Displaying 10 results from an estimated 10 matches for "kellner".
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keller
2005 Oct 12
2
Wanting to Make a PocketPC have a secure Connection to asterisk server
Does anyone know of a good solution to create a secure (encrypted)
connection from a pocketpc (IPAQ 6515 in my case) to an asterisk server?
Thanks
Peter Kellner
http://PeterKellner.net
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2009 Jul 29
1
lrm-function: Interpretation and error message
...ng
variable(s): Error in est[z$pivot[nvi:(irank + 1)] - kint] :
only 0's may be mixed with negative subscripts
Does anyone know? I suspect that the first question is probably rather
easy for you clever guys but I'm a statistics noob so... looking forward
to your help.
Martin Kellner
2005 May 26
5
Looking for inexpensive phone to use with Asterisk with message light and a button that will let me play new messages
I'm wanting to have a phone at home next to the garage door that when my
bride comes home, she can see that there is a new message, push a button
and have the messages played to her. Otherwise, she will not let me
install asterisk on my home line.
Can someone suggest relatively inexpensive hardware that will do this
for me (us)?
Thanks,
-Peter
2005 Oct 13
0
RE: Wanting to Make a PocketPC have asecureConnection to asterisk server
...h client for PPC in one of my archives
somewhere. Sorry, don't know what its called, where its from, its been
a while since I've needed it. But it does exist.
If that's what you need, I'll take a look for it on the weekend.
Kevin
________________________________
From: Kellner, Peter [mailto:Peter@PeterKellner.net]
Sent: October 12, 2005 11:18 PM
To: asterisk-users@lists.digium.com
Subject: [Asterisk-Users] Wanting to Make a PocketPC have a
secureConnection to asterisk server
Does anyone know of a good solution to create a secure (encrypted)
connection from a pocket...
2005 Mar 29
2
Asterisk@Home 0.7 released Question/Problem
I'm new to this and have tried to find the answer in the discussions and
docs but to no avail. I even read the posting saying the password issue
has already been discussed. So, at he risk of being exiled, here goes.
Question 1: I've installed 0.7 and can log into the asterisk server
from windows by typing http://192.168.1.11 I can log in with wwwadmin
and the password I set myself
2005 Mar 28
2
problem with 1 dialing (recording says must dial 1 when I thought I did)
TRUNKMSD1=1 ; MSD digits to strip
(usually 1 or 0)
TRUNKMSD2=2 ; MSD digits to strip
(usually 1 or 0)
; logn distance calls
exten => _91NXXNXXXXXX,1,NoOp("Dialing: "${TRUNK}/${EXTEN:${TRUNKMSD1}})
exten => _91NXXNXXXXXX,2,Dial(${TRUNK}/${EXTEN:${TRUNKMSD1}})
exten => _91NXXNXXXXXX,3,Congestion
When I dial
2005 Mar 28
13
Asterisk@Home 0.7 released
We had added a lot to this release to our one button
install of Asterisk. Now you can have even more
features automatically installed and configured.
Asterisk 1.0.7
AMP 1-10-007
Flash Operator Panel 0.20
Redesigned WebMeetme
weather agi scripts
Midnight Commander
We have added some of our most requested features.
- Web Meetme is now installed by default and the
meetme2
2005 Mar 29
0
Using @Home 0.7 and wanting to debug dial plan problem
I've finally got @Home .7 up and working. I have a Digium TDM400P with
2 fxo and 2 fxs. All I've done so far after loading is to run
genzaptelconf -s -d ; verified that ztcfg -v shows all 4 ports and
logged into the AMP app and added 1 extension (200) to one of my fxs
ports.
When I pick up either of the phones plugged into the fxs ports and press
the number 2, it immediately rings
2011 Dec 13
0
Define ARMA model
Hi,
is there a way in the arma function to exclude coefficients for the
estimation. For example I estimated an ARMA(2,2) model to data where only
the coefficients of the second order have been significant. Therefore I
would like to estimate the ARMA(2,2) model without the 1,1-coefficients.
Thanks a lot!
Regards,
Ralf
--
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2012 Jul 12
0
Generate random numbers with nested Archimedean Copula
Hi everybody,
I try to simulate random numbers from a trivariate nested Archimedean
copula. My aim is to correlate two processes with, e.g. theta2, as the so
called child pair and then to correlate these two processes with a third one
with theta1 (parent). This "figure" tries to capture what I am explaining
theta1
theta2