Displaying 20 results from an estimated 72 matches for "logrank".
2007 May 01
7
logrank test
how do l programme the logrank test. l am trying to compare 2 survival curves
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2006 Jan 03
1
p-value of Logrank-Test
Hello!
I want to compare two Kaplan-Meier-Curves by using the Logrank-Test:
logrank(Surv(time[b], status[b]) ~ group[b])
This way I only get the value of the test-statistic, but not the p-value.
Does anybody know how I can get the p-value?
Thanks in advance!
Verena Hoffmann
2007 May 07
2
computing logrank statistic/test
hie how do you compute the logrank test using R
what commands do you use my data looks something like just an example
treatmentgrp strata censoringTime survivalTime censoring act.surv.time
[1,] 2 2 42.89005 1847.3358 1 42.89005
[2,] 1 1 74.40379 44...
2007 May 14
1
logrank
hie
is it possible to get the code for the logrank test l just need the chisquared value.
thanks
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2011 Nov 20
1
Cox proportional hazards confidence intervals
...lly
obtain the LR, Wald, and Score test p-values from the coxph.object, as
well as the hazard ratio as follows:
formula.obj = Surv(days, status) ~ type
coxph.model = coxph(formula.obj, df)
fit = summary(coxph.model)
hazard.ratio = fit$conf.int[1]
lower95 = fit$conf.int[3]
upper95 = fit$conf.int[4]
logrank.p.value = fit$sctest[3]
wald.p.value = fit$waldtest[3]
lr.p.value = fit$logtest[3]
I had intended to report logrank P values with the hazard ratio and CI
obtained from this function. In one case the P was 0.04 yet the CI
crossed one, which confused me, and certainly will raise questions by
review...
2007 Nov 16
1
logrank test
hie carried out a comparison of survival curves using the log rank test in R with the values of rho ranging from -2 to 2 in increments of 0.5 the question is at rho=-1.5 the power of the test seems to fluctuate or differ from the trend shown by the other values of rho is the statistical reason for this difference.ie if the power is increasing as i move from 0 to -2 at rho=-1.5 the power either
2008 Feb 28
0
surv2sample 0.1-2
...ons should update because a bug in the function
cif2.ks has been fixed.
General information about the package:
surv2sample provides various two-sample tests for right-censored survival
data. Three main areas and corresponding methods are:
* comparison of two survival distributions
- surv2.logrank: weighted logrank tests and their combinations (max, sum)
- surv2.neyman: Neyman's smooth test and its data-driven version
- surv2.ks: Kolmogorov?Smirnov, Cram?r?von Mises and Anderson?Darling
test
* comparison of two cumulative incidence functions for competing risks data
- cif: es...
2008 Feb 28
0
surv2sample 0.1-2
...ons should update because a bug in the function
cif2.ks has been fixed.
General information about the package:
surv2sample provides various two-sample tests for right-censored survival
data. Three main areas and corresponding methods are:
* comparison of two survival distributions
- surv2.logrank: weighted logrank tests and their combinations (max, sum)
- surv2.neyman: Neyman's smooth test and its data-driven version
- surv2.ks: Kolmogorov?Smirnov, Cram?r?von Mises and Anderson?Darling
test
* comparison of two cumulative incidence functions for competing risks data
- cif: es...
2009 Sep 16
2
Teasing out logrank differences *between* groups using survdiff or something else?
R Folk:
Please forgive what I'm sure is a fairly na?ve question; I hope it's clear.
A colleague and I have been doing a really simple one-off survival analysis,
but this is an area with which we are not very familiar, we just happen to
have gathered some data that needs this type of analysis. We've done quite
a bit of reading, but answers escape us, even though the question below
2013 Apr 02
0
coxph and variables
...eCat_all)1 2.6426 0.3784 0.7847
8.8989as.factor(nodeCat_all)2 7.1803 0.1393 2.1720
23.7368Concordance= 0.699 (se = 0.039 )Rsquare= 0.096 (max possible=
0.911 )Likelihood ratio test= 23.33 on 3 df, p=3.444e-05Wald test
= 21.76 on 3 df, p=7.312e-05Score (logrank) test = 24.46 on 3 df,
p=2.001e-05
I think, this means that the two variables I tested are of interest to build
the model with a p-value of about 10e-5. This also mean that having the
Herceptincat =1 is significantly different from having a Herceptincat = 0.
Moreover, having a nodecat_all iof 2...
2010 Apr 20
3
Help: coxph() in {survival} package
Hi All,
I'm runnning coxph() on 90 different datasets (in a loop).
1. I'm wondering how can I get "log-likelihood" value from coxph() output.
Currently I can only see following:
Likelihood ratio test =
Wald test =
Score (logrank) test =
2. Once I have likelihood value, I would like to extract these from R
output (for each data set).
Can any one help please, thanks in advance,
Xin
P.S. OR, may be if anyone can suggest me some other function which can help
me with this.
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2004 Aug 17
1
survdiff
Hello,
As I am quitte an ignorant user of R, excuse me for any wrongfull usage of
all the terms.
My question relates to the statistics behind the survdiff function in the
package survival.
My textbook knowledge of the logrank test tells me that if I want to compare
two survival curves, I have to take the sum of the factors: (O-E)^2/E of
both groups, which will give me the Chisq.
If I calculate this by hand, I get a different value than the one R is
giving me.
Actually, the (O-E)^2/E that R gives me, those I agree with,...
2008 Oct 30
2
p-value=0 running coxph
...-9.16 0
exp(coef) exp(-coef) lower .95 upper .95
Albumin_gproL 0.855 1.17 0.826 0.884
Rsquare= 0.003 (max possible= 0.033 )
Likelihood ratio test = 73.6 on 1 df, p=0
Wald test = 83.8 on 1 df, p=0
Score (logrank) test = 86.1 on 1 df, p=0
> cox.zph(cox_1111)
rho chisq p
Albumin_gproL -0.0509 0.197 0.657
----------------------------------------------------------------------------------------------------
Thank you in advance...
GSt
--
View this message in c...
2011 Jun 28
2
coxph() - unexpected result using Crawley's seedlings data (The R Book)
...e 0.9981 1.002 0.3120 3.193
gapsize:strata(cohort)cohort=September 2.0491 0.488 0.3792 11.074
Rsquare= 0.022 (max possible= 0.993 )
Likelihood ratio test= 1.35 on 2 df, p=0.5097
Wald test = 1.32 on 2 df, p=0.5178
Score (logrank) test = 1.33 on 2 df, p=0.514
Anyone have an idea why this is occurring?
Kind Regards
Jacob
2009 May 10
2
plot(survfit(fitCox)) graph shows one line - should show two
...P] -1.15 0.316 0.518 -2.23 0.026
exp(coef) exp(-coef) lower .95 upper .95
Drug[T.MXT+CSP] 0.316 3.16 0.115 0.871
Rsquare= 0.086 (max possible= 0.915 )
Likelihood ratio test= 5.75 on 1 df, p=0.0165
Wald test = 4.96 on 1 df, p=0.026
Score (logrank) test = 5.52 on 1 df, p=0.0188
>
>
> plot(survfit(fit0))
John David Sorkin M.D., Ph.D.
Chief, Biostatistics and Informatics
University of Maryland School of Medicine Division of Gerontology
Baltimore VA Medical Center
10 North Greene Street
GRECC (BT/18/GR)
Baltimore, MD 21201-152...
2009 Aug 03
0
new package: interval
I have just uploaded a new package called interval. It does weighted logrank tests (e.g., logrank, Wilcoxon-type tests) on interval censored data. It allows Surv objects and can calculated exact p-values. It calls the perm package, but also allows calculation of scores that may be output to faster permutation packages like coin.
There is a full description of the packge an...
2010 Feb 04
0
Update of interval package
Hi all,
I have uploaded an update of the interval package, which calculates nonparametric maximum likelihood estimates (NPMLE) of distributions and exact or asymptotic weighted logrank-type tests for interval censored data. An important part of the update is that now the default initial estimate of the NPMLE uses the MLEcens package and is much faster. This increases the speed of the logrank-type tests as well. Other changes are listed in the NEWS file.
For details on the packa...
2003 Jun 13
1
(no subject)
Dear collegues,
Using maxstat I am getting the following:
> blood <- maxstat.test(Surv(SUPER, FV)~ZAP,data=zap70, smethod="LogRank")
Error in maxstat(y = structure(c(24.4301369863014, 26.4164383561644,
18.7835616438356, : couldn't find function "cscores"
I do not know the meaning of this problem. Could you please help me on dat?
Thank you in advance for your time.
Sincerely,
Francesc Bosch, M.D.
Senior...
2005 Dec 13
1
Problem with understanding output of Cox model
...del for discrete choice
habitat modelling.
However, I'm having a hard time understanding the meaning of the first
line the following part of the summary() output:
Rsquare= 0.307 (max possible= 0.475 )
Likelihood ratio test= 91.8 on 12 df, p=2.23e-14
Wald test = 26.3 on 12 df, p=0.00977
Score (logrank) test = 58.6 on 12 df, p=4.03e-08
Does anyone know how I can read the 'max possible' R-square? What does
it signify?
Is it some kind of quasi-correlation; in which case I read it that I
have explained 65% (i.e., 0.307/0.475) of the variation?
I hope someone can help on this.
Thanks in a...
2009 Aug 03
0
new package: interval
I have just uploaded a new package called interval. It does weighted logrank tests (e.g., logrank, Wilcoxon-type tests) on interval censored data. It allows Surv objects and can calculated exact p-values. It calls the perm package, but also allows calculation of scores that may be output to faster permutation packages like coin.
There is a full description of the packge an...