search for: l2

Dear R-users, i have to integrate the following function `fun1` <- function (a, l1, l2) { exp(log(l1) * (a - 1) - l2 * lgamma(a)) } but if l1 is large, i get the "non-finite function value" error, so my idea is to rescale with exp(-l1) `fun2` <- function (a, l1, l2) { exp(log(l1) * (a - 1) - l2 * lgamma(a) - l1) } but it seems this doesn't solve the problem,...

...f_X), replace=TRUE), rep(ID.Path, No_of_X)) Y <- lapply(X,function(x) sample(x, round(runif(1, min=10, max=50)))) X and Y are both lists, and I've made the following function to work on that data as part of a simulation I'm building: Mutate<-function(x){ l<-0 for(i in x){ l2<-0 l<-l+1 for(i in x[[l]]){ l2<-l2+1 if(runif(1) < 0.9) ifelse(runif(1) <0.5, x[[l]][l2] <- x[[l]][l2]+1, x[[l]][l2] <- x[[l]][l2]-1) } } return(x) } I call this with Effectors<-Mutate(X) The function is designed to alter the values of each eleme...

Shamelessly reusing the announcement Arnaud sent about three months ago for nut-2.2.1: "We're preparing to release 2.2.1-pre2, so if you have some fixes to backport on Testing, consider announcing it and doing asap. As always, compatibilities update and bugfixes only!" Regards, Arjen -- Eindhoven - The Netherlands Key fingerprint - 66 4E 03 2C 9D B5 CB 9B 7A FE 7E C1

...om experiment), change the value by 1 in either direction, higher or lower with equal probability. Here it is (I've changed the 0.3 value I mentioned to 0.9, so many values change so it can be easily seen): l<-0 # Set counter 1 to 0. for(i in Effectors){ # Begin loop on list of effectors. l2<-0 # Set counter 2 to 0. l <-l+1 # Increace counter number 1. for(i in Effectors[[l]]){ # Begin loop through all effector values. l2 <-l2+1 # Increace counter number 2. if(runif(1) < 0.9) ifelse(runif(1) <0.5, Effectors[[l]][l2] <- Effectors[[l]][l2]+1, Effectors[[l]][...

...notice below, the output is sorted according to lags. >VAR(cbind(fossil,labour),p=2,type="const") VAR Estimation Results: ======================= Estimated coefficients for equation fossil: =========================================== Call: fossil = fossil.l1 + labour.l1 + fossil.l2 + labour.l2 + const fossil.l1 labour.l1 fossil.l2 labour.l2 const 0.4686535 -0.5324335 0.2308964 0.8777865 -0.6711897 Estimated coefficients for equation labour: =========================================== Call: labour = fossil.l1 + labour.l1 + fossil.l2 + labour.l2 + const f...

Hi Could anybody explain me how to check how many L1/L2 cache my cpu have. I'm using CentOS 5.6 *cat /proc/cpuinfo |grep CPU * model name : Intel(R) Core(TM)2 Duo CPU T9300 @ 2.50GHz model name : Intel(R) Core(TM)2 Duo CPU T9300 @ 2.50GHz Diagram of a generic dual-core processor, with CPU-local level 1 caches, and a shared, on-die level 2 cache....

...repeated several times, and some attributes at that location. The second table has the same locations, but only once with a different set of attributes. I would like to add the second set of attributes to the first table. Example: set.seed <- 123 loc <- c(rep("L1", 3), rep("L2", 5), rep("L3", 2)) val1 <- round(rnorm(10),2) val2 <- c("a", "b", "c", "a", "b", "d", "f", "e", "b", "e") t1 <- data.frame(loc, val1, val2) t2 <- data.frame(loc=c("L1...

QEMU's default qcow2 L2 cache size is too small for large images (and small cluster sizes), resulting in very bad performance. https://blogs.igalia.com/berto/2015/12/17/improving-disk-io-performance-in-qemu-2-5-with-the-qcow2-l2-cache/ shows huge performance hit for a 20GB qcow2 with default 64kB cluster size: L2 Cache,...

I have a vector of character strings such as mainnames<-c("CAD","AUD") and another vector say checknames<-c("CAD.l1","AUD.l1","JPY.l1","EUR.l1","CAD.l2","AUD.l2","JPY .l2","EUR.l2") I want a new vector of character strings that is just resultnames<-c("JPY.l1","EUR.l1","JPY.l2","EUR.l2") Because any time a name occurs in checknames that has a subset that matches with ma...

Hi, I'm running into a wall when trying to use the integrate function. I have the following setting: powerLaw2 <- function(x,l1,l2,c0,t0) { idx <- which(x <= 0); if (length(idx) > 0) { x[idx] <- 0; } xl <- (-l1+l2)*log(x/t0); L <- log(c0)-l1*log(x)-log(1+exp(xl)); L <- exp(L); return(L); } plCDF2 <- function(x,l1,l2,c0,t0) { print(c(l1,l2,c0,t0)); cdf <- integrate...

I think that's incorrect. It should to: .section .foo .L1: .L2 = .L1 .section .bar .long .L3-.L2 .L3: Because .L3 and .L2 are in different sections. - Justin On Thu, Jun 26, 2014 at 2:46 PM, Rafael Espíndola <rafael.espindola at gmail.com> wrote: > This reduces to > > .section .foo > .L1: > .L2 = .L1 > .section .bar > .long .L1-.L...

...10, 22, NA, NA, 80, 49, 61, 190), ncol=4 ) #Whereas x contains all NA?s from y plus some additional NA?s. #I want to find the index of these additional NA?s. I think, there must be a very easy way to do this. #Here are the indices of NA?s in x and y: l1 <- which(is.na(x), arr.ind=TRUE) l2 <- which(is.na(y), arr.ind=TRUE) #> l1 # [,1] [,2] #[1,] 2 1 #[2,] 3 1 #[3,] 4 1 #[4,] 3 3 #[5,] 4 3 #> l2 # row col #[1,] 2 1 #[2,] 3 1 #[3,] 3 3 #[4,] 4 3 #Now I want to find a matrix, which includes the values of l1, without the r...

Hi, How does the requirement that phi instructions have one value per predecessor basic block interact with indirectbr instructions? For instance, take the following code: L1: br i1 %somevalue, label %L2, label %L3 L2: %ret1 = i8* blockaddress(@myfunction, %L5) br label %L4 L3: %ret2 = i8* blockaddress(@myfunction, %L6) br label %L4 L4: %ret = phi i8* [%ret1, L2], [%ret2, L3] indirectbr i8* %ret, [label %L5, label %L6] L5: %myval = phi i32 [0, %L2], [1, %L3] ; are both of these...

Is it even possible or even worth while to do layer 3 switching (bridging) on a Linux system? Or would this be considered routing even though everything is done on OSI Layer 2? Which would be faster, Layer 3 switching (bridging) on OSI Layer 2 or routing on OSI Layer 3? Grant. . . .

On 01/17/2014 04:06 PM, Rom Freiman wrote: > Kashyap, just to be sure - it happens to you during the v2v > conversion? on L2? I haven't done any v2v conversions in L2 (or at any other level). PS: Sorry, I didn't notice my previous 2 emails didn't go to the list, that wasn't intended. Rich, you bounce them here, if you prefer (instead of me clumsily forwarding them). -- /kashyap

...gth for each type of object as opposed to the mean of all the objects in the set. This is in order to make a comparison between the lengths of each type of objects and the number of those objects. > x Chromosome Begin End Type Class Norm Length 458327 Y 1 318 L2_Plat1b LINE/L2 5.758902 317 458330 Y 439 673 L2_Plat1i LINE/L2 5.455321 234 458331 Y 2 309 L2_Plat1i LINE/L2 5.726848 307 458332 Y 1746 2232 L2_Plat1d LINE/L2 6.186209 486 458333 Y 948 1132 L2_Plat1e LINE/L2 5.214936 184 458335...

Hi We have touched on this before, but I don't think I quite got it right. So I have a list, each element of which is a a vector of 2 numbers: > l2 $cat000_a01 [1] 0.3429944 4.5138244 $cat000_a02 [1] 0.1929336 4.3064944 $cat000_a03 [1] -0.2607796 4.1551591 What I actually want to convert this into is a matrix with the names (cat000_a01 etc) as row names, the first element of each of the vectors forming the first column of the new matrix, a...

Hi, We all agree that it's not specific to virt-v2v. I managed to reproduce the same double fault on "normal" L2 boot - without libguestfs interference. And as Paolo wrote already, he will take a look at it. Thanks, Rom On Tue, Jan 21, 2014 at 3:05 PM, Richard W.M. Jones <rjones@redhat.com>wrote: > On Tue, Jan 21, 2014 at 04:38:30PM +0100, Kashyap Chamarthy wrote: > > On 01/17/2014 04:06 PM...

On Mon, Sep 19, 2016 at 11:32:26AM -0400, Frank Myhr wrote: >QEMU's default qcow2 L2 cache size is too small for large images (and small cluster sizes), resulting in very bad performance. > >https://blogs.igalia.com/berto/2015/12/17/improving-disk-io-performance-in-qemu-2-5-with-the-qcow2-l2-cache/ >shows huge performance hit for a 20GB qcow2 with default 64kB cluster size...

...ch panel shows levels vs. responses; the levels are sorted by responses but levels vary from one panel to another. However, I run into problems with controlling the y-limits and y-labels. In particular, suppose I have a data frame rsp <- c(10,2,4,0,2,3) lvl <- factor(c("L1","L2","L3","L2","L3","L4"),levels=c("L1","L2","L3","L4")) cat <- factor(c("A","A","A","B","B","B"),levels=c("A","B")) xx <- data.fram...