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I am a new R user. I trying to install a package all Matching but failed. Here is the error msg. > install.packages("Matching", dependencies=TRUE) Installing package(s) into ?C:/Users/jzhu/Documents/R/win-library/2.13? (as ?lib? is unspecified) --- Please select a CRAN mirror for use in this session --- Warning: unable to access index for repository http://cran.wustl.edu/bin/windows/contrib/2.13 Warning: unable to access index for repository http://www.stats.ox.ac.uk/pub/RWin/bin/win...

Hi all, a newbie question. I''m trying to install lenny guest image (in an img file) on my lenny Dom0 by following the http://wiki.debian.org/Xen: xm create -c xm-debian.cfg install=true install-mirror=ftp://ftp.XX.debian.org/debian i created the xen-lenny-image.img using dd, format is ext3. disk is defined as (cfg file): disk =

Dear all, There is this delcol() function in Splus. It is a support function for drop1.lm(). But it seems it disappears from R. Could some one tell me whether there is any equivalent function of delcol() in R or is there any other way that I can implement its functionality? Your help is highly appreciated!!! Regards, -Ji

Dear all, I know in rpart(), one can control the tree size (i.e. number of terminal nodes) through rpart.control(), e.g. minsplit, minbucket, maxdepth etc. But is there any more direct way to specify the number of terminal nodes when rpart() does the recursive partitioning? Your help is highly appreciated! Regards, -Ji

Dear all, I have a 100 iteration loop. Within each loop, there are some calls to rpart() like: ctl <- rpart.control(maxcompete=0, maxsurrogate=0, maxdepth=10) temp <- rpart(y~., x, w=wt, method="class", parms=list(split="gini"), control=ctl) res <- log(predict.rpart(temp, type="prob")) newres <- log(predict.rpart(temp, newdata=newx,

Dear R users, Is anyone familiar with the "n.iter" argument of the simplex() function (in the boot package)? It seems it doesn't have an effect no matter what value I set it ... I'm trying to solve a linear programming problem and running into the problem of simplex.object$solved = 0 or "A value of 0 indicates that the maximum number of iterations was reached without