search for: diseases

Displaying 20 results from an estimated 571 matches for "diseases".

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2008 Nov 17
1
Type III ANOVA of package car depends on factor level order
## Question1: How to define IV with interaction alone, without main effects? ## Question2: Should Type III ANOVA in package car be independent of the factor level order? ## data from http://www.otago.ac.nz/sas/stat/chap30/sect52.htm drug <- c(t(t(rep(1,3)))%*%t(1:4)); disease <- c(t(t(1:3)) %*% t(rep(1,4))); y <- t(matrix(c( 42 ,44 ,36 ,13 ,19 ,22 ,33 ,NA ,26 ,NA ,33 ,21 ,31 ,-3 ,NA
2003 Jul 26
1
A model for disease progression
I would be grateful for advice about the following problem. It's not directly R-related, but I'm hoping that R will help me analyse the following data. I have a table which indicates the progression of a certain age-related disease. At a certain point in time, a population was sampled; and I have measurements for the age of each individual, and their disease stage. (Disease stage is an
2011 Sep 12
3
Multiple t.test
Dear R experts, Suppose I have an data frame likes this: > example <- data.frame(age=c(1,2,3, 4,5,6), height=c(100,110,120,130,140,150), disease=c(TRUE, TRUE, TRUE, FALSE, FALSE, FALSE)) > example age height disease 1 1 100 TRUE 2 2 110 TRUE 3 3 120 TRUE 4 4 130 FALSE 5 5 140 FALSE 6 6 150 FALSE Is there anyway to compare the age and
2005 Sep 12
6
trouble with reading data from excel
I have been trying to open data that I have saved in an excel spread sheet. I saved it as a csv. Then I tried using the read.csv command. However, everytime I do this-- diseasedat<-read.csv("M:/sloan/R/disease/disease.csv", sep=, header = TRUE, fill= TRUE)-- I get an error message: Error in file(file, "r") : unable to open connection In addition: Warning message:
2007 Feb 09
1
Using variable names in for loops - Generating plots semi-automatically from a series of variables Partly solved
...variables called 'Male_CVD, Female_CVD,Male_RTA,Female_RTA, and so on. For each disease, I want to pull out the column of data containing the word 'Male' and plot this against age, and then add a line to the plot for the corresponding column containing 'Female'. -- attach(data) Diseases <- c("Cardiovascular disease","Road Traffic Injury", ... ,"All causes") Male <- names(data)[grep("Male",names(data))] Female <- names(data)[grep("Female",names(data))] #Disease contains disease labels in the correct order, and Male and Fem...
2009 Nov 14
2
formatting dates in axis labels (ggplot2)
I'm having trouble figuring out how to format Date variables when used as axis labels in graphs. The particular case here is an attempt to re-create Nightingale's coxcomb graph with ggplot2, where I'd like the months to be labeled as "Mar 1885", "Apr 1885", using a date format of "%b %Y" applied to label the dates, or really anything other than
2009 Aug 26
2
Statistical question about logistic regression simulation
Hi R help list I'm simulating logistic regression data with a specified odds ratio (beta) and have a problem/unexpected behaviour that occurs. The datasets includes a lognormal exposure and diseased and healthy subjects. Here is my loop: ors <- vector() for(i in 1:200){ # First, I create a vector with a lognormally distributed exposure: n <- 10000 # number of study subjects
2008 Mar 10
3
A stats question -- about survival analysis and censoring
Dear UseRs, Suppose I have data regarding smoking habits of a prospective cohort and wish to determine the risk ratio of colorectal cancer in the smokers compared to the non-smokers. What do I do at the end of the study with people who die of heart disease? Can I just censor them exactly the same as people who become uncontactable or who die in a plane crash? If not, why not? I'm thinking
2009 Jul 09
2
datadist() in Design library
Hi I got an error message using datadist() from Design package: > library(Design,T) > dd <- datadist(beta.final) > options(datadist="dd") > lrm(Disease ~ gsct+apcct+rarct, x=TRUE, y=TRUE) Error in eval(expr, envir, enclos) : object "Disease" not found All variables inclduing response variable "Disease" are in the data frame
2017 Jul 05
3
Question about correlation
Greeting. Dear Mr/Mrs/Miss, OTU ID Health Disease Bacterial 1 0.29 0.34 Bacterial 2 0.25 0.07 Bacterial 3 0.06 0.06 Bacterial 4 0.07 0.09 Bacterial 5 0.02 0.05 Above show the first 6 data sets, may I ask that the reason of R show the error like "Error in cor(data) : 'x' must be numeric" ? And how to solve it? Besides, isn't this data can conduct correlation matrix?
2017 Jul 05
0
Question about correlation
Hi Chin Yi, If you are trying to correlate "Health" with "Disease", i.e. cydf<-read.table(text="OTU ID Health Disease Bacterial 1 0.29 0.34 Bacterial 2 0.25 0.07 Bacterial 3 0.06 0.06 Bacterial 4 0.07 0.09 Bacterial 5 0.02 0.05", header=TRUE) print(cor(cydf$Health,cydf$Disease)) [1] 0.7103517 If you are getting that error, it probably means that
2007 Aug 11
1
binomial simulation
hello, I asked about this simulation a few days ago, but still i can't get what i need. I have 2 units: icu and regular. from icu I want to take 200 observations from binomial distribution, when probability for disease is: p=0.6. from regular I want to take 300 observation with the same probability: p=0.6 . the distribution to detect disease when disease occurred- *for someone from icu* - is:
2008 Mar 22
1
Simulating Conditional Distributions
Dear R-Help List, I'm trying to simulate data from a conditional distribution, and haven't been able to modify my existing code to do so. I searched the archives, but didn't find any previous post that matched my question. n=10000 pop = data.frame(W1 = rbinom(n, 1, .2), W2 = runif(n, min = 3, max = 8), W3 = rnorm(n, mean=0, sd=2)) pop = transform(pop, A = rbinom(n, 1,
2017 Jul 05
2
Question about correlation
On 2017-07-05 11:56, Jim Lemon wrote: > Hi Chin Yi, > If you are trying to correlate "Health" with "Disease", i.e. > > cydf<-read.table(text="OTU ID Health Disease > Bacterial 1 0.29 0.34 > Bacterial 2 0.25 0.07 > Bacterial 3 0.06 0.06 > Bacterial 4 0.07 0.09 > Bacterial 5 0.02 0.05", > header=TRUE) >
2009 Jul 20
3
Re gression using age and Duration of disease as a continous factors
Please explain me as what it means and how this analysis can be done using R and which library(ies) are needed. Thanks -- View this message in context: http://www.nabble.com/Regression-using-age-and-Duration-of-disease-as-a-continous-factors-tp24574133p24574133.html Sent from the R help mailing list archive at Nabble.com.
2008 Feb 13
1
Modelling disease spread
I was at a lecture the other day and I saw a presentation of very neat (short) animation modeling epidemic disease spread over a map region. When I ask what software they used they mentioned SAS. Do you know if there are equivalent resources in R to model the spread of disease with animation output? My search in R-help and google didn't lead to any document (though I found a couple of
2004 Dec 31
2
Supressing empty sections with Sweave
...report has several sections along the lines of: \section*{Disease X} <<MapX,fig=TRUE,echo=FALSE>>= image(vectorx,vectory,matrixz) @ Notes with or without Sexpr{a}. \vfill \pagebreak \section*{Disease Y} <<MapY,fig=TRUE,echo=FALSE>>= ...etc. Often one or more of the diseases is not observed (all values in matrixz are 0), in which case I would prefer not to display the section at all. Does any one no whether it is possible automate this with Sweave? Mikkel
2009 Jan 30
3
paste together object names to pass it on to a function
...sub-lists/dataframes, which I want to specify with a name vector and paste together the object name and pass it on to a function. Here an (hopefully) instructive example #Data Example gnuff<-list() gnuff$IHD$LE<-66 gnuff$LUNG$LE <-55 #This is the list, where I collect data for different diseases at the second level of the list #Now I want to do calcualtions just for these two diseases and the sub-list "LE" within these diseases nam <- c("LUNG","IHD") for(i in 1:2) x[i] <- paste("gnuff",nam[i],"LE",sep="$") /2 x #So I try...
2005 Mar 04
0
Need suggestions for finding dose response using nls
I am relatively new to R and am looking for advice, ideas or both... I have a data set that consists of pathogen population sizes on individual plant units in an experimental field plot. However, in order to estimate the pathogen population sizes I had to destroy the plant unit and could not determine if that plant unit became diseased or to what extent it would have become diseased. I
2007 May 03
4
Survival statistics--displaying multiple plots
Hello all! I am once again analyzing patient survival data with chronic liver disease. The severity of the liver disease is given by a number which is continuously variable. I have referred to this number as "meld"--model for end stage liver disease--which is the result of a mathematical calculation on underlying laboratory values. So, for example, I can generate a Kaplan-Meier plot