search for: l1

...== (note -- w/ core turbo disabled, performance is _very_ stable; variance of < 0.5% run-to-run; figure of merit is "seconds elapsed" here) * Producer / consumer bound to Hyperthread pairs: Performance counter stats for './vring_bench_noshadow 1000000000': 343,425,166,916 L1-dcache-loads 21,393,148 L1-dcache-load-misses # 0.01% of all L1-dcache hits 61,709,640,363 L1-dcache-stores 5,745,690 L1-dcache-store-misses 10,186,932,553 L1-dcache-prefetches 1,491 L1-dcache-prefetch-misses 121.335699344 seconds time elapsed Performance cou...

...== (note -- w/ core turbo disabled, performance is _very_ stable; variance of < 0.5% run-to-run; figure of merit is "seconds elapsed" here) * Producer / consumer bound to Hyperthread pairs: Performance counter stats for './vring_bench_noshadow 1000000000': 343,425,166,916 L1-dcache-loads 21,393,148 L1-dcache-load-misses # 0.01% of all L1-dcache hits 61,709,640,363 L1-dcache-stores 5,745,690 L1-dcache-store-misses 10,186,932,553 L1-dcache-prefetches 1,491 L1-dcache-prefetch-misses 121.335699344 seconds time elapsed Performance cou...

Dear R-users, i have to integrate the following function `fun1` <- function (a, l1, l2) { exp(log(l1) * (a - 1) - l2 * lgamma(a)) } but if l1 is large, i get the "non-finite function value" error, so my idea is to rescale with exp(-l1) `fun2` <- function (a, l1, l2) { exp(log(l1) * (a - 1) - l2 * lgamma(a) - l1) } but it seems this doesn't solve the probl...

...performance is _very_ stable; variance of > < 0.5% run-to-run; figure of merit is "seconds elapsed" here) > > * Producer / consumer bound to Hyperthread pairs: > > Performance counter stats for './vring_bench_noshadow 1000000000': > > 343,425,166,916 L1-dcache-loads > 21,393,148 L1-dcache-load-misses # 0.01% of all L1-dcache hits > 61,709,640,363 L1-dcache-stores > 5,745,690 L1-dcache-store-misses > 10,186,932,553 L1-dcache-prefetches > 1,491 L1-dcache-prefetch-misses > 121.335699344 seconds...

Hi list, I have a very strange problem with my network. I have 2 internet connections: A - 1 Gbit, B - 100Mbps. Network layout: A, B | | [Brd1] / \ [L1] [L2] \ / [ GW1] ................... Clients ..................... Brd1 runs bgpd, and balances the traffic through L1 and L2. L1 and L2 do traffic shaping. GW1 does some packet filtering, and balances the traffic through L1 and L2. Every interface is gigabit. (Realte...

...mer prefetchw/reads. The AMD Optimization guides have specific >> language on this subject, but other platforms may benefit. >> (see Intel #'s below) For core2core case(not HT paire), after consumer reads that M cache line for avail_idx, is that line still in the producer core's L1 data cache with state changing from M->O state? >> >>> Do you have perf data on Intel CPUs? >> Good idea -- I ran some tests on a couple of Intel platforms: >> >> (these are perf data from sample runs; for each I ran many runs, the >> numbers were pretty s...

..._bench, the time required for > > 10,000,000 buffer checkout/returns was reduced by ~2% (average > > across many runs) on an AMD Piledriver (15h) CPU: > > > > (w/o shadowing): > > Performance counter stats for './vring_bench': > > 5,451,082,016 L1-dcache-loads > > ... > > 2.221477739 seconds time elapsed > > > > (w/ shadowing): > > Performance counter stats for './vring_bench': > > 5,405,701,361 L1-dcache-loads > > ... > > 2.168405376 seconds time elap...

..._bench, the time required for > > 10,000,000 buffer checkout/returns was reduced by ~2% (average > > across many runs) on an AMD Piledriver (15h) CPU: > > > > (w/o shadowing): > > Performance counter stats for './vring_bench': > > 5,451,082,016 L1-dcache-loads > > ... > > 2.221477739 seconds time elapsed > > > > (w/ shadowing): > > Performance counter stats for './vring_bench': > > 5,405,701,361 L1-dcache-loads > > ... > > 2.168405376 seconds time elap...

Shamelessly reusing the announcement Arnaud sent about three months ago for nut-2.2.1: "We're preparing to release 2.2.1-pre2, so if you have some fixes to backport on Testing, consider announcing it and doing asap. As always, compatibilities update and bugfixes only!" Regards, Arjen -- Eindhoven - The Netherlands Key fingerprint - 66 4E 03 2C 9D B5 CB 9B 7A FE 7E C1

Dear R-Helpers, I have a list l1 like: l1[[1]] a b c l1[[2]] d l1[[3]] e f I want an output res like: res[[1]] 1 1 1 res[[2]] 2 res[[3]] 3 3 Essentially, I want to replicate each index equal to the number of elements present in that index. Below is what I do to accomplish this: l1 <- list(c("a", "b&quot...

...d be related to xen/mmu: Release just the MFN list, not MFN list and part of pagetables. http://git.kernel.org/?p=linux/kernel/git/konrad/xen.git;a=commit;h=785f62314984ea3af9dd830b020289ba2509ae69 (XEN) Freed 212kB init memory. (XEN) mm.c:908:d0 Error getting mfn 2009b (pfn 5555555555555555) from L1 entry 000000002009b023 for l1e_owner=0, pg_owner=0 (XEN) mm.c:908:d0 Error getting mfn 2009c (pfn 5555555555555555) from L1 entry 000000002009c023 for l1e_owner=0, pg_owner=0 [...] (XEN) mm.c:908:d0 Error getting mfn c32116 (pfn 5555555555555555) from L1 entry 8000000c32116063 for l1e_owner=0, pg_o...

...(20, NA, NA, NA, 50, 19, 32, 101, 10, 22, NA, NA, 80, 49, 61, 190), ncol=4 ) #Whereas x contains all NA?s from y plus some additional NA?s. #I want to find the index of these additional NA?s. I think, there must be a very easy way to do this. #Here are the indices of NA?s in x and y: l1 <- which(is.na(x), arr.ind=TRUE) l2 <- which(is.na(y), arr.ind=TRUE) #> l1 # [,1] [,2] #[1,] 2 1 #[2,] 3 1 #[3,] 4 1 #[4,] 3 3 #[5,] 4 3 #> l2 # row col #[1,] 2 1 #[2,] 3 1 #[3,] 3 3 #[4,] 4 3 #Now I want to find a matrix, which i...

Hi Could anybody explain me how to check how many L1/L2 cache my cpu have. I'm using CentOS 5.6 *cat /proc/cpuinfo |grep CPU * model name : Intel(R) Core(TM)2 Duo CPU T9300 @ 2.50GHz model name : Intel(R) Core(TM)2 Duo CPU T9300 @ 2.50GHz Diagram of a generic dual-core processor, with CPU-local level 1 caches, and a shared, on-die level 2 cac...

...rather than lags. If you notice below, the output is sorted according to lags. >VAR(cbind(fossil,labour),p=2,type="const") VAR Estimation Results: ======================= Estimated coefficients for equation fossil: =========================================== Call: fossil = fossil.l1 + labour.l1 + fossil.l2 + labour.l2 + const fossil.l1 labour.l1 fossil.l2 labour.l2 const 0.4686535 -0.5324335 0.2308964 0.8777865 -0.6711897 Estimated coefficients for equation labour: =========================================== Call: labour = fossil.l1 + labour.l1 + fossil.l2 +...

Hello,? I want to split the dataframe into 1000 groups based on two column values(max value and second max value). First, I made two lists L1 and L2. ?L1 is the list divided into 100 groups based on the range of max value and L2 is divided into 10 groups based on the second max values. Now I want to do the combinations based on L1 and L2. I want to do a for loop for L1 and for each element in L1, I split it into 10 groups based on L2. I...

...y I couldn't be of more help and I hope someone chimes in with the correct solution soon. On Wed, Jan 3, 2018 at 4:48 PM, Son Tuan VU <sontuan.vu119 at gmail.com> wrote: > Hello again, > > After digging a little deeper to this, I guess this is the reason: > > lit.py: /dsk/l1/misc/vusontuan/llvm/projects/libcxxabi/test/lit.cfg:58: > note: Using configuration variant: libcxxabi > lit.py: /dsk/l1/misc/vusontuan/llvm/projects/libcxx/utils/libcxx/test/config.py:297: > note: inferred use_system_cxx_lib as: None > lit.py: /dsk/l1/misc/vusontuan/llvm/projects/libcx...

...itoring via the SNMP driver an APC SmartUPS that has split > phase (2L + neutral) 240V input and 120/120 volt outputs. The data > for the voltages is not what I'm expecting, and I am wondering how I > should interpret it. Wow, that sounds kind of industrial. Model? Is the input an L14-20P? Or equivalent non-twistlock? > Here is an example from upsc: > > input.L1-L2.voltage: 121 > input.L2-L3.voltage: 120 > input.voltage: 121.20 > output.current: 5.90 > output.L1-L2.voltage: 119 > output.L1.current: 5.90 > output.L2-L3.voltage: 119 > output.L2.cur...

Hi, I'm running into a wall when trying to use the integrate function. I have the following setting: powerLaw2 <- function(x,l1,l2,c0,t0) { idx <- which(x <= 0); if (length(idx) > 0) { x[idx] <- 0; } xl <- (-l1+l2)*log(x/t0); L <- log(c0)-l1*log(x)-log(1+exp(xl)); L <- exp(L); return(L); } plCDF2 <- function(x,l1,l2,c0,t0) { print(c(l1,l2,c0,t0)); cdf <- integr...

I have a vector of character strings such as mainnames<-c("CAD","AUD") and another vector say checknames<-c("CAD.l1","AUD.l1","JPY.l1","EUR.l1","CAD.l2","AUD.l2","JPY .l2","EUR.l2") I want a new vector of character strings that is just resultnames<-c("JPY.l1","EUR.l1","JPY.l2","EUR.l2") Because...

Hi R users: I got an error that "l1" is not found. This is a sample code: f1<-function(i,l1){ print(l1[[i]]) l1[[i+1]]<<-i return(i) } z1<-list(x=100,NULL,a=c(1,1)) lapply(1:3,f1,l1=z1) My final goal is to update the value of each list component to use it in the following step. I see that print function fo...