Displaying 14 results from an estimated 14 matches for "freeni".
Did you mean:
freenx
2009 Nov 28
1
Include manually an intercept in lm without breaking it?
Hi
Say I want to add manually an intercept in the function lm. Even if
almost all results will be identical, few stats are different as DF
counting will be different as intercept will not be included in
"automatic" case, while it will be in "manual" case. See:
###usual lm on freeny
fr<-lm(freeny.y~freeny.x)
###manual lm on freeny
man<-cbind(1,freeny.x)
2018 Mar 05
1
model.frame strips class as promised, but fails to strip OBJECT in C
Full thread here:
https://github.com/tidyverse/broom/issues/287
Reproducible example:
is.object(freeny$y)
# [1] TRUE
attr(freeny$y, 'class')
# [1] "ts"
class(freeny$y)
# [1] "ts"
# ts attribute wiped by model.frame
class(model.frame(y ~ ., data = freeny)$y)
# [1] "numeric"
attr(model.frame(y ~ ., data = freeny)$y, 'class')
# NULL
# but still:
2009 Nov 29
1
lm: eval(parse(text=)) works on one side y/x but not on both?
Hi
My goal is to do a (multiple) regression, just knowing that my Y
variables will be the say k first variables of a matrix/data frame. I
thought I should do it with eval(parse)) but encounter a strange problem.
See:
lm(y~.-y, data=freeny) #that's what I want to do in the one equation case
#Problem is I don't know name of the variable... only that it is the
first one...
#so idea is to
2008 Mar 03
1
How to include an externally defined NULL value in lm
Hello!
I would love to be able to include an external variable to a lm call, I
mean something:
if(TRUE)
a<-freeny.x[,4]
else
a<-NULL
lm(freeny.y~freeny.x[,-4] +a)
but it does not work with a<-NULL, whereas
lm(freeny.y~freeny.x[,-4] +NULL)
I don't understand why and did not find an answer in the manuals... do
you see it? Any idea?
Thanks!!
2012 Mar 29
2
What is 'freeny.x' object?
Dear all, I have discovered an object named 'freeny.x' which seems
in-built. Can somebody tell me why it is there and what purpose it is
serving?
'ls()' syntax does not seem to catch this object in the environment.
Thanks,
1999 Feb 18
1
model.frame mangles time series (PR#121)
This one showed up while looking at one of Ripley's other reports:
> data(freeny)
> model.frame(y~1,data=freeny,subset=1:10)
y
1962.25 8.79236
1962.5 8.79137
1962.75 8.81486
1963 8.81301
1963.25 8.90751
1963.5 8.93673
1963.75 8.96161
1964 8.96044
1964.25 9.00868
1964.5 9.03049
> model.frame(y~1,data=freeny,subset=1:10)$y
Warning: Replacement length not a
1998 Aug 22
0
Handling of offsets in glm is really inconsistent.
[Copied to R-devel for information]
This applies to all versions of R I have: 0.62.2, 0.62.3, 0.63.
Great care seems needed with glms with offsets, as many things seem
wrong.
Consider the following:
> data(freeny)
> freeny.glm <- glm(y ~ offset(lag.quarterly.revenue) + price.index +
income.level + market.potential, data=freeny, subset=1:30)
> predict(freeny.glm)
Qtr1
2009 Nov 29
4
lm() notation question
Hi,
A recent thread provided a (working) construct for lm:
lm(as.matrix(freeny[ix]) ~., freeny[-ix])
Can someone explain what is meant by the formula in that expression,
that is, what does "mymatrix~." do? I couldn't find any such example
in the lm() or formula() help pages.
thanks
Carl
2005 Feb 02
4
(no subject)
can you recommend a good manual for R that starts with a data set and gives
demonstrations on what can be done using R? I downloadedR Langauage
definition and An introduction to R but haven't found them overly useful.
I'd really like to be able to follow some tutorials using a dataset or many
datasets. The datasets I have available on R are
Data sets in package 'datasets':
2009 Sep 13
1
Help with Loop Please!
Hi,
I’d like to fit one GLM model for each possible combination of inputs (i.e.
exhaustive search). The package leaps can help me to generate all possible
variable subsets, but I’ll appreciate your guidance as of how to generate
one model for each of those possible subsets. I’m new in R! Thanks in
advance for your help.
library(leaps)
subsets <- regsubsets( y ~ . , data=freeny, nbest=100,
2010 Sep 04
1
tail.matrix returns matrix, while tail.mts return vector
Hi
I have a few problems with tail/head when applied to multiple time
series. I'm not sure as whether I did not understand the function or
whether it correspond to an unexpected behavior.
When head(a,n) is applied on data.frame or matrix, it returns a
data-frame or matrix with first n obs of *each* variable. When applied
to a mts object, it returns first n obs of *first* variable only,
2008 May 09
0
Incorrect fix for PR#9316: Cook's Distance & plot.lm
Bug PR#9316 noted an inconsistency between the Cook's distance contours
on plot.lm(x, which = 5) and the values given by cooks.distance(x) -- as
shown in plot.lm(x, which = 4) -- for glms:
http://bugs.r-project.org/cgi-bin/R/Analyses-fixed?id=9316;user=guest;selectid=9316
The suggested fix was to modify the contour levels by a dispersion
factor, implemented as follows:
dispersion <-
2000 Feb 17
2
Installation of rpm file on Suse Linux 6.2 (PR#449)
Full_Name: Luzi P. Schucan
Version: R-base-0.90.1-2.i386.rpm
OS: Linux
Submission from: (NULL) (141.84.136.129)
I just wanted to install the rpm package with rpm --v -i [file], and here is the
log:
(I DID run it as root!!)
(the important thing is in the end: there must be a bug in the post install
script.
The problem is, that it does install all the files, but it doesn't correctly
hang
the
2002 Jul 11
1
dyn.load tcl/tk (PR#1774)
<<insert bug report here>>
------------------------------------------------------
Error:
R : Copyright 2002, The R Development Core Team
Version 1.5.1 (2002-06-17)
R is free software and comes with ABSOLUTELY NO WARRANTY.
You are welcome to redistribute it under certain conditions.
Type `license()' or `licence()' for distribution details.
R is a collaborative project with