search for: ikuzar

Hi, I have to debug my program. When I execute my function (in debug mode), I have got an error but I do not know which line is concerned. I do not want to do an infinite "Browse[2]>n with each line in my function... THanks for your help, ikuzar -- View this message in context: http://r.789695.n4.nabble.com/basic-debugging-tp4371113p4371113.html Sent from the R help mailing list archive at Nabble.com.

...1 v2 v3 1 1 2 3 2 2 3 4 3 3 4 5 > min_vect = min(df) > min_vect [1] 1 I 'd like to get min_vect = (1, 2, 3), where 1 is the min of v1, 2 is the min of v2 and 3 is the min of v3. The example above are very easy but, in real, I have got v1, v2, ... v1440 Thanks for your help, ikuzar -- View this message in context: http://r.789695.n4.nabble.com/how-to-compute-a-vector-of-min-values-tp4536224p4536224.html Sent from the R help mailing list archive at Nabble.com.

Hello, I created a data.frame which contains two columns: df$P (Power) et df$DateTime (time). I'd like to add a new column df$diffP (difference of Power between T and T-2). I made a loop : for (i in 3:length(df$DateTime)){ df$diffP[i] = df$P[i] - df$P[i-2] } execution time result is unaceptable: 24s !! Is there any way to reduce complexity about O(n) ? for example 2 or 3s (10s maxi)

Hi, I 'd like to select the Date where myvalue =1800 appears the* first time*. For instance: df =data.frame(date, myvalue, ...) ... Date myvalue 2012-01-05 2500 2012-01-06 2450 *2012-01-07 1800* 2012-01-08 2200 2012-01-09 1800 I'd like to retrieve the third line. I do

Hi, I 'd like to know how to retrieve a column name of a data frame. For instance : df = data.frame(c1=c('a','b'),c2=c(1,2)) > df c1 c2 1 a 1 2 b 2 I would like to retrieve the column name which value is 2 (here, the column is c2) thanks for your help -- View this message in context:

Hello, RStudio displays errors in french . I'd like to change it in english Please help, Thanks -- View this message in context: http://r.789695.n4.nabble.com/RStudio-how-to-change-language-from-fr-french-to-eng-english-tp4424972p4424972.html Sent from the R help mailing list archive at Nabble.com.

Hi everybody, I want to use macro in my R code. But defmacro was not in my libraries. So I installed it : > install.packages("gtools") Installing package(s) into ?C:/Program Files/R/R-2.13.2/library? (as ?lib? is unspecified) essai de l'URL 'http://cran.cict.fr/bin/windows/contrib/2.13/gtools_2.6.2.zip' Content type 'application/zip' length 102500 bytes (100 Kb)

Hi, Does anybody know why get I this kind of strange situation: Browse[2]> hcEnd [1] "2009-03-29 06:30:00" Browse[2]> class(hcEnd) [1] "POSIXlt" "POSIXt" Browse[2]> is.na(hcEnd) [1] TRUE This issue is the source of my all issues in my program, Thanks for your help -- View this message in context:

Hello, I'd like to know how to plot several curves in the same frame (1curve = 1line=1day). For instance (csv file): 2012-02-01 01:00:00; 2100 2012-02-01 02:00:00; 2200 ... 2012-02-01 23:00:00; 2500 2012-02-02 01:00:00; 1000 2012-02-02 02:00:00; 1500 ... 2012-02-02 23:00:00; 1700 Here, I have to plot 2 curves in the same frame: 1 for 2012-02-01 (on the first line) and 1 for 2012-02-02 (on

Hi, I'd like to know if there is an equivalent for #ifdef (Clangage) in R. I 'd like to do something like: useDebug = defmacro(DEBUG, expr=(DEBUG==1)) if(useDebug(0)){ #Here I do not use debug mode make_addition = function(a, b) { c=a+b plot(c) return(c) } }else{ #here I use debug mode c=a+b } I assume this would work... The problem is : if

Hi, I'd like to plot a point: plot(1,2) I use RStudio. I'd like to know how to specify the length of Oy axis. I 'd like to put 20 as length of Oy but , by default, I 've got 2.5. Thanks for your help -- View this message in context: http://r.789695.n4.nabble.com/how-to-specify-the-Oy-axis-length-tp4372937p4372937.html Sent from the R help mailing list archive at Nabble.com.

Hi, I'd like to debug in a loop (using debug() and browser() etc but not print() ). I'am looking for the first occurence of NA. For instance: tab = c(1:300) tab[250] = NA len = length(tab) for (i in 1:len){ if(i != len){ tab[i] = tab[i]+tab[i+1] } } I do not want to do "Browse[2]> n" for each step ... I'd like to declare a "browser()" in the loop

Hi, I 'd like to know how to extract an interval of "hour:minute" type from a column of POSIXlt POSIXct type. For instance: my_data.csv: 4352;2011-09-02 21:30:00;3242; 4352;2011-09-02 21:31:00;3315; 4352;2011-09-02 21:32:00;4241; 4352;2011-09-02 21:33:00;5394; ... 4352;2011-09-02 01:02:00;67; 4352;2011-09-02 01:03:00;67; 4352;2011-09-02 01:04:00;67; .... I loaded

Hello, I'd like to classify data with kmeans algorithm. In my case, I should get 2 clusters in output. Here is my data colCandInd colCandMed 1 82 2950.5 2 83 1831.5 3 1192 2899.0 4 1193 2103.5 The first cluster is the two first lines the 2nd cluster is the two last lines Here is the code: x = colCandList$colCandInd y = colCandList$colCandMed m = matrix(c(x, y),

Hello, I have got a data frame df like this : > df e1 e2 e3 e4 1 1 11 1 21 2 2 12 2 22 3 3 13 3 23 4 4 14 4 24 5 5 15 5 25 6 6 16 6 26 7 7 17 7 27 8 8 18 8 28 9 9 19 9 29 10 10 20 10 30 where e1 ... e3 are vectors I have to select columns which median is in the interval [5;6] ( Here, for instance, e1 and e3) I would not want to use loop... (for, while) I search

Hello, I 'd like to use some functions in myLib. So I do: library(myLib) Then I get this message: Error: package 'myLib' is not installed for 'arch=i386' > sessionInfo() R version 2.13.2 (2011-09-30) Platform: i386-pc-mingw32/i386 (32-bit) locale: [1] LC_COLLATE=French_France.1252 LC_CTYPE=French_France.1252 LC_MONETARY=French_France.1252 LC_NUMERIC=C

I have data that looks like this: > df1 group id 1 red A 2 red B 3 red C 4 blue D 5 blue E 6 blue F I want a list of the groups containing vectors with the ids. I am avoiding subset(), as it is only recommended for interactive use. Here's what I have so far: df1 <- data.frame(group=c("red", "red", "red", "blue",