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...s. group 4. A more complicated comparison would be time B in group 3 of group L with B in group 4 of group L. I normally subset each group with the following type of code. data=read(...) #L v D L=data[LvD %in% c("L"),] D=data[LvD %in% c("D"),] #Groups 3 and 4 within L and D group3L=L[group %in% c("3"),] group4L=L[group %in% c("3"),] group3D=D[group %in% c("3"),] group4D=D[group %in% c("3"),] #Times B, S45, FR2, FR8 you get the idea Is there a more efficient way to subset groups? Thanks for any insight. Regards, Charles [[alterna...