Displaying 4 results from an estimated 4 matches for "lis2".
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2011 Apr 06
2
A zoo related question
Dear all, please consider my following workbook:
library(zoo)
lis1 <- vector('list', length = 2)
lis2 <- vector('list', length = 2)
lis1[[1]] <- zooreg(rnorm(20), start = as.Date("2010-01-01"), frequency = 1)
lis1[[2]] <- zooreg(rnorm(20), start = as.yearmon("2010-01-01"), frequency =
12)
lis2[[1]] <- matrix(1:40, 20)
lis2[[2]] <- matrix(41:80, 20)...
2006 Sep 07
1
Running wilcox.test function on two lists
Dear all,
I'm a newbie to R and I would really apperciate any help with the following:
I have two lists, l1 and l2:
l1:
$"A*0101"
[1] 0.076 0.109 0.155 0.077 0.09 0 0 0.073
[9] 0.33 0.0034 0.0053
$"A*0247"
[1] 0 0 0.5 .004 0 0 0
$"A*0248"
[1] 0 0 0.3 0 0.06
....
l2:
$"A*1101"
[1] 0.17 0.24 0.097 0.075 0.067
$"A*0247"
numeric(0)
2011 Apr 19
1
Reducing dimension of a list object
...rent session I have few objects which are
actually list of list of list..(say n step). If I reduce their dimension
then I have call Reduce() function many times. Therefore my question is, is
there any 1-step way to reduce the dimension at the lowest level? Take this
example:
lis1 <- list(4)
lis2 <- list(1,8)
lis3 <- list(lis1, lis2)
# Now I want to reduce the dimension of lis3 to a column vector:
> Reduce("c", Reduce("c", lis3))
[1] 4 1 8
I want to have some mechanism so that I need not to call reduce() function
twice. Is there any way to do that?...
2005 Jan 06
2
Generating Data mvrnorm and loops
Dear List:
I am generating N datasets using the following
Sigma<-matrix(c(400,80,80,80,80,400,80,80,80,80,400,80,80,80,80,400),4,4
)
mu<-c(100,150,200,250)
N=100
for(i in 1:N)
{
assign(paste("Data.", i, sep=''),
as.data.frame(cbind(seq(1:1000),(mvrnorm(n=1000, mu, Sigma)))))
}
With these datasets, I need to work on some of the variables and then
run each dataset