search for: l2

Dear R-users, i have to integrate the following function `fun1` <- function (a, l1, l2) { exp(log(l1) * (a - 1) - l2 * lgamma(a)) } but if l1 is large, i get the "non-finite function value" error, so my idea is to rescale with exp(-l1) `fun2` <- function (a, l1, l2) { exp(log(l1) * (a - 1) - l2 * lgamma(a) - l1) } but it seems this doesn't solve the problem,...

...f_X), replace=TRUE), rep(ID.Path, No_of_X)) Y <- lapply(X,function(x) sample(x, round(runif(1, min=10, max=50)))) X and Y are both lists, and I've made the following function to work on that data as part of a simulation I'm building: Mutate<-function(x){ l<-0 for(i in x){ l2<-0 l<-l+1 for(i in x[[l]]){ l2<-l2+1 if(runif(1) < 0.9) ifelse(runif(1) <0.5, x[[l]][l2] <- x[[l]][l2]+1, x[[l]][l2] <- x[[l]][l2]-1) } } return(x) } I call this with Effectors<-Mutate(X) The function is designed to alter the values of each eleme...

Shamelessly reusing the announcement Arnaud sent about three months ago for nut-2.2.1: "We're preparing to release 2.2.1-pre2, so if you have some fixes to backport on Testing, consider announcing it and doing asap. As always, compatibilities update and bugfixes only!" Regards, Arjen -- Eindhoven - The Netherlands Key fingerprint - 66 4E 03 2C 9D B5 CB 9B 7A FE 7E C1

...om experiment), change the value by 1 in either direction, higher or lower with equal probability. Here it is (I've changed the 0.3 value I mentioned to 0.9, so many values change so it can be easily seen): l<-0 # Set counter 1 to 0. for(i in Effectors){ # Begin loop on list of effectors. l2<-0 # Set counter 2 to 0. l <-l+1 # Increace counter number 1. for(i in Effectors[[l]]){ # Begin loop through all effector values. l2 <-l2+1 # Increace counter number 2. if(runif(1) < 0.9) ifelse(runif(1) <0.5, Effectors[[l]][l2] <- Effectors[[l]][l2]+1, Effectors[[l]][...

...ut and 120/120 volt outputs. The data > for the voltages is not what I'm expecting, and I am wondering how I > should interpret it. Wow, that sounds kind of industrial. Model? Is the input an L14-20P? Or equivalent non-twistlock? > Here is an example from upsc: > > input.L1-L2.voltage: 121 > input.L2-L3.voltage: 120 > input.voltage: 121.20 > output.current: 5.90 > output.L1-L2.voltage: 119 > output.L1.current: 5.90 > output.L2-L3.voltage: 119 > output.L2.current: 1 > > The "input.voltage" value doesn't reflect the 240 volts that i...

...notice below, the output is sorted according to lags. >VAR(cbind(fossil,labour),p=2,type="const") VAR Estimation Results: ======================= Estimated coefficients for equation fossil: =========================================== Call: fossil = fossil.l1 + labour.l1 + fossil.l2 + labour.l2 + const fossil.l1 labour.l1 fossil.l2 labour.l2 const 0.4686535 -0.5324335 0.2308964 0.8777865 -0.6711897 Estimated coefficients for equation labour: =========================================== Call: labour = fossil.l1 + labour.l1 + fossil.l2 + labour.l2 + const f...

Hi Could anybody explain me how to check how many L1/L2 cache my cpu have. I'm using CentOS 5.6 *cat /proc/cpuinfo |grep CPU * model name : Intel(R) Core(TM)2 Duo CPU T9300 @ 2.50GHz model name : Intel(R) Core(TM)2 Duo CPU T9300 @ 2.50GHz Diagram of a generic dual-core processor, with CPU-local level 1 caches, and a shared, on-die level 2 cache....

...t-phase" it could do some conversions. Is that feasible? Would it make more sense to do it in upsc? Or should I post-process in my own tooling? The mapping I came up with follows. Any suggestions on how/where best to deal with this? John ==== # Substitute "Leg1" for "L1-L2" or "L1" input.L1-L2.voltage=121 input.L1-L2.voltage.maximum=123 input.L1-L2.voltage.minimum=118 output.L1-L2.voltage=119 output.L1.current=6.10 output.L1.current.maximum=13.20 output.L1.current.minimum=5.50 output.L1.power.maximum.percent=63 output.L1.power.minimum.percent=27 output...

...repeated several times, and some attributes at that location. The second table has the same locations, but only once with a different set of attributes. I would like to add the second set of attributes to the first table. Example: set.seed <- 123 loc <- c(rep("L1", 3), rep("L2", 5), rep("L3", 2)) val1 <- round(rnorm(10),2) val2 <- c("a", "b", "c", "a", "b", "d", "f", "e", "b", "e") t1 <- data.frame(loc, val1, val2) t2 <- data.frame(loc=c("L1...

QEMU's default qcow2 L2 cache size is too small for large images (and small cluster sizes), resulting in very bad performance. https://blogs.igalia.com/berto/2015/12/17/improving-disk-io-performance-in-qemu-2-5-with-the-qcow2-l2-cache/ shows huge performance hit for a 20GB qcow2 with default 64kB cluster size: L2 Cache,...

Hi -- I am monitoring via the SNMP driver an APC SmartUPS that has split phase (2L + neutral) 240V input and 120/120 volt outputs. The data for the voltages is not what I'm expecting, and I am wondering how I should interpret it. Here is an example from upsc: input.L1-L2.voltage: 121 input.L2-L3.voltage: 120 input.voltage: 121.20 output.current: 5.90 output.L1-L2.voltage: 119 output.L1.current: 5.90 output.L2-L3.voltage: 119 output.L2.current: 1 The "input.voltage" value doesn't reflect the 240 volts that is actually being applied. To get that, wou...

I have a vector of character strings such as mainnames<-c("CAD","AUD") and another vector say checknames<-c("CAD.l1","AUD.l1","JPY.l1","EUR.l1","CAD.l2","AUD.l2","JPY .l2","EUR.l2") I want a new vector of character strings that is just resultnames<-c("JPY.l1","EUR.l1","JPY.l2","EUR.l2") Because any time a name occurs in checknames that has a subset that matches with ma...

Sounds pretty normal from what I see. It appears that this is *NOT* a true 240v UPS, but rather one that provides two legs of 120v output from two legs of 120 input, and what is seen as "L2" is actually neutral, and the line names are reporting incorrectly. With that in mind, each leg in should be 120v, as well as the outputs, which is exactly what you are seeing.(The fact tht L1 to L3 is 240v really isn't relevant). - Tim On November 11, 2024 6:56:51 PM EST, Greg Troxel vi...

Thanks, Tim. The unit was available with single as well as split phase output, and from the data I can find the input was single phase, though the input connector has L1/L2/N/G wires. I'm digging through the MIB to see what the raw data looks like. Thanks! John ---- On 11/11/24 19:14, Tim Dawson wrote: > Sounds pretty normal from what I see. It appears that this is *NOT* a > true 240v UPS, but rather one that provides two legs of 120v output from >...

Hi, I'm running into a wall when trying to use the integrate function. I have the following setting: powerLaw2 <- function(x,l1,l2,c0,t0) { idx <- which(x <= 0); if (length(idx) > 0) { x[idx] <- 0; } xl <- (-l1+l2)*log(x/t0); L <- log(c0)-l1*log(x)-log(1+exp(xl)); L <- exp(L); return(L); } plCDF2 <- function(x,l1,l2,c0,t0) { print(c(l1,l2,c0,t0)); cdf <- integrate...

I think that's incorrect. It should to: .section .foo .L1: .L2 = .L1 .section .bar .long .L3-.L2 .L3: Because .L3 and .L2 are in different sections. - Justin On Thu, Jun 26, 2014 at 2:46 PM, Rafael Espíndola <rafael.espindola at gmail.com> wrote: > This reduces to > > .section .foo > .L1: > .L2 = .L1 > .section .bar > .long .L1-.L...

...10, 22, NA, NA, 80, 49, 61, 190), ncol=4 ) #Whereas x contains all NA?s from y plus some additional NA?s. #I want to find the index of these additional NA?s. I think, there must be a very easy way to do this. #Here are the indices of NA?s in x and y: l1 <- which(is.na(x), arr.ind=TRUE) l2 <- which(is.na(y), arr.ind=TRUE) #> l1 # [,1] [,2] #[1,] 2 1 #[2,] 3 1 #[3,] 4 1 #[4,] 3 3 #[5,] 4 3 #> l2 # row col #[1,] 2 1 #[2,] 3 1 #[3,] 3 3 #[4,] 4 3 #Now I want to find a matrix, which includes the values of l1, without the r...

Hi, How does the requirement that phi instructions have one value per predecessor basic block interact with indirectbr instructions? For instance, take the following code: L1: br i1 %somevalue, label %L2, label %L3 L2: %ret1 = i8* blockaddress(@myfunction, %L5) br label %L4 L3: %ret2 = i8* blockaddress(@myfunction, %L6) br label %L4 L4: %ret = phi i8* [%ret1, L2], [%ret2, L3] indirectbr i8* %ret, [label %L5, label %L6] L5: %myval = phi i32 [0, %L2], [1, %L3] ; are both of these...

Is it even possible or even worth while to do layer 3 switching (bridging) on a Linux system? Or would this be considered routing even though everything is done on OSI Layer 2? Which would be faster, Layer 3 switching (bridging) on OSI Layer 2 or routing on OSI Layer 3? Grant. . . .

On 01/17/2014 04:06 PM, Rom Freiman wrote: > Kashyap, just to be sure - it happens to you during the v2v > conversion? on L2? I haven't done any v2v conversions in L2 (or at any other level). PS: Sorry, I didn't notice my previous 2 emails didn't go to the list, that wasn't intended. Rich, you bounce them here, if you prefer (instead of me clumsily forwarding them). -- /kashyap