Displaying 9 results from an estimated 9 matches for "grouper".
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2003 Aug 20
2
samba-3.0rc1 Can access PDC but not others
...o
domain all run smoothly). I then joined the samba machine to the domain,
and now I can browse and use shares on the PDC just fine. However, when
I try to access or browse the NT fileservers I get
NT_STATUS_LOGON_FAILURE. What gives? Here is an example (the samba
machine is RUSTBUCKET, PDC is GROUPER, servers are XPCL and WIN2KCLIENT,
domain is TNG-PDC-TEST1):
[root@rustbucket linux-2.4]# smbclient -N -L grouper
Anonymous login successful
Sharename Type Comment
--------- ---- -------
Error returning browse list: NT_STATUS_ACCESS_DENIED
Anonymous login...
2011 Mar 30
0
offset in gam
Hi, we are modelling dusky grouper distribution using underwater visual
census. Our response variable is the abundance of groupers but we want to
see differences in habitat related to maturity because dusky groupers use
different habitats when they're juveniles versus adults. So we're using the
% of maturity.
ie 1 individua...
2010 May 19
3
offset in gam and spatial scale of variables
Hi,
We are analizing the relationship between the abundance of groupers in line
transects and some variables. We are using the quasipoisson distribution. Do
we need to include the length of the transects as an offset if they all have
the same length??
Also, can we include in the gam models variables that are measured at
different spatial scales? We have done an anal...
2010 Mar 10
3
Help with aggregate and cor
...rked for mean and sum, but not cor.
In desperation, I tried looping over the different 5 minute levels and
computing cor, but I'm so R-clueless I couldn't even figure out how to
assign to a variable inside of that loop!
code such as
for (f in fivemin){
output[f] <- cor(df[grouper==f,]); }
failed, as I couldn't figure out how to initialize output so that
output[f] would accept the output of cor.
Any help or steering towards the proper R-way would be appreciated.
Regards,
James Marca
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2004 Nov 11
5
wrong answer for simple expressions
I am experiencing strange (to me) output when trying to do simple
calculations. Expressions that should equal zero yield non-zero
values.
Examples:
> a <- 4.1-3.1
> b <- 5.1-4.1
> a-b
[1] -4.440892e-16
> (4.1-3.1)-(5.1-4.1)
[1] -4.440892e-16
When this last expression is expanded, I get the right answer:
> 4.1-3.1-5.1+4.1
[1] 0
I am using the binary packaged version
2006 Dec 23
1
Question regarding window output extents
Hi,
in a plugin I am developing with some other people (namely: tabbed
window grouper), we want to paint a glow like effect around the windows.
This is done by adding the glow as "second decoration" around the window
decoration.
The question now is: How can we communicate the fact that there is a
second set of decoration properly to other plugins so that window
damaging an...
2006 Jun 27
1
Post this please
Post the following please. Thanks!
Voxura, an internet video sharing startup, is looking for a skilled and
motivated Web User Interface Developer to work with us in building our video
sharing products and features. You will work with a strong, creative team
building features used by people every day.
Our team is looking for a Web User Interface Developer with in-depth
knowledge of web
2005 Jun 22
2
Trouble with ifelse and if statement (PR#7962)
Full_Name: Woolton Lee
Version: 2.1
OS: windows
Submission from: (NULL) (128.118.224.46)
I did the following ('g' and 'h' are both numeric vectors)
> i <- abs(g-h)
creating a vector 'i' with values,
> i
[1] 0.08 0.00 0.33 0.00 0.00 0.00 0.00 0.33 0.00 0.00 0.08 0.08 0.20 0.00 0.13
Now, I want to create a new vector =1 whenever 'i' = 0.33 and =0
2003 Jul 14
6
bug?
Dear R programmers,
is there a sensible explanation for the following behaviour? The second
command seems not to be interpreted correctly.
> seq(0.6, 0.9, by=0.1) == 0.8
[1] FALSE FALSE TRUE FALSE
> seq(0.7, 0.9, by=0.1) == 0.8
[1] FALSE FALSE FALSE
> c(0.7, 0.8, 0.9) == 0.8
[1] FALSE TRUE FALSE
> seq(0.9, 0.7, by=-0.1) == 0.8
[1] FALSE TRUE FALSE
I am running R version 1.7.1 on