search for: equidistantly

I am running ARMA model on time series data. Data consists of price changes in S&P 500 during the day, recorded at 4 predefined time stamps( 8:30, 10:30,10:15, 3:12, hence non equidistant) My question is, do I need to worry about the data being non equidistant? If so, how do I modify my series to account for it? Or is it safe to assume data as being equidistant,as it may not have a strong

Hello, I am fitting data using different methods e.g. Local Polynomial and Smoothing splines. The data is generated out of a true function model with added normally distributed noise. I would like to know "how often the confidence band for all points simultaneously contain all true values". I can answer the question for one point in the following way: e.g. #

...r to what i get with plot(x,y,type='o'). The problem is that i have to many data-points for that method, the symbols will just "melt together", as in plot(seq(1,500), seq(1,500), type='o') - just one big line. What i want is to have a configurable number of symbols spread equidistantly over the whole graph, regardless of the number or position of data-points. Does anyone have an idea how to achieve this? Thanks, Timo

This might not possible in R but I thought I would give it shot. I am have to set up a 40 x 40 cm grid of 181 points equidistant from each other. Is there any way to produce a graph with R that can do this for me? Actual sizes are unimportant as long it is to scale. Thanks -- View this message in context: http://www.nabble.com/Grid-building-in-R-tp18371874p18371874.html Sent from the R help

Hi, if I dermine the break points using the hist() function and then try to re-use these in a new histogram, R fails. Here is an example of the problem: ##First, plot a histogram: data(islands) foo <- hist(islands,freq=T) ##Now, try plot it again, with the previously determined break points: hist(islands,breaks=foo$breaks,freq=T) ##... this lead to the warning message: Warning message:

Hello, I would like to plot a wireframe of a function which is defined on the unit square using the lattice library (for trellis-like plots). The plot contains z-values of about 100 (only in the neighborhood of zero) although most of the z-values are in the range of -let's say- 0 to 10. If I evaluate this function on an equidistant grid of 25 points on the unit square the plot quality is not

Hello R Users, How to make a variable equidistance with time i.e. how to interpolate a variable if it is not sampled at equal time interval. Many thanks, Regards, Yogesh [[alternative HTML version deleted]]

Hi, I build a graph taking into account the times: 1, 2,4,6,8,10,12,15,18,21,24,28,32 and 48. Be that the scale of the X axis does not look right. It seems equidistant. (graph attached) What changes have I to do in the following commands so that the scale be correct? interaction.plot(Tempo, Trat, Valor, ylim=c(0, 2), las=1, lty=c(1,2,3,4), lwd=3, bty='l',

Hi there, I hope this question is not as stupid as the one before ... I tried to shorten my histogram (because the distribution is quite skewed and I simply don't want to see the long tail but still use the histogram plot). How can I do something like this? (The example does not work but I don't know why...) data <- rnorm(100) # as example, of course this is not skewed... h <-

Hi all, I am trying to find a way to rename R objects with names pulled from a vector of names. For example, I have a data frame, my.data.frame, and a list of names, my.names. My.names is simply the column names of my.data.frame. I want save the histogram with the column name as the name of the object. for (i in 1:ncol(my.data.frame) { tmp<-hist(my.data.frame[,i])

Full_Name: Dr. Bernd Winkler Version: 1.2.2 OS: Linux Submission from: (NULL) (194.59.179.176) Hi all, having updated to version 1.2.2 last week I experienced some strange behaviour of the hist function. I want to plot a histogram of frequencies resp. counts, for example poisson random numbers, on a predefined and fixed x scale > hist(rpois(500, 2), breaks=0:10) But instead of the

Hi, Given that cdplot() is used to produce the conditional density of a categorical y along a numerical x, it seems natural that it could be used with a date or time x (such as 'POSIXct'). Is this desirable? If so, I've created a patch that would allow this, by coercing the POSIXct x variable to produce the density, but use the original POSIXct x to draw the x axis. Index:

Hello, I have a problem with the hist() function and showing densities. The densities sum to 50 and not to 1! I use R version 2.9.1 (2009-06-26) and I load the seqinR library. My data is the following vector: [1] 0.1400000 0.2000000 0.2200000 0.2828283 0.1600000 0.1600000 0.3600000 [8] 0.1600000 0.2200000 0.2600000 0.2000000 0.3000000 0.2200000 0.2342342 [15] 0.1800000 0.2200000 0.1600000

Dear R-Listers, I have spatial data on an equidistant rectangular grid, similar to topographic data. I know that there are quite a few R-packages or base functions that provide nice iso-contours plot, but I don't want a plot, just the smoothed isocontour line of ONE level (e.g. 10 mm). Data sets are large, so it would be preferable if the availability of regular grid data could be exploited,

Dear All, I am a undergraduate using R for the first time. It seems like an excellent program and one that I look forward to using a lot over the next few years, but I have hit a very basic problem that I can't solve. I want to produce a standardised histogram, i.e. one where the area under the graph is equal to 1. I look at the manual for the histogram function and find this: freq:

Having to collect hourly electricity loads and quarter-of-an-hour electricity production data for some years I think that the tidiest way of doing it is to resort to ts but I don't know how to define such a frequency starting from a set date. Leafing through r-help mail archives I've found this *ALMOST* satisfactory message: ==========================================================

(I'm reposting this message because the original has not appeared after about 2 days. Sorry if it shows up twice.) Hello. First, thanks to those who responded to my recent inquiry about using contour() over arbitrary (x,y) by mentioning the interp() function in the akima package. That worked nicely. Now for a new question: I would like to use a pair of prediction intervals to

Hello, all; I get an unexpected result when trying to plot a probability histogram with R1.9.1 on windows xp: #with the following code: > x <- runif(100,0,1) > hist(x) > hist(x, freq=F) > h <- hist(x, freq=F) > summary(h) # Length Class Mode #breaks 11 -none- numeric #counts 10 -none- numeric #intensities 10 -none- numeric #density 10

Hi, I have a large amount of data that I would like to create a histogram of and plot and do things with in R. It is pretty much impossible to read the data into R, so I have written a program to bin the data and now have a list of counts in each bin. Is it possible to somehow import this into R and use hist(), so I can, for instance, plot the probability density? I have looked at the help page

In an experimental setup we obtain z-data samples at equidistant grid points. The surf.gls (Kriging) algorithm produces an error under this circumstance when performing the Choleski decomposition. A workaround is to dither the grid coordinates using (x <- rnorm(length(x)) ; y<- rnowm(length(y))). Question: Is this an expected behaviour of the surf.gls function ? Regards, Berthold