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...-axis label to be ( in symbols) g(sigma given alpha) where given is the conditional sign. I've tried ylab=expression(g(sigma|alpha))) but it gave me g(|(sigma,alpha)) where the sigma and alpha are in greek but the conditional sign is misplaced (before the bracket) Any help would be appreciated. Maram. [[alternative HTML version deleted]]

I have no idea to be honest. I have never used the package, I simply did a search for it. Hopefully a more experienced user can help --- On Sun, 7/12/09, maram salem <marammagdysalem at yahoo.com> wrote: > From: maram salem <marammagdysalem at yahoo.com> > Subject: Re: [R] (no subject) > To: "John Kane" <jrkrideau at yahoo.ca> > Received: Sunday, July 12, 2009, 1:01 PM > Dear > John, > Thank u so much 4 ur...

...(mode="numeric",length=1) powercdf<-function(a,y) (y/350)^a   But when I typed: powercdf(10,y) instead of getting : (y/350)^10     (which is what I want) I got : object y not found ??   I want y to remain as it is, a continous variable, not for example seq(0,350). Thank you in advance. Maram [[alternative HTML version deleted]]

...ical vector and find their minimum value. I think c( ) should work.For example if I have only 10 values I could have used c(B1,B2,B3,B4,B5,B6,B7,B8,B9,B10) But how can I do this for 1000 values? I think the question is really trivial, but I tried to work on it and couldn't reach anythg. Thanks. Maram [[alternative HTML version deleted]]

...[1] LC_COLLATE=English_United States.1252 [2] LC_CTYPE=English_United States.1252 [3] LC_MONETARY=English_United States.1252 [4] LC_NUMERIC=C [5] LC_TIME=English_United States.1252 attached base packages: [1] stats graphics grDevices utils datasets methods base On 11/23/2016 5:22 PM, Maram SAlem wrote: > Thanks a lot Bert , will check out your suggestions. > > I've unchecked the buffer output option in GUI but still have the same problem. > > Thanks for your time and concern. > > Maram Salem > > Sent from my iPhone > >> On Nov 23, 2016, at 5:55...

...ing me some problems, so I don't know if there is a general option for R that enables me to still see the code and the output of all the iterations till the loop is over, as was the case with earlier R versions. I didn't include the code as it's a long one. Thanks a lot in advance, Maram Sent from my iPhone

...ing me some problems, so I don't know if there is a general option for R that enables me to still see the code and the output of all the iterations till the loop is over, as was the case with earlier R versions. I didn't include the code as it's a long one. Thanks a lot in advance, Maram Sent from my iPhone

Hi all, I've a trivial question. If (q) is a continous variable,actually a vector of 1000 values. how to calculate the probability that q is greater than a specific value, i.e. P(q>45)?? Thanks Maram [[alternative HTML version deleted]]

...TYPE=English_United States.1252 > [3] LC_MONETARY=English_United States.1252 > [4] LC_NUMERIC=C > [5] LC_TIME=English_United States.1252 > > attached base packages: > [1] stats graphics grDevices utils datasets methods base > > > > > On 11/23/2016 5:22 PM, Maram SAlem wrote: >> Thanks a lot Bert , will check out your suggestions. >> >> I've unchecked the buffer output option in GUI but still have the >> same problem. >> >> Thanks for your time and concern. >> >> Maram Salem >> >> Sent from my...

Hi all, I've a linear equation of the form: 0.95=2 ( [3+ln(x/3)]^-13  + 4 [3+2ln(x/3)]^-13  + [3+4ln(x/3)]^-13 ) and I want to solve it for x, can I do this using R? Thanks in advance. Maram. [[alternative HTML version deleted]]

...'t mean a linear equation, of course this equation is not linear, I meant an equation in one unknown. Hi all, I've a linear equation of the form: 0.95=2 ( [3+ln(x/3)]^-13? + 4 [3+2ln(x/3)]^-13? + [3+4ln(x/3)]^-13 ) and I want to solve it for x, can I do this using R? Thanks in advance. Maram. ? ? ? ??? [[alternative HTML version deleted]] -------------- next part -------------- ______________________________________________ R-help at r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guid...

Dear All, I'm trying to plot a histogram (with the relative frequencies as the Y axis), But the scale of the y axis is given by 0e+00, 1e-04, 2e-04, 3e-04,......... Now, I have 2 questions 1- Does (1e-04=0.01831563)? 2- If this true,how can i change the given scale to (0.01,0.03,0.05,0.07,0.09)? [[alternative HTML version deleted]]

...kernel density estimation toestimate the density of q. But what I'm really intersed in is to?estimate the probability that q is greater than a certain value , for ex.,P(q>11000), using the density estimates I obtained. ?Could u help me with a fn or some document to do this? Thank u so much Maram

...i want to integerate f(x) over a certain range using integrate( ). So i want R to consider the above matrix as a function where the first col is the argument x and the second is the realization f(x). I've tried as.function and vectorize but it didn't work out. Could u help me do it? Thanks Maram [[alternative HTML version deleted]]

...he arguments of akj(x, z =, p =, h = -1, alpha = 0.5, kappa = 0.9, iker1 = 0) I've a vector of 1000 values (my X), but I don't know how to get the Z and what's Kappa? I'm sorry if the question is trivial but I hope u could recommend some refrence if u know one. Thank u so much again Maram ________________________________ From: John Kane <jrkrideau@yahoo.ca> Sent: Monday, June 29, 2009 10:35:49 PM Subject: Re: [R] (no subject) Perhaps? http://finzi.psych.upenn.edu/R/library/quantreg/html/akj.html > Subject: [R] (no subject) > To: r-help@r-project.org > Re...

--- On Tue, 6/30/09, maram salem <marammagdysalem at yahoo.com> wrote: > From: maram salem <marammagdysalem at yahoo.com> > Subject: [R] (no subject) > To: r-help at r-project.org > Received: Tuesday, June 30, 2009, 6:34 AM > Hi Group, > I've a vector of 1000 numeric values for which I want...

Dear all, How can I use the histogram density estimate (hist) to find the value of the cdf at a certain point? Thanks Maram [[alternative HTML version deleted]]

...9313 But when I used hist with breaks = "scott", that is h<-hist(x,breaks="scott") I got the breaks in the histogram object = 0  10   20   30 that is, the binwidth used is equal to 10 not 7.89313?? I don't know why? shouldn't they be exactly the same?? Thanks a lot, Maram. [[alternative HTML version deleted]]

...rnel="gaussian") > d > plot(d)   But what I'm really intersed in is to estimate the probability that q is greater than a certain value , for ex.,P(q>11000), using the kernel density estimate I obtained.  Could u help me with a fn or some document to do this? Thank u so much Maram           [[alternative HTML version deleted]] [[alternative HTML version deleted]]

...kernel density estimation toestimate the density of q. But what I'm really intersed in is to?estimate the probability that q is greater than a certain value , for ex.,P(q>11000), using the density estimates I obtained. ?Could u help me with a fn or some document to do this? Thank u so much Maram ? ? ?? Dear All, Attached are the codes of a histogram & a kernel density estimate and the output they produced. I'll copy the codes here in case there's something wrong with the attachement -------------- next part -------------- _____________________________________________...