Displaying 5 results from an estimated 5 matches for "mathallan".
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matalan
2009 Apr 29
2
Kolmogorov-Smirnov test
I got a distribution function and a empirical distribution function. How do I
make to Kolmogorov-Smirnov test in R.
Lets call the empirical distribution function >Fn on [0,1]
and the distribution function >F on [0,1]
ks.test( )
thanks for the help
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Sent
2009 Apr 27
3
Generalized linear models
I have to fit a generalized linear model in R, and I have never done this
before, so I'm in very much doubt.
I have a dataset (of 4036 observations)
claims sum grp
1 3852 34570293 1
2 1194 7776468 1
3 3916 26343305 1
4 1258 5502915 1
5 11594 711453346 1
...
there are 4 groups (grp).
The task
2009 May 06
2
Summary help
Hi, I have fittet a gamma model, and is wondering if I can read the shape and
the scale direct from the summary
Estimate Std. Error t value Pr(>|t|)
(Intercept) 1.612e+00 4.735e-02 34.052 <2e-16 ***
myvalue 3.564e-02 2.787e-03 12.788 <2e-16 ***
...
Is the shape = 1.1612e+00
and the scale = 3.564e-02 ??
is
2009 Apr 28
1
How to read the summary
How can I from the summary function, decide which glm (fit1, fit2 or fit3)
fits to data best? I don't know what to look after, so I would please
explain the important output.
> fit1 <- glm(Y~X, family=gaussian(link="identity"))
> fit2 <- glm(Y~X, family=gaussian(link="log"))
> fit3 <- glm(Y~X, family=Gamma(link="log"))
> summary(fit1)
Call:
2009 May 08
1
glm fit
Hi, I try to ask here, because I hope someone will help me understand this
problem-
I have fittet a glm in R with the results
> glm1 <-
> glm(log(claims)~log(sum)*as.factor(grp),family=gaussian(link="identity"))
> summary(glm1)
Call:
glm(formula = log(claims) ~ log(sum) * as.factor(grp), family =
gaussian(link = "identity"))
Deviance Residuals:
Min 1Q