search for: lis

I am tying myself in knots over subscripts when applied to lists I have a list along the lines of: lis<-list(c("a","b","next","want1","c"),c("d", "next", "want2", "a")) >From which I want to extract the values following "next" in each member of the lis...

Is there a simple way to calculate summary statistics for all the matrices or dataframes in a list? For example: > z <- list(matrix(c(2,2,2,2), ncol = 2), matrix(c(4,4,4,4), ncol = 2)) > z [[1]] [,1] [,2] [1,] 2 2 [2,] 2 2 [[2]] [,1] [,2] [1,] 4 4 [2,] 4 4 > I would like to calculate, for example, the mean value for each cell. I can do that the h...

..., or a function (if the lib contains one) that returns a value whitch equals to the overall loudness of a frame. So i can do some simple interactions with users whitch doesnt want to yell in their microphone for talking something. Other ones got headsets that record their breathing and anyone can listen to. This is not funny the whole day... Greets Lis ----- Original Message ----- From: "Jean-Marc Valin" <jean-marc.valin@usherbrooke.ca> To: "Lis" <lis@1234567890qwertzuiopasdfghjklyxcvbnm.de> Cc: <speex-dev@xiph.org> Sent: Thursday, March 02, 2006 2:35 AM...

...xt <- htmlTreeParse(txt, error=function(...){}, useInternalNodes = TRUE) > > g <- xpathSApply(txt, "//p", function(x) xmlValue(x)) > head(grep(" ", g, value=T)) [1] "????PART-TIME EXPORT SALES ASSOCIATES (ALSO SUMMER WORK) ? Valuatum Oy ??Helsinki ??Ilmoitus lis??tty: 31.12.2009. Viimeinen hakup??iv??: 28.02.2010" [2] "????MSN EDITOR / ONLINE PRODUCER ??Manpower Oy ??Espoo ??Ilmoitus lis??tty: 30.12.2009. Viimeinen hakup??iv??: 15.1.2010" [3] "????MYYNTINEUVOTTELIJA ??Rand Customer Contact Oy ??Helsinki ? Ilmoitus lis??tty: 30.12.2009....

...f the SPEC97 tomcatv benchmark I have laying around. So it seems both 32-bit and 64-bit can call into shared libs. Not to say I haven't seen some code gen warts (using -O3). :) >From hello.s: main: mflr 0 stw 31, -4(1) stw 0, 4(1) stwu 1, -16(1) lis 3, .Lstr at ha mr 31, 1 la 3, .Lstr at l(3) bl puts li 3, 0 addi 1, 1, 16 lwz 0, 4(1) lwz 31, -4(1) mtlr 0 blr By the strict letter of the 32-bit ABI, the save and restore of r31 at a negative offset of r1 is verboten. The A...

Dear experts, For the makeGenotype function I need a list as in the example. However, since my list needs to be 184 long there must be an easy way to make it. >list(1:2,3:4,5:6,7:8) [[1]] [1] 1 2 [[2]] [1] 3 4 [[3]] [1] 5 6 [[4]] [1] 7 8 I have tried lis<-1:184 dim(lis)=c(92,2,1) as.list(lis) and several other options. Any suggestions?...

Hi I have a list that has attributes: attributes(lis[2]) $names [1] "150096_at" I want to use those attributes in a function and then use lapply to apply that function to every element of the list, eg for simplicity's sake: my.fun <- function(x) { attributes(x) } Then l2 <- lapply(...

Hi, I am using this subset statement and it works outside a function. LIS[[i]]<- lapply(LI, subset, select=cov[[i]]) However, wrapped inside a function this statement produces the same values for every LIS[[1]] which is only the first subset of LI. Does anyone know why is not working correctly inside a function? ff = factor(covariate) nLev <- nlevels(ff) cov <...

...removed completely, and LiveIntervals can be directly // computed. (We still either need to regenerate kill flags after regalloc, or // preferably fix the scavenger to not depend on them). When looking in TwoAddressInstructionPass.cpp it looks like the pass only use/update LV when there is no LIS. And there seems to be an experimental -early-live-intervals option to calculcate LIS before TwoAddressInstructionPass. I also noticed that the -early-live-intervals option was added back in 2012. So I assume that the plans to replace LiveVariables by LiveIntervals in TwoAddressInstructionPass got...

Dear list members, I am trying, within a lapply command, to print the name of the objects in list or data frame. This is so that I can use odfWeave to print out a report with a section for each object, including the object names. I tried e.g. a=b=c=1:5 lis=data.frame(a,b,c) lapply( lis, function (z) { ob...

...dxvon at 163.com> wrote: > >> >> At 2014-01-01 04:36:21,"Andrew Trick" <atrick at apple.com> wrote: >> >> On Dec 31, 2013, at 3:52 AM, Haishan <hndxvon at 163.com> wrote: >> My update steps are shown following: >> LiveIntervals *LIS = &getAnalysis<LiveIntervals>(); >> 1. LIS->insertMBBInMaps(NewMBB) >> 2. LIS->InsertMachineInstrRangeInMaps(NewMBB->begin(), NewMBB->end()) >> 3. Due to some machine instructions of NewMBB copy from OldMBB, I have to removeInterval firstly. Then...

...s the last couple of lines on my ssh session. Pressing enter will give me an extra blank line. There are blank lines after the last file was copied. I have not pressed CTRL-C yet. I do not have the prompt yet nor are the normal statistics/report returned from rsync. " saturn/sfkpipe07.lis saturn/sfkpipe08.lis saturn/sfkpipe09.lis saturn/sfkpipe10.lis saturn/sfrpini.lis saturn/sfrpini_uvi.log " After completion, while hanging waiting for report and shell prompt, On the sending side: ps -ef | grep rsync root 467122 757914 0 20:28:47 pts/0 0:00 remsh backenp650 rsyn...

[My previous message rejected, therefore I am sending same one with some modification] I have 3 vectors with object name : dat1, dat2, dat3 Now I want to create a loop, like : for (i in 1:3) { cat(sd(dati)) } How I can do this in R? Regards,

...s, compared to recomputing liveness in batch after multiple changes. Consider hoisting chained instructions out of a loop one at a time. The live ranges of the intermediate steps look completely different from the final result. So for a future automatic liveness API, I imagine something like: LIS.beginChanges(); .. Move multiple instructions around. .. LIS.endChanges(); [Or it could use RAII, that's not important] MachineFunction would provide observer hooks that LIS can use to collect a set of changed instructions. The call to LIS.endChanges() would then recompute the invalid...

I done it speex_preprocess_ctl(sppPreprocess, SPEEX_PREPROCESS_GET_PROB_START, &g.s.VADstart); speex_preprocess_ctl(sppPreprocess, SPEEX_PREPROCESS_GET_PROB_CONTINUE, &g.s.VADcontin); /*char *lisDebugCh = (char*) malloc(20); int decimalFcvt, signFcvt; static int firstDebug = 1; lisDebugCh = gcvt(g.s.VADstart, 20, lisDebugCh); if(firstDebug == 1) { ::MessageBoxA(NULL, lisDebugCh, "Mumble", MB_OK | MB_ICONERROR); firstDebug = 0; }*/ g.s.VADstart = 0.90f; f.s....

On 2008-06-11, at 13:16, Gary Benson wrote: > Duncan Sands wrote: > >> Can you please attach IR which can be compiled to an executable >> (and shows the problem). > > I've been generating functions using a builder and then compiling > them with ExecutionEngine::getPointerToFunction(). Is there some way > I can get compilable IR from that?

I havent had found anything in the documentation about voice activation levels. Does i can change a variable to change the accuracy for activations? If not does the speex lib already implement a function for read out the sound level of a frame? Thanks for the advance. Lis (Louis Hoefler) -------------- next part -------------- An HTML attachment was scrubbed... URL: http://lists.xiph.org/pipermail/speex-dev/attachments/20060302/7464c135/attachment.html

Duncan Sands wrote: > Can you please attach IR which can be compiled > to an executable (and shows the problem). I've been generating functions using a builder and then compiling them with ExecutionEngine::getPointerToFunction(). Is there some way I can get compilable IR from that? Cheers, Gary -- http://gbenson.net/

...omputeVirtRegs. LiveVariables is not actually needed to update live intervals. It is only added as a requirement to make sure it runs before the 2-address pass. -Andy Thank you for your reply. I do it as you tell me, and you are right. My update steps are shown following: LiveIntervals *LIS = &getAnalysis<LiveIntervals>(); 1. LIS->insertMBBInMaps(NewMBB) 2. LIS->InsertMachineInstrRangeInMaps(NewMBB->begin(), NewMBB->end()) 3. Due to some machine instructions of NewMBB copy from OldMBB, I have to removeInterval firstly. Then I use LIS->createAndComp...

Dear all, I think that my question is very simple but I failed to solve it. I have a list which elements are matrices like this: >mylist [[1]] [,1] [,2] [,3] [1,] 1 3 5 [2,] 2 4 6 [[2]] [,1] [,2] [,3] [1,] 7 9 11 [2,] 8 10 12 I'd like to create a matrix M<-mylist[[1]]+mylist[[2]] [,1] [,2] [,3] [1,] 8 12 16 [2,] 1...