search for: hotz

...user-friendly fashion. Try library(stepR) example(smuceR) # for [1] and [2] example(jsmurf) # for [3] example(stepsel) # for [4] to get an idea about what it can do, and how to use it. We hope it proves useful; community feedback is therefore very welcome! Best regards Thomas Hotz TU Ilmenau, Institute of Mathematics References: [1] Frick, K., Munk, A., and Sieling, H. (2014). Multiscale Change-Point Inference. With discussion and rejoinder by the authors. Journal of the Royal Statistical Society, Series B, 76(3), 495-580. [2] Futschik, A., Hotz, T., Munk, A. Sieling, H....

...user-friendly fashion. Try library(stepR) example(smuceR) # for [1] and [2] example(jsmurf) # for [3] example(stepsel) # for [4] to get an idea about what it can do, and how to use it. We hope it proves useful; community feedback is therefore very welcome! Best regards Thomas Hotz TU Ilmenau, Institute of Mathematics References: [1] Frick, K., Munk, A., and Sieling, H. (2014). Multiscale Change-Point Inference. With discussion and rejoinder by the authors. Journal of the Royal Statistical Society, Series B, 76(3), 495-580. [2] Futschik, A., Hotz, T., Munk, A. Sieling, H....

http://bugzilla.mindrot.org/show_bug.cgi?id=1242 hotz at jpl.nasa.gov changed: What |Removed |Added ---------------------------------------------------------------------------- CC| |hotz at jpl.nasa.gov ------- Comment #2 from hotz at jpl.nasa.gov 2006-11-10 06:20 ----...

...I thought of using my named routes instead of specifying the path as a string. That worked up until the point when I reached: When "creating a new topic titled", "Nicks Mom" do |title| post topics(@forum, ??? ), :topic => { :title => title, :body => "She is teh hotZ!" } end The problem was since its a nested routed I couldn''t complete the post request without specifying the topic_id. But since the topic hasn''t been created yet their is no way (that I know of) to pass the id since I don''t know what it will be. I would think the...

Hi, I was trying to draw an empirical distribution function with uniform confidence bands. So I tried to find a way to calculate values of the Kolmogorov-Smirnov Distribution but failed. I guess it must be hidden somewhere (since the ks-test is implemented), but I was unable to find it. Is there any way to do this? Thanks Leif Boysen

...ction(ev) { cmd <- ev$getActionCommand() if(cmd == "Reset") reset() else { print(compute()) } NULL } <environment: 013B8AC4> $className character(0) $targetClasses character(0) attr(,"class") [1] "AnonymousRReference" --- Thomas Hotz Research Associate in Medical Statistics University of Leicester United Kingdom Department of Epidemiology and Public Health 22-28 Princess Road West Leicester LE1 6TP Tel +44 116 252-5410 Fax +44 116 252-5423 Division of Medicine for the Elderly Department of Medicine The Glenfield Hospital Leic...

...= nplots) 1: xyplot(y ~ x | my.shingle, data = my.data, as.table = T, scales = list(x = list(relation = "sliced")), layout = c(1, 4)) --- P.S. Allow me to take the opportunity to give big thanks to Deepayan Sarkar for writing and maintaining this brilliant package! --- Thomas Hotz Research Associate in Medical Statistics University of Leicester United Kingdom Department of Epidemiology and Public Health 22-28 Princess Road West Leicester LE1 6TP Tel +44 116 252-5410 Fax +44 116 252-5423 Division of Medicine for the Elderly Department of Medicine The Glenfield Hospital Leic...

Hi I have two lots of numbers which I would like to histogram using the hist() function. For comparative reasons, I want them to be on the same scale, which I can use the xlim and ylim options to achieve. However, having them on the same scale is meaningless unless they have the same "breaks". Consulting the documentation, there are 4 ways of defining the number of breaks, only one

Hi R lovers 2 questions: 1) I'd like to know how to clean the title, the sub title or the labels of a graph. I know how to redefine it with the function title() but it overwrites the previous title and do not replace it 2) How could I clear a whole plot (for example in a multiple figure environment) thanks for your help vincent

Dear list, I would like to study the dynamics of functions using R (instead of mathematica e.g.), i.e. the behavior of points under iteration of a function. So I tried (in vain) writing a function myfunction <- function(f,n,x){...} in order to compute f^{n}(x), f^{n}(x) being the function f composed with itself n-1 times. n is a natural number, and the argument x is the abscissa of the point I

..._ platform i386-pc-mingw32 arch i386 os mingw32 system i386, mingw32 status major 1 minor 7.1 year 2003 month 06 day 16 language R --- Thomas Hotz Research Associate in Medical Statistics University of Leicester United Kingdom Department of Epidemiology and Public Health 22-28 Princess Road West Leicester LE1 6TP Tel +44 116 252-5410 Fax +44 116 252-5423 Division of Medicine for the Elderly Department of Medicine The Glenfield Hospital Leic...

R1.7.0, Win2k: When I use plot( ) on a groupedData object, if I have 165 subjects I'm supposed to be able to use plot(..., layout = c(5,3,11)) to get all 165 on 11 separate sheets. The graphics window is only displaying the first 10. If I use plot(..., layout = c(5,3,12)) I get the appropriate 11 sheets. Furthermore, yesterday I noticed that when using plot( <linear model object> )

Hello, I have a question about using the layout command within a function. I've written function that uses layout to create a figure from 2 plots. This works fine to create a figure. When I use par(mfrow = c(2,2)) to create multiple plots, it seems that the layout command resets the mfrow parmeter. Is there a way for me to avoid this problem? For example practice<- function() {

Hello all, I'm a new member in this list and, also, a new R user and need some information about Resistant Smooth (using medians). The method I need of Resistant Smooth is the 4253H one and I didn't found how to perform that in R. Does anybody have an idea? Thanks, Henrique.

Dear R help, I'm pretty new to R and would be grateful for help. I have 11 data.frames, each with 3 columns of data. Each has the same row.names, however these are not sorted. Please tell me the best way to sort these (by row.names) and secondly the best way to extract data columns from these to form a merged table. Thanks a million Aedin

...an)? > > Maybe there is no way to figure it out, and just > wanna get some help and try it. > > Fred > > ______________________________________________ > R-help at stat.math.ethz.ch mailing list > https://www.stat.math.ethz.ch/mailman/listinfo/r-help > --- Thomas Hotz Research Associate in Medical Statistics University of Leicester United Kingdom Department of Epidemiology and Public Health 22-28 Princess Road West Leicester LE1 6TP Tel +44 116 252-5410 Fax +44 116 252-5423 Division of Medicine for the Elderly Department of Medicine The Glenfield Hospital Leic...

Dear All, I've been trying to format a plot output using par() with mfrow, fin, mai, etc and basically it's proving to be a pain. I searched on google and found that Paul Murrell had written a grid Graphics program which seems perfect. However, when I try and use say viewport() I just get a function not found error. Can someone tell me what I'm doing wrong please? Thank-you

Dear R Users, I suppose this is a school boy question, but here it is anyway. I'm trying to re-create the residuals for a poisson GLM with simulated data; x<-rpois(1000,5) model<-glm(x~1,poisson) my.resids<-(log(x)- summary(model)$coefficients[1]) plot(my.resids,residuals(model)) This shows that my calculated residuals (my.resids) are not the same as residuals(model). p 65 of

Hi R lovers! I have discovered recently that graph can be exported from R in a Latex compatible file thanks to the pictex command I would like to know if there is the equivalent while exporting datas. Let's say I have a matrix, a data.frame or a list that I would like to export as a flat text file that is immediatly transcripted into a table into latex Is there a macro or package that could

Undoubtedly a simple question: I've looked at order() and sort() in the help pages for R1.7.1. It doesn't appear that these functions are immediately suited to doing the same thing as PROC SORT DATA = BLAH; BY X Y Z; RUN; in SAS. I have also checked Frank Harrell's Hmisc library. Could someone point me in the right direction so I can sort by the levels of Z within the levels of