search for: lenx

Dear All! How can I cope with overlapping or covered labels (covered by labels from other data points) in plots? Martina Renninger [[alternative HTML version deleted]]

Hi, all. I'm using hist() to obtain a vector of break values in an interval. I then want to be able to identify which cell any value from another vector falls in. E.g. applying > breaks [1] -3.5 -3.0 -2.5 -2.0 -1.5 -1.0 -0.5 0.0 0.5 1.0 1.5 2.0 to > x [1] -3.74519666 -0.38183630 -1.22884247 -0.20971824 -0.30533939 -0.36271207 [7] -2.27513499 -2.23688653 -1.98827155 -1.48666274

Dear All, Sorry to bother I want to write a function in R using if Say I have a dataset x, if x[i]<0, then x[i]=x[i], if x[i]>0, then x[i]=0 for example, x=-3:3, then using the function, x becomes [-3,-2,-1,0,0,0,0] I write the codes as follows, gjr=function(x) {lena=length(x) for(i in 1:lenx) if (x[i]<0) return (x[i]) if (x[i]>0) return (0) x} but then, doing gjr(x? it only comes out with one number Does anyone have any suggestions? I appreciate a lot! Sincerely, Zoe -- View this message in context: http://r.789695.n4.nabble.com/if-function-problems-tp3710995p3710995.html...

Hi, This is a simple version of something that I am trying to do. If I can sort the problem basically, I figure I should be able to sort it for the program I'm writing (which would take longer to explain). I need to know if there is any way of using different colours for different intervals of a line on a graph. Eg. If I plot the line y=x for x=1:10, and split this line into 106 intervals

...on (x, y, plot.it = TRUE, xlab = deparse(substitute(x)), ylab = deparse(substitute(y)), x.counts=rep(1L,length.out=length(x)), y.counts=rep(1L,length.out=length(y)), ...){ sx <- sort(x) sy <- sort(y) swx <- cumsum(x.counts[order(x)]) swy <- cumsum(y.counts[order(y)]) lenx <- length(sx) leny <- length(sy) sx <- approx(swx, sx, n=min(lenx,leny))$y sy <- approx(swy, sy, n=min(lenx,leny))$y if (plot.it) plot(sx, sy, xlab = xlab, ylab = ylab, ...) invisible(list(x = sx, y = sy)) } #Sample example n <- 15 a <- runif(n);b <...

...dditive and 0 as multiplicative. The R seasonal can be "additive" or "multiplicative", so the R code must invert the logic when calling C. The proposed solution is to define a seasonalChoice variable: hw <- function(x, alpha, beta, gamma, seasonal, start.time, f, ...) { lenx <- length(x) seasonalChoice <- if (seasonal == "multiplicative") 0L else 1L .C(C_HoltWinters, as.double(x), lenx, as.double(max(min(alpha, 1), 0)), as.double(max(min(beta, 1), 0)), as.double(max(min(gamma, 1), 0)), as.integer(...

...name list(coefficients= coef, residuals = resid, effects = eff, rank= dimx[2], fitted.values = fits, assign= assn, cov.unscaled = D, df.residual = dimy[1] - dimx[2], df = df ) } print.aov <- function (x, digits = max(3, .Options$digits - 3), ...) { lenx <- length(x$df) tabl <- cbind(x$df,x$effects, x$effects/x$df) tabl <- cbind(tabl,c(tabl[1:(lenx-1),3]/tabl[lenx,3],NA)) tabl <- cbind(tabl,1-pf(tabl[,4],tabl[,1],tabl[lenx,1])) dimnames(tabl) <- list(names(x$effects), c("df","SS","MS","F...

Hey there I have two vectors: y<- c(0.4, 0.0, 0.2, -0.2, -0.6, 0.2, 0.0, 0.0, 0.4, 0.4, 0.2) In the vector y, I want to access (in the order given) all of the values in between each of the specific values of given. I understand subsetting with y[i], but how do I get to ssomewhere in between -0.6 and 0.2? Thanks Eric Jennings matheric at myuw.net

Dear all, ftable produces a list of the frequencies of all occuring values. But how about the occuring values? How can I retrieve a list of occuring values? How can I retrieve a table with both the list of occuring values and their respective frequencies? Thank you in advance, Yours, Ferri

Dear R commnuity, Thanks a lot for your help. I want to read in tables, the problem is that the table is composed in a difficult way. In ariginal it looks like this: 669 736 842101610481029114711811166124312081128117611221026 9581024 992 685 720 829 925 995 96010241057116611501104106410711092 983 908 989 904 924 896 882 897 909 933 928 907 916 902 546 734 784 868 970 954

I have a, no doubt, simple question. I wish to write a function such that a <- 9 b <- 10 changer _ function(x,y) { if (y>x){ x <<- Y+1}} Of course there are easier ways to accomplish the task above, but I am more interested in how to have the "x <<- Y+1" part of the function to change x in place for purposes of a much larger function. I have been wrestling with