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...lids Cell phones 0 0 7 193 Plastic lids Canned goods 0 0 7 197 Plastic lids Hand/dish towel 3 0 12 Thank you. Greg Blevins The Market Solutions Group Windows xp, 2.1.1 Gregory L. Blevins Vice President, Partner The Market Solutions Group, Inc. gblevins at marketsolutionsgroup.com Office phone: 612 392-3163 Cell phone: 612 251-0232 "What is at the beginning but a small error, swells to huge proportions at the close." Aristotle

...if (a == 2 || b == 2) return(2) + if (a == 3 || b == 3) return(3) + if (a == 4 || b == 4) return(4) + NA + } > mapply(decision, qs2, qs9) [1] 2 1 1 3 4 3 1 1 1 4 1 2 3 1 4 3 1 2 2 3 Hope this is what you want. Andy > -----Original Message----- > From: Greg Blevins [mailto:gblevins at mn.rr.com] > Sent: Monday, October 06, 2003 11:21 PM > To: R-Help > Subject: [R] Problem getting an ifelse statment to work > > > Hello R experts, > > I trust I have a simple request. I have a dataframe which > among its contents are two variables, qs2 and qs9,...

Hello, R 2.3.0 Windows XP I have spent quite a bit of time trying to resolve my problem below, which included a R site search. The "vertical bars" syntax below produces a vertical bar chart with the values displayed above each bar. I want to cast this graphic horizontally, but I have not been able to arrive at a suitable outcome. The best I have been able to do, using the second block

I have been wrestling with this function for quite a while, and am not making headway. 1) I want to apply a function to the following columns of a dataframe: myfunction. <- apply(ph5028[,c(83:107)],2,function(x) ... 2) Within each of the above columns there is a single numeric code, 1, 2 or 3 or an NA. 3) My goal is to determine the percent of time each person used a 2 code. So if a person

Hello, I have spent considerable time trying to figure out that which I am about to describe. This included searching Help, consulting my various R books, and trail and (always) error. I have been assuming I would need to use a loop (looping over columns) but perhaps and apply function would do the trick. I have unsuccessfully tried both. A scaled down version of my situation is as follows:

I will be involved with an analysis based on a file that will be roughly 25 meg. Assuming I have enough memory, is their any limitations to using R on a file this large. Thank you, Gregory L. Blevins Vice President, Partner The Market Solutions Group, Inc. gblevins at marketsolutionsgroup.com Office phone: 612 392-3163 Cell phone: 612 251-0232

Hello, In the Hmisc package, functions describe and summarize can explicitly take a weight variable. My question is can a weight variable be applied when using 'summary'? For example, using...summary(var1 ~ var2) I would like to weight the data by var 3 (same length). Is this possible? Thanks a lot. Greg Blevins The Market Solutions Group, Inc.

Hello R masters, This request is being made after searching through archive mailing list. I have a "many" table in a medical application where each injury a person suffers is recorded as a separate row. In my toy example below it means respondent #1 had three injuries and so on. If x2 equal 2 then I want to delete all the rows for that person from the dataframe--see Before and After

Full_Name: Gregory L. Blevins Version: 1.8 OS: Windows 2000 Submission from: (NULL) (65.29.54.28) I see this when I open 1.8 Error in grep("united.states", Sys.getlocale("LC_CTYPE"), TRUE) : 5 arguments passed to "grep" which requires 6. R : Copyright 2003, The R Development Core Team Version 1.8.0 alpha (2003-09-18) R is free software and comes with

Dear R Masters, I have searched high and low (the help archives and my various R reference material and help files) for a solution to what appears to me to be quite a simple problem. In the following syntax, variable n10 has three levels. I would like the symbols that appear in the graph for these three levels to be different colors. The best I have been able to do is to have the Key display

Hello R experts, The following problem outstrips my current programming knowledge. I have a dataframe with two fields that looks like the following: ID Contract 01 1 01 1 02 2 02 3 02 1 03 2 03 2 03 2 03 1 03 1 03 1 etc... I would like to end up with a dataframe with one row per ID where the value in the contract field would be the

Hello, I have a data frame that has three fields. Resp# ActCode ProdUsed 100 3 2 100 3 2 100 4 3 100 4 3 101 3 6 102 2 1 102 3 1 103 5 1 103 5 1 103

Hello R experts I am using Hmisc aregImpute and Impute (following example on page 105 of The Hmisc and Design Libraries). *My end goal is to have NAs physically replaced in my dataframe. I have read the help pages and example in above sited pdf file, but to no avail. Here is example of what I did. Ph, my data frame, is attached. > xt <- aregImpute (~ q5 + q22rev02 + q28a, n.impute=10,

Hello R users, I am having difficulting getting multcomp to run. I have a dataframe attached with a numeric variable q12a and a numeric variable quota (which is really a classification variable). quota has 10 levels and unequal sample sizes. a12a has some missing data. I am interested in doing pairwise testing across the 10 quota groups on q12a. Using the ctest package the following code

Hello, I am inputing a 17 x 17 symetric matrix to sammon. The matrix is a co-occurance matrix with no missing data. If this is at all relevant, running hclust on this matrix works. > samx <- sammon(q23axproduct) I receive the following error: Error in sammon(q23axproduct) : initial configuration must be complete In addition: Warning messages: 1: some of the first 2 eigenvalues are

Hello list, I have the following function which, as you can see, uses mean: meanratings <- round(apply(stack03[,c(102:121)],2,function(x) (tapply(x ,actcode, mean, na.rm=T))), digits=1) The above function yields the following output: q27a q27b q27c q27d q27e q27f q27g q27h q27i q27j q27k q27l q27m q27o q27p 1 7.8 8.1 7.7 7.9 7.9 NaN NaN 8.4 7.8 7.0 7.6 NaN NaN 7.1 6.0 2

Hello, I am running R 2.1.0 on Windows 2000. When I attempt to install or update packages, regardless of whether I use the menu or command line, I get the following error. > utils:::chooseCRANmirror() > utils:::menuInstallPkgs() Warning message: unable to connect to 'cran.cnr.Berkeley.edu' on port 80. Warning: unable to access index for repository

Hello, I have struggled, for longer than I care to admit, with this seemingly simple problem, but I cannot find a solution other than the use of long drawn out ifelse statements. I know there has to be a better way. Here is stripped down version of the situation: I start with: a <- c(1,0,1,0,0,0,0) b <- c(1,1,1,1,0,0,0) c <- c(1,1,0,1,0,0,0) rbind(a,b,c) [,1] [,2] [,3] [,4] [,5]

Hello, I have a df, pp, with five variables: > nobs(pp) q10_1 q10_2 q10_3 q10_4 actcode 1620 1620 1620 1620 1620 I want to create a loop to run four xtabs (the first four variables above by the fifth) and then store the results in a matrix. Below I make my intent clear by showing the output of one xtab which is inserted into a matrix. > a <- xtabs(q10_1 ~

Hello R folks. 1) The question that generated the data, which I call Qx: Which of the following 5 items have you performed in the past month? (multipe response) 2) How the data is coded in my current dataframe: The first item that a person selected is coded under a field called Qxfirst; the second selected under Qxsecond, etc. For the first Person, the NAs mean that that person only selected