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I got a distribution function and a empirical distribution function. How do I make to Kolmogorov-Smirnov test in R. Lets call the empirical distribution function >Fn on [0,1] and the distribution function >F on [0,1] ks.test( ) thanks for the help -- View this message in context: http://www.nabble.com/Kolmogorov-Smirnov-test-tp23296096p23296096.html Sent

Hi, I have fittet a gamma model, and is wondering if I can read the shape and the scale direct from the summary Estimate Std. Error t value Pr(>|t|) (Intercept) 1.612e+00 4.735e-02 34.052 <2e-16 *** myvalue 3.564e-02 2.787e-03 12.788 <2e-16 *** ... Is the shape = 1.1612e+00 and the scale = 3.564e-02 ?? is

How can I from the summary function, decide which glm (fit1, fit2 or fit3) fits to data best? I don't know what to look after, so I would please explain the important output. > fit1 <- glm(Y~X, family=gaussian(link="identity")) > fit2 <- glm(Y~X, family=gaussian(link="log")) > fit3 <- glm(Y~X, family=Gamma(link="log")) > summary(fit1) Call:

Hi, I try to ask here, because I hope someone will help me understand this problem- I have fittet a glm in R with the results > glm1 <- > glm(log(claims)~log(sum)*as.factor(grp),family=gaussian(link="identity")) > summary(glm1) Call: glm(formula = log(claims) ~ log(sum) * as.factor(grp), family = gaussian(link = "identity")) Deviance Residuals: Min 1Q

I have to fit a generalized linear model in R, and I have never done this before, so I'm in very much doubt. I have a dataset (of 4036 observations) claims sum grp 1 3852 34570293 1 2 1194 7776468 1 3 3916 26343305 1 4 1258 5502915 1 5 11594 711453346 1 ... there are 4 groups (grp). The task