have the data.frame > > id meas date > 1 a 0.637513747 1 > 2 a 0.187710063 2 > 3 a 0.247098459 2 > 4 a 0.306447690 3 > 5 b 0.407573577 2 > 6 b

Hi all, I'm writing a function that read data from a binary file. I want to close all opened connections, but it failed: > showConnections() description class mode text isopen can read can write 3 "daten/t5_all.mea" "file" "rb" "binary" "opened" "yes" "no" 4 "daten/t5_all.mea"

Hello all, I want box plots by group to display in order of increasing mean (or median) of each group but can't seem to figure it out and couldn't find anything on R-seek, either. My data looks like this: meas unit sid grade rsprti 1 2.24 1002 99999902 NA 0.8600000 2 3.04 1007 43589520 3 0.9400000 3 4.95 2002 39910470 5 1.5300000 4 2.24 2002 39986280 5

I have a combined date and time. I would like to separate them out into two columns so I can do things such as take the mean by time across all dates. meas<-runif(435) nTime<-seq(1303975800, 1304757000, 1800) nDateT<-as.POSIXct(nTime, origin="1970-01-01") mat1<-cbind(nDateT,meas) means1<- aggregate(mat1$meas, list(nDateT), mean) This doesn't do anything as each day

I'm trying to write a loop for a series of nested functions. and I get an incompatible types error when trying to run it. It's supposed to be a simulation (1000 iterations) with a random value for "rand" being chosen each time. After each rand value is chosen, the rest of the functions are evaluated with this given rand value and their "Fitness" sum value is saved and

Greetings, fellow R'ers. How can I get this frame in R: ID meas ID.1 meas.1 1 1.1 3 1.2 2 2.1 4 2.2 to look like this (stacking): ID meas 1 1.1 2 2.1 3 1.2 4 2.2 It's not really the reshape function (or is it?) because we can consider the additional columns, viz., ID.1 and meas.1, as independent of ID and meas so it is basically a stacking

I am very confused about this. I want to convert a string to a name so I can use it to extract an element of a data frame using `$'. Here is my (non-working) code: do.graph <- function (meas) { fn <- paste("a", meas, ".dat", sep='') themeas <- read.table(fn, header=F) ameas <- as.name(paste("a", meas, sep=''))

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I have a dataset where I have missing times (11:00 and 16:00). I would like the outputs to include the missing time so that the final time vector looks like "realt" and has the previous time's value. Ex. If meas at time 15:30 is 0.45, then the meas for time 16:00 will also be 0.45. meas are the measurements and times are the times at which they were taken. meas<-runif(18)

Hello everybody. In my case, calculating multiple comparisons (Tukey) after lmer produced the following two errors: > sv.mc <- glht(model.sv,linfct=mcp(comp="Tukey")) Error in x$terms : $ operator not defined for this S4 class Error in factor_contrasts(model) : no 'model.matrix' method for 'model' found! What I have done before: > sv.growth <-

Dear all, I am relatively new to R and have had some difficulty in understanding an error i get when running a code to solve a system of non-linear equations, with four equations and two variables. This is my code: ALPHA <- c(-0.0985168033402, 0.1, 0.15, 0.2, 0.25, 0.3, 0.35, 0.4) BETA <- c(-0.0985168033402, 0.1, 0.15, 0.2, 0.25, 0.3, 0.35, 0.4) GAMMA <- c(0.3940672148378, 0.1, 0.15,

I uploaded improperly about 13 hours ago, and winetricks was nondownloadable since this morning, but it's back now. Thanks to the users who commented on http://code.google.com/p/winetricks/wiki/Installing to alert me to the problem.

Hello, I am trying to ask the user for which column their data is in, and then use this information in a function. So far I have: data <- read.csv(file.choose(), header=TRUE) col <- (winDialogString("Which column contains your data?","")) and I want to be able to reference such as: meas <- data$col and use this meas in the function. However, I can't seem to

For some time now I've had this type of error showing up in my logs: [2004/09/16 11:52:08, 0] smbd/service.c:set_current_service(56) chdir (/export/downloads) failed I've Googled, I've looked at the source, and I still can't understand why this error appears. What's really odd is that everything seems to work fine, in spite of the error. Could someone please explain what

Dear R people Could you please help with following Trying to compare accuracy of tumor size evaluation by different methods. So data looks like id true metod1 method2 ... 1 2 2 2.5 2 1.5 2 2 3 2 2 2 etc. Could you please give a hint how to deal with that. Seems like {merror} does not suite to me because I am trying to compare accuracy of measurements with their true known values not just

Santi, In the second line of your function you have the following: f <- numeric(length(x)) This sets the length of this numeric vector (i.e., "f") to the length of the vector "x". Later, inside the function you assign to values to 4 elements of the vector "f". This assumes that "f" is at least 4 element in length. However, you define

I have used Sweave a lot the latest year, but never really used any long function calls. If I have code which look like this ------------------------------------------------------------- gof <- benthic.flux(ID="Gulf of Finland", meas.conc=conc, bw.conc=bw.conc, time=times,

Hi, I have constructed a dataframe as follows: Oil <- rep(c("Oil1","Oil2","Oil3"),8) Comp <- rep(rep(c("C1","C2"),c(4,4)),3) Mth <- rep(c("M1","M1","M2","M2"),6) Meas <- rep(c(1,2),12) Result <- rnorm(24,mean=100, sd=5) df <- data.frame(Oil, Comp, Mth, Meas, Result) The same compound

Y'all, I need to get the look of a "standard" fixed effect ANOVA table: anova(aov(meas~op*part,data=fs)) Analysis of Variance Table Response: meas Df Sum Sq Mean Sq F value Pr(>F) op 2 2.62 1.308 1.3193 0.2750 part 19 1185.43 62.391 62.9151 <2e-16 *** op:part 38 27.05 0.712 0.7178 0.8614 Residuals 60 59.50 0.992 when I perform a

maybe it's in the data? So here it comes. > sv.growth Grouped Data: length ~ meas | box_id meas spec comp water box_id sprouts leaves length long.sprout 1 1 Sv control moist 1 8.800000 37.80 211.2000 60.6 2 1 Sv xfull moist 2 7.000000 8.00 174.8000 62.8 3 1 Sv control moist 3 9.000000