search for: doga

...ults in a vector for each iteration, but I cannot see how to get the data out of the loop in such a way that I can use it. I can print it but how do I get it into a set of vectors or what ever. Any help gratefully received. Thanks Example cata <- c( 3,5,6,8,0, NA) catb <- c( 1,2,3,4,5,6) doga <- c(3,5,3,6,4, 0) dogb <- c(2,4,6,8,10, 12) rata <- c (NA, 5, 5, 4, 9, 0) ratb <- c( 1,2,3,4,5,6) bata <- c( 12, 42,NA, 45, 32, 54) batb <- c( 13, 15, 17,19,21,23) id <- Cs(a,b,b,c,a,b) site <- c(1,1,4,4,1,4) mat1 <- cbind(cata, catb, doga, dogb, rata, ratb, bata, batb)...

#I have a data set that looks like this. A bit more complicated actually with # three factor levels but these calculations need to be done on one factor at a #I then have a set of different rates that are applied #to it. #dataset cata <- c( 1,1,6,1,1,2) catb <- c( 1,2,3,4,5,6) doga <- c(3,5,3,6,4, 0) data1 <- data.frame(cata, catb, doga) rm(cata,catb,doga) data1 # start rates # names for lists fnams <- c("af", "pf", "cf", "mf") mnams <- c("am", "pm", "cm", "mm") # Current layout...

...le but I am doing something wrong in the real world. In the real world I am loading a labeled data.frame. The orginal data comes from a spss file imported using spss.get but the current data.frame is a subset of the orginal spss file. EXAMPLE cata <- c( 1,1,6,1,1,NA) catb <- c( 1,2,3,4,5,6) doga <- c(3,5,3,6,4, 0) dogb <- c(2,4,6,8,10, 12) rata <- c (NA, 9, 9, 8, 9, 8) ratb <- c( 1,2,3,4,5,6) bata <- c( 12, 42,NA, 45, 32, 54) batb <- c( 13, 15, 17,19,21,23) id <- c('a', 'b', 'b', 'c', 'a', 'b') site <- c(1,1,4,4,1,4) m...

...elow. How do I apply the colnames from the matrix or names from the data.frame to label the tables in the results in the list. I know that I can do this individually but there should be a way to do something like an apply but I am missing it cata <- c( 1,1,6,1,1,NA) catb <- c( 1,2,3,4,5,6) doga <- c(3,5,3,6,4, 0) dogb <- c(2,4,6,8,10, 12) rata <- c (NA, 9, 9, 8, 9, 8) ratb <- c( 1,2,3,4,5,6) bata <- c( 12, 42,NA, 45, 32, 54) batb <- c( 13, 15, 17,19,21,23) id <- c('a', 'b', 'b', 'c', 'a', 'b') site <- c(1,1,4,4,1,4) m...

...see a solution. I have a data.frame with a number of columns where I would like 0 <- NA thus I have df1[,144:157] <- NA if df1[, 144: 157] ==0 and df1[, 190:198] <- NA if df1[, 190:198] ==0 but I cannot figure out a way do this. cata <- c( 1,1,6,1,1,NA) catb <- c( 1,2,3,4,5,6) doga <- c(3,5,3,6,4, 0) dogb <- c(2,4,6,8,10, 12) rata <- c (NA, 9, 9, 8, 9, 8) ratb <- c( 1,2,3,4,5,6) bata <- c( 12, 42,NA, 45, 32, 54) batb <- c( 13, 15, 17,19,21,23) id <- c('a', 'b', 'b', 'c', 'a', 'b') site <- c(1,1,4,4,1,4) m...

...or loop but I don't see how to handle it there either. I am sure I have seen something about exporting multiple .csv files a couple of days ago that would be relevant but I cannot find it. Can anyone suggest anything? Thanks Example: cata <- c( 3,5,6,8,0, NA) catb <- c( 1,2,3,4,5,6) doga <- c(3,5,3,6,4, 0) dogb <- c(2,4,6,8,10, 12) rata <- c (NA, 5, 5, 4, 9, 0) ratb <- c( 1,2,3,4,5,6) bata <- c( 12, 42,NA, 45, 32, 54) batb <- c( 13, 15, 17,19,21,23) id <- Cs(a,b,b,c,a,b) site <- c(1,1,4,4,1,4) Df <- data.frame(cbind(site, id, cata, catb, doga, dogb, rata...

...il adresa mogla je biti dobivena na temelju va??e prijave na web stranici Izdava??ka ku??a Poslovna Literatura d.o.o. ili ste svoj e-mail objavili u jednu od baza poslovnih subjekata, na osnovu telefonske prijave, temeljem preporuke, sudjelovanja u nagradnoj igri, popisa sudionika u obrazovanju ili doga??ajima (izlo??be, seminari, telefonska prodaja i drugi doga??aji u organizaciji poduze??a Izdava??ka ku??a Poslovna Literatura d.o.o.) ili kao odgovor na va?? upit.Ako u budu??nosti ne ??elite vi??e primati na??e obavijesti mo??ete se odjaviti s na??e liste klikom na [ Odjavi pkg-xen-devel at lists...

Dear R'sians, Would really appreciate if you could suggest a more efficient way to order the columns of a dataset. The column names of the dataset contain indices separated by a period. Following are examples of my code and the dataset. oC <- function(tg=x2) { lth <- length(grep("T",names(tg))) thix <-

...======================================================= df1 <- structure(list(site = c(1, 1, 4, 4, 1, 4), id = structure(c(1L, 2L, 2L, 3L, 1L, 2L), .Label = c("a", "b", "c"), class = "factor"), cata = c(1, 1, 6, 1, 1, NA), catb = c(1, 2, 3, 4, 5, 6), doga = c(3, 5, 3, 6, 4, 0), dogb = c(2, 4, 6, 8, 10, 12), rata = c(NA, 9, 9, 8, 9, 8), ratb = c(1, 2, 3, 4, 5, 6), bata = c(12, 42, NA, 45, 32, 54), batb = c(13, 15, 17, 19, 21, 23)), .Names = c("site", "id", "cata", "catb", "doga", "dogb&q...

...ura ) Tehni?ko upravljanje ( http://www.chm.hr/tehnicko-upravljanje ) Property managment ( http://www.chm.hr/managment/property-managment ) Facility managment ( http://www.chm.hr/managment/facility-managment ) Ostale usluge ( http://www.chm.hr/ostale-usluge ) Koliko puta ste se zapitali? * ?to se doga?a s Va?om nekretninom dok Vas nema (posebno nakon nevremena)? * Uslijed neprovjetravanja Va?a ku?a-apartman ima neugodan miris? * Primjetili ste pojavu gljivica, vlage i plijesni? * ?elite izbje?i mukotrpna ?i??enja (kada do?ete i prije nego odlazite)? * ?eljeli biste iznajmljivati nekretninu k...

hi I plot a series of observation data every minutes in a day as the attachment below plot(wnd,type='l',lty=1,col='red',lwd=1,xlab=xxlab,ylab=yylab,ylim=YY) In the figure, the x-axis tickment is the number of data How can I change it fore example 1h 2h 3h 4h and so on ? -- TANG Jie Email: totangjie at gmail.com Tel: 0086-2154896104 Shanghai Typhoon Institute,China