Displaying 20 results from an estimated 358 matches for "hypothese".
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hypotheses
2008 Nov 21
2
Growth rate determination using ANCOVA
I'm a programmer in a biology lab who is starting to use R to automate
some of our statistical analysis of growth rate determination. But I'm
running into some problems as I re-code.
1) Hypotheses concerning Slope similarity/difference:
I'm using R's anova(lm()) methods to analyse a model which looks
like this:
growth.metric ~ time * test.tube
I understand that testing the the interaction between time and tube
(time:test.tube) will tell us if the growth rates (fo...
2011 Mar 01
1
glht() used with coxph()
...coef exp(coef) se(coef) z p
treatmentpyridoxine -0.063 0.939 0.161 -0.391 0.70
treatmentthiotepa -0.159 0.853 0.168 -0.947 0.34
Likelihood ratio test=0.91 on 2 df, p=0.635 n= 294
> glht(fit,linfct=mcp(treatment='Tukey'))
General Linear Hypotheses
Multiple Comparisons of Means: Tukey Contrasts
Linear Hypotheses:
Estimate
pyridoxine - placebo == 0 -0.06303
thiotepa - placebo == 0 -0.15885
thiotepa - pyridoxine == 0 -0.09582
However, once I added a strata term in the formula of coxph(), then glht() can't...
2008 Jul 15
2
sem & testing multiple hypotheses with BIC
I'm coming from the AMOS world and am wondering if there is a simple
way to do multiple hypothesis testing in the manner of BIC analyses in
AMOS using the sem package in R. I've read the documentation, but
don't see anything in there except for basic BIC scores. Perhaps
someone has devised a simple way to compare the relative likelihood of
all possible path-fittings within a
2006 Aug 26
5
Type II and III sum of square in Anova (R, car package)
Hello everybody,
I have some questions on ANOVA in general and on ANOVA in R particularly.
I am not Statistician, therefore I would be very appreciated if you answer
it in a simple way.
1. First of all, more general question. Standard anova() function for lm()
or aov() models in R implements Type I sum of squares (sequential), which
is not well suited for unbalanced ANOVA. Therefore it is better
2006 Mar 13
0
wishlist: function mlh.mlm to test multivariate linear hypotheses of the form: LBT'=0 (PR#8680)
Full_Name: Yves Rosseel
Version: 2.2.1
OS:
Submission from: (NULL) (157.193.116.152)
The code below sketches a possible implementation of a function 'mlh.mlm' which
I think would be a good complement to the 'anova.mlm' function in the stats
package. It tests a single linear hypothesis of the form H_0: LBT'= 0 where B is
the matrix of regression coefficients; L is a matrix
2007 Jun 10
1
{nlme} Multilevel estimation heteroscedasticity
Dear All,
I'm trying to model heteroscedasticity using a multilevel model. To
do so, I make use of the nlme package and the weigths-parameter.
Let's say that I hypothesize that the exam score of students
(normexam) is influenced by their score on a standardized LR test
(standLRT). Students are of course nested in "schools". These
variables are contained in the
2024 Aug 07
1
Manually calculating values from aov() result
...results. (I slightly
regret using the "type-*" terminology for car::Anova() because of the
lack of exact correspondence to SAS.) The standard R anova() function
computes type-I (sequential) SSs.
The focus, however, shouldn't be on the SSs, or how they're computed,
but on the hypotheses that are tested. Briefly, the hypotheses for
type-I tests assume that all terms later in the sequence are 0 in the
population; type-II tests assume that interactions to which main effects
are marginal (and higher-order interactions to which lower-order
interactions are marginal) are 0. Type-II...
2004 Mar 23
4
statistical significance test for cluster agreement
I was wondering, whether there is a way to have
statistical significance test for cluster agreement.
I know that I can use classAgreement() function to get
Rand index, which will give me some indication whether
the clusters agree or not, but it would be interesting
to have a formal test.
Thanks.
2007 Jun 16
1
linear hypothesis test in gls model
Dear all,
For analysis of a longitudinal data set with fixed measurement in time I built a gls model (nlme). For testing hypotheses in this model I used the linear.hypothesis function from the car package. A check with the results obtained in SAS proc MIXED with a repeated statement revealed an inconsistency in the results. The problem can be that the linear.hypothesis function (1) only gives the asymptotic chi square test and...
2008 Sep 09
2
test for a single variance
Dear R Gurus:
Is there a test for a single variance available in R, please?
Thanks,
Edna Bell
2017 Oct 10
2
Power test binominal GLM model
...ative difference
in the redemption rate between control group and test groups. Now, applying
the post hoc test:
> Treat.comp<-glht(mod.binposthoc,mcp(bono_recibido='Tukey'))> summary(Treat.comp) # el modelo se encuentra en log odds aqui
Simultaneous Tests for General Linear Hypotheses
Multiple Comparisons of Means: Tukey Contrasts
Fit: glm(formula = TRAN_DURING_CAMP_FLG ~ bono_recibido, family = "binomial",
data = exp2)
Linear Hypotheses:
Estimate Std. Error z value Pr(>|z|)
BONO3EUROS - benchmark == 0 -0.87277 0.09931 -8.788...
2009 Apr 23
3
Interpreting the results of Friedman test
...the results of a Friedman test. It seems
to me that the p-value resulting from a Friedman test and with it the
"significance" has to be interpreted in another way than the p-value
resulting from e.g. ANOVA?
Let me describe the problem with some detail: I'm testing a lot of
different hypotheses in my observer study and only for some the
premises for performing an ANOVA are fulfilled (tested with Shapiro
Wilk and Bartlett). For the others I perform a Friedman test.
To my surprise, the p-value of the Friedman test is < 0.05 for all my
tested hypotheses. Thus, I tried to "compare&q...
2011 Apr 03
2
Unbalanced Anova: What is the best approach?
I have a three-way unbalanced ANOVA that I need to calculate (fixed effects
plus interactions, no random effects). But word has it that aov() is good
only for balanced designs. I have seen a number of different recommendations
for working with unbalanced designs, but they seem to differ widely (car,
nlme, lme4, etc.). So I would like to know what is the best or most usual
way to go about working
2011 Dec 11
2
multiple comparison of interaction of ANCOVA
...woing:
> library(HH)
> mca.1993 <- mcalinfct(mydata.aov, "Trt")
> non.zero <- mca.1993[,5:6] != 0
> mca.1993[,5:6][non.zero] <- 1993 * sign(mca.1993[,5:6][non.zero])
> summary(glht(mydata.aov, linfct=mca.1993))
Simultaneous Tests for General Linear Hypotheses
Fit: aov(formula = y ~ Trt * year, data = mydata)
Linear Hypotheses:
Estimate Std. Error t value Pr(>|t|)
B - A == 0 2.8779 0.5801 4.961 0.00215 **
C - A == 0 -2.8845 0.5801 -4.972 0.00191 **
C - B == 0 -5.7624 0.5801 -9.933 < 0.001 ***
---
Signif. codes:...
2004 Aug 02
3
logistic regression
I have a system with a binary response variable that was hypothesized to
follow a simple logistic function. The relationship between the continuous
independent variable and the logit is clearly not monotonic. I have two
questions. 1) Can anyone recommend a reference that describes my modeling
options in this case, and 2) what facilities does R have to deal with this
situation?
Thanks,
Kevin
2018 Mar 22
1
adjusted values
...c tests (z-statistics):
> ph_conditional <- c("des_days1 = 0",
"des_days14 = 0",
"des_days48 = 0");
> lev.ph <- glht(lev.lm, linfct = ph_conditional);
> summary(lev.ph)
Simultaneous Tests for General Linear Hypotheses
Fit: lme.formula(fixed = data ~ des_days, data = data_red_trf, random
= ~des_days |
ratID, method = "ML", na.action = na.omit, control = lCtr)
Linear Hypotheses:
Estimate Std. Error z value Pr(>|z|)
des_days1 == 0 -0.002632 0.007428 -0.354 0.971
des_days1...
2012 Feb 19
1
Basic Model Setup Question from a Beginner
Hello all! I would like to start off by saying that I am still really new to
the vast world of R so please excuse my very limited vocabulary in the
program.
I have collected data from monkey videos and would like to setup some
model(s) in R that can help with my hypotheses. I am having trouble figuring
out which statistical tests/models to use for my two hypotheses.
#1: Comparing the presence of an observer (a categorical variable consisting
of either Approaching/Near, Near or On Top of Cage) to the presence of
aggressive behavior (again categorical variables cons...
2010 Feb 10
1
heplot3d / rgl : example causes R GUI to crash
...#39;R for Windows GUI encountered a problem and needs to close...'). I
think the problem comes from an
rgl call, but, I can't get a traceback or other information because my R
session crashes. I've never seen this
behavior before.
The problem occurs *whenever* I try to supply linear hypotheses to be
displayed along with the model
terms. Here is a small example:
library(heplots)
# Soils data, from car package
soils.mod <- lm(cbind(pH,N,Dens,P,Ca,Mg,K,Na,Conduc) ~ Block +
Contour*Depth, data=Soils)
Anova(soils.mod)
heplot(soils.mod, variables=c("Ca", "Mg"))
## t...
2012 Nov 07
1
A warning message in glht
...is warning is smth
that I should ignore or not. And if not, what I should do about it (I kind
of know how to deal with this problem for categorical factors, however, in
my data, one of the factors (AveScore) is continuous).
Thanks a lot!
Yuliia
Simultaneous Tests for General Linear Hypotheses
Multiple Comparisons of Means: Tukey Contrasts
Fit: glm(formula = EW1 ~ AveScore + Speaker + File + factor(Bplace) +
factor(Sex) + AveScore:File, family = binomial(link = "logit"),
data = data.0)
Linear Hypotheses:
Estimate Std. Error z value Pr(>|z|)
In -...
2012 Feb 12
2
ANCOVA post-hoc test
...a post hoc test with glht() to find out between which samplings:
>summary(glht(mod, linfct=mcp(sampling="Tukey")))
The results seem to say that there are no significantly different slopes for any of the pair-wise comparisons of factor levels:
Simultaneous Tests for General Linear Hypotheses
Multiple Comparisons of Means: Tukey Contrasts
Fit: aov(formula = h ~ sampling * dist, data = data)
Linear Hypotheses:
Estimate Std. Error z value Pr(>|z|)
sp - au == 0 0.06696 0.04562 1.468 0.457
su - au == 0 -0.02238 0.04562 -0.491 0.961
wi - au == 0 0.01203...