search for: lanas

Is anyone using Gluster with the Rocks cluster system? If so, do you know if there is a Roll for Gluster? Or, do you have any advice about things to do and things to avoid doing? We're considering using Gluster with Infiniband on our cluster and trying to learn whether other people have done this so we can perhaps learn from their experience. Thanks. .. Lana (lana.deere at gmail.com)

Hi, Can someone suggest an efficient way to substitute a vector/matrix which contains 1's and 0's to P's and A's (resp.)? Thanks, Lana

I am not able to find information about doing line plots with error bars in the R- help information. Would someone like to tell me if this can be done in R and either get me started or lead me to information about how to do the error bars? Thanks, Lana

Friends, Is there a Partial Least Squares package implemented in R? Thanks, Lana [[alternative HTML version deleted]]

I hope this isn't too long, and I hope it's the correct list. I have a network configuration where I have 2 hosts, A and B. Each has a local LAN on which the run Samba, plus they're connected by a VPN. So has A has addresses lanA and wanA, and host B has addresses lanB and wanB. Because of the way the VPN works, they can talk to each other either via their LAN addresses (lanA

Hi, I need to convert numbers to characters in order to index an array when I encountered the number 100000 which turned into "1e+05". Does anyone know how to get around this problem? Lana Schaffer Biostatistics/Informatics The Scripps Research Institute DNA Array Core Facility La Jolla, CA 92037 (858) 784-2263 (858) 784-2994 schaffer at scripps.edu

Unknown ----- Original Message ----- From: <samba@samba.org> To: Multiple recipients of list SAMBA <samba@samba.org> Sent: Monday, September 27, 1999 10:37 AM Subject: SAMBA digest 2249 > SAMBA Digest 2249 > > For information on unsubscribing see http://samba.org/listproc/ > Topics covered in this issue include: > > 1) Re: redhat->nt printing problem after

How can plots (histograms) be implemented with the command line interface to R? Lana Schaffer

Hi, I am using this subset statement and it works outside a function. LIS[[i]]<- lapply(LI, subset, select=cov[[i]]) However, wrapped inside a function this statement produces the same values for every LIS[[1]] which is only the first subset of LI. Does anyone know why is not working correctly inside a function? ff = factor(covariate) nLev <- nlevels(ff) cov <-

Hello everyone, I use syslinux to make bootable USB sticks. I would like to offer the choice, right at the beginning, to either continue booting from the USB stick, or to boot as usual from the hard disk. Is this psossible to do with syslinux ? Thanks, Al

Hi, I am trying to compile the R-dev version on a unix Suse machine and got errors. Would someone be able to help me determine what to do to fix these errors: make[1]: Entering directory `/lustre/people/schaffer/R-devel/m4' make[1]: Nothing to be done for `R'. make[1]: Leaving directory `/lustre/people/schaffer/R-devel/m4' make[1]: Entering directory

It looks like you made a copy/paste error below. Your ata.frame should be data.frame. Kevin On 05/04/2018 08:18 AM, Bill Poling wrote: > Good morning. > > Novice usR. Here. > > I am following this string, among many, learning as I go. > > Quick question please? > > I thought that perhaps ata.frame was part of the zoo pkg, b/c when I > searched it came up in

I suspect this is pretty easy, but I'm having trouble figuring it out. Basically, I have a list of data frames such as the following example: list(A=data.frame(x=1:2, y=3:4),B=data.frame(x=5:6,y=7:8)) I would like to turn this into data frame where the list elements are essentially rbind'ed together and the element name becomes a new variable. For example, I would like to turn the

Good morning. Novice usR. Here. I am following this string, among many, learning as I go. Quick question please? I thought that perhaps ata.frame was part of the zoo pkg, b/c when I searched it came up in help? However, evidently not or I am not using it properly. Please advise, thank you. x <- list(A=data.frame(x=1:2, y=3:4),B=data.frame(x=5:6,y=7:8)) x2 <- do.call(rbind,

pc1(LANa) ----poor connection ----> VPS <--------- PC2(LANb) pc1 and pc2 used to connected directly with tinc, since pc1 used to have WAN IP(pppoe), but the pppoe IP is not WAN IP anymore (ISP changed to let all ADSL user in a LAN). if I let the two pc connect to a VPS with tinc, can later connections between pc1 and pc2 be directly ? for example, ssh from pc1 to pc2 but not proxyed by

Hello, From a user perspective, the simple (tcpri) and complex TC configs offers two rather distinct choices. A user can very well be OK with only using the simple way and that''s very fine. Then again, even in doing so, the more complex config options are available. What is the interplay between the two as far as having some parameters configured in both at the same time ? So far

Hi Kevin, There is probably a better way, but it can be done in two steps like this temp <- list(A=data.frame(x=1:2, y=3:4),B=data.frame(x=5:6,y=7:8)) temp <- lapply(names(temp), function(n, temp) { temp[[n]]$type <- n return(temp[[n]]) }, temp = temp) do.call(rbind, temp) On Wed, May 2, 2018 at 1:11 PM, Kevin E. Thorpe <kevin.thorpe at utoronto.ca> wrote: > I suspect

Hi, I am running OpenVPN where i have one central hub VPN server, and multiple spoke VPN clients. I can ping from each client to the server and each client to computers on the subnet which the server resides (192.168.2.0/24) so it works ok there. I cannot however, ping from one client to another client. I guess the packet path would go: clienta -> vpn -> shorewall/router -> vpn ->

I'm sure this is simple enough, but an R site search on my subject terms did suggest a solution. I have a numeric vector with many values that I wish to create a factor from having only a few levels. Here is a toy example. > x <- 1:10 > x <-

Hello: I wonder if I could get a little help with random sampling in R. I have a vector of length 7375. I would like to draw 3 distinct random samples, each of length 100 without replacement. I have tried the following: d1 <- 1:7375 set.seed(7) i <- sample(d1, 100, replace=F) s1 <- sort(d1[i]) s1 d2 <- d1[-i] set.seed(77) j <- sample(d2, 100, replace=F) s2 <- sort(d2[j])