Displaying 20 results from an estimated 571 matches for "disease".
2008 Nov 17
1
Type III ANOVA of package car depends on factor level order
## Question1: How to define IV with interaction alone, without main effects?
## Question2: Should Type III ANOVA in package car be independent of
the factor level order?
## data from http://www.otago.ac.nz/sas/stat/chap30/sect52.htm
drug <- c(t(t(rep(1,3)))%*%t(1:4));
disease <- c(t(t(1:3)) %*% t(rep(1,4)));
y <- t(matrix(c(
42 ,44 ,36 ,13 ,19 ,22
,33 ,NA ,26 ,NA ,33 ,21
,31 ,-3 ,NA ,25 ,25 ,24
,28 ,NA ,23 ,34 ,42 ,13
,NA ,34 ,33 ,31 ,NA ,36
,3 ,26 ,28 ,32 ,4 ,16
,NA ,NA ,1 ,29 ,NA ,19
,NA ,11 ,9 ,7 ,1 ,-6
,21 ,1 ,NA ,9 ,3 ,NA
,24 ,NA ,9 ,22 ,-2 ,15
,2...
2003 Jul 26
1
A model for disease progression
I would be grateful for advice about the following problem. It's not
directly R-related, but I'm hoping that R will help me analyse the
following data.
I have a table which indicates the progression of a certain age-related
disease. At a certain point in time, a population was sampled; and I have
measurements for the age of each individual, and their disease stage.
(Disease stage is an ordered factor, none<A<B<C<D.)
I hypothesize that the rate of disease-onset depends on age, but that
(once the disease has start...
2011 Sep 12
3
Multiple t.test
Dear R experts,
Suppose I have an data frame likes this:
> example <- data.frame(age=c(1,2,3, 4,5,6), height=c(100,110,120,130,140,150), disease=c(TRUE, TRUE, TRUE, FALSE, FALSE, FALSE))
> example
age height disease
1 1 100 TRUE
2 2 110 TRUE
3 3 120 TRUE
4 4 130 FALSE
5 5 140 FALSE
6 6 150 FALSE
Is there anyway to compare the age and height between those with
disease=TRUE and disease=FALSE...
2005 Sep 12
6
trouble with reading data from excel
I have been trying to open data that I have saved in an excel spread sheet. I saved it as a csv. Then I tried using the read.csv command. However, everytime I do this--
diseasedat<-read.csv("M:/sloan/R/disease/disease.csv", sep=, header = TRUE, fill= TRUE)--
I get an error message:
Error in file(file, "r") : unable to open connection
In addition: Warning message:
cannot open file 'M:/sloan/R/disease/disease.csv'
What am I doing wrong o...
2007 Feb 09
1
Using variable names in for loops - Generating plots semi-automatically from a series of variables Partly solved
Hi,
This code is trying to produce a series of graphics files, with plots
of male and female disease rates by age, one plot per disease. The
dataframe contains a variable 'Age' and a set of variables called
'Male_CVD, Female_CVD,Male_RTA,Female_RTA, and so on. For each
disease, I want to pull out the column of data containing the word
'Male' and plot this against age, and then...
2009 Nov 14
2
formatting dates in axis labels (ggplot2)
...42248, -42217, -42187,
-42156, -42125, -42095, -42064, -42034, -42003, -41972, -42278,
-42248, -42217, -42187, -42156, -42125, -42095, -42064, -42034,
-42003, -41972, -42278, -42248, -42217, -42187, -42156, -42125,
-42095, -42064, -42034, -42003, -41972), class = "Date"), Cause =
c("Disease",
"Disease", "Disease", "Disease", "Disease", "Disease", "Disease",
"Disease", "Disease", "Disease", "Disease", "Wounds", "Wounds",
"Wounds", "Wounds", &q...
2009 Aug 26
2
Statistical question about logistic regression simulation
Hi R help list
I'm simulating logistic regression data with a specified odds ratio
(beta) and have a problem/unexpected behaviour that occurs.
The datasets includes a lognormal exposure and diseased and healthy
subjects.
Here is my loop:
ors <- vector()
for(i in 1:200){
# First, I create a vector with a lognormally distributed exposure:
n <- 10000 # number of study subjects
mean <- 6
sd <- 1
expo <- rlnorm(n, mean, sd)
# Then I assign each study subject a probability of...
2008 Mar 10
3
A stats question -- about survival analysis and censoring
Dear UseRs,
Suppose I have data regarding smoking habits of a prospective cohort and wish
to determine the risk ratio of colorectal cancer in the smokers compared to
the non-smokers. What do I do at the end of the study with people who die
of heart disease? Can I just censor them exactly the same as people who become
uncontactable or who die in a plane crash? If not, why not?
I'm thinking that heart disease isn't independent of smoking even though
a death from heart disease is probably uninformative about colorectal
cancer risk. Hence
I sus...
2009 Jul 09
2
datadist() in Design library
Hi I got an error message using datadist() from Design package:
> library(Design,T)
> dd <- datadist(beta.final)
> options(datadist="dd")
> lrm(Disease ~ gsct+apcct+rarct, x=TRUE, y=TRUE)
Error in eval(expr, envir, enclos) : object "Disease" not found
All variables inclduing response variable "Disease" are in the data frame "beta.final", why then "Disease" can not be found? I thought with datadist(), all va...
2017 Jul 05
3
Question about correlation
Greeting.
Dear Mr/Mrs/Miss,
OTU ID Health Disease
Bacterial 1 0.29 0.34
Bacterial 2 0.25 0.07
Bacterial 3 0.06 0.06
Bacterial 4 0.07 0.09
Bacterial 5 0.02 0.05
Above show the first 6 data sets, may I ask that the reason of R show the
error like "Error in cor(data) : 'x' must be numeric" ? And how to solve
it? Besides, isn't t...
2017 Jul 05
0
Question about correlation
Hi Chin Yi,
If you are trying to correlate "Health" with "Disease", i.e.
cydf<-read.table(text="OTU ID Health Disease
Bacterial 1 0.29 0.34
Bacterial 2 0.25 0.07
Bacterial 3 0.06 0.06
Bacterial 4 0.07 0.09
Bacterial 5 0.02 0.05",
header=TRUE)
print(cor(cydf$Health,cydf$Disease))
[1] 0.7103517
If you are getting that error, it proba...
2007 Aug 11
1
binomial simulation
hello,
I asked about this simulation a few days ago, but still i can't get what i
need.
I have 2 units: icu and regular. from icu I want to take 200 observations
from binomial distribution, when probability for disease is: p=0.6.
from regular I want to take 300 observation with the same probability: p=0.6
.
the distribution to detect disease when disease occurred- *for someone from
icu* - is: p(T+ | D+)=0.95.
the distribution to detect disease when disease occurred- *for someone from
reg.unit* - is: p(T+ | D+)=0....
2008 Mar 22
1
Simulating Conditional Distributions
....
n=10000
pop = data.frame(W1 = rbinom(n, 1, .2),
W2 = runif(n, min = 3, max = 8), W3 = rnorm(n, mean=0, sd=2))
pop = transform(pop,
A = rbinom(n, 1, .5))
pop = transform(pop,
Y = rbinom(n, 1, 1/(1+exp(-(1.5*A-.05*W1-2*W2-2*W3+2*A*W1)))))
In this population the probability of being "diseased" (Y=1) is
approx 0.030. What I want to be able to do is specify a conditional
distribution of (A, W1, W2, W3) given that Y=1 and one for (A, W1,
W2, W3) given that Y=0. Then I can sample diseased and non-diseased
individuals from these distributions without having to simulate a
la...
2017 Jul 05
2
Question about correlation
On 2017-07-05 11:56, Jim Lemon wrote:
> Hi Chin Yi,
> If you are trying to correlate "Health" with "Disease", i.e.
>
> cydf<-read.table(text="OTU ID Health Disease
> Bacterial 1 0.29 0.34
> Bacterial 2 0.25 0.07
> Bacterial 3 0.06 0.06
> Bacterial 4 0.07 0.09
> Bacterial 5 0.02 0.05",
> header=TRUE)
> print(cor(cydf$Health,cydf$Disease))
>...
2009 Jul 20
3
Re gression using age and Duration of disease as a continous factors
Please explain me as what it means and how this analysis can be done using R
and which library(ies) are needed.
Thanks
--
View this message in context: http://www.nabble.com/Regression-using-age-and-Duration-of-disease-as-a-continous-factors-tp24574133p24574133.html
Sent from the R help mailing list archive at Nabble.com.
2008 Feb 13
1
Modelling disease spread
I was at a lecture the other day and I saw a presentation of very neat
(short) animation modeling epidemic disease spread over a map region. When I
ask what software they used they mentioned SAS. Do you know if there are
equivalent resources in R to model the spread of disease with animation
output? My search in R-help and google didn't lead to any document (though I
found a couple of documents for SAS). Ho...
2004 Dec 31
2
Supressing empty sections with Sweave
Dear useRs,
I'm writing regular survey reports using Sweave. Each
report has several sections along the lines of:
\section*{Disease X}
<<MapX,fig=TRUE,echo=FALSE>>=
image(vectorx,vectory,matrixz)
@
Notes with or without Sexpr{a}.
\vfill
\pagebreak
\section*{Disease Y}
<<MapY,fig=TRUE,echo=FALSE>>=
...etc.
Often one or more of the diseases is not observed (all
values in matrixz are 0), in which ca...
2009 Jan 30
3
paste together object names to pass it on to a function
...sub-lists/dataframes, which I
want to specify with a name vector and paste together the object name
and pass it on to a function.
Here an (hopefully) instructive example
#Data Example
gnuff<-list()
gnuff$IHD$LE<-66
gnuff$LUNG$LE <-55
#This is the list, where I collect data for different diseases at the
second level of the list
#Now I want to do calcualtions just for these two diseases and the
sub-list "LE" within these diseases
nam <- c("LUNG","IHD")
for(i in 1:2)
x[i] <- paste("gnuff",nam[i],"LE",sep="$") /2
x
#So I tr...
2005 Mar 04
0
Need suggestions for finding dose response using nls
...oking for advice, ideas or both...
I have a data set that consists of pathogen population sizes on
individual plant units in an experimental field plot. However, in
order to estimate the pathogen population sizes I had to destroy the
plant unit and could not determine if that plant unit became diseased
or to what extent it would have become diseased. I collected disease
data from each plot and have estimates of the disease in an
experimental plot several days after the pathogen population sizes were
estimated. From this data I would like to determine a dose-response
relationship in the fie...
2007 May 03
4
Survival statistics--displaying multiple plots
Hello all!
I am once again analyzing patient survival data with chronic liver disease.
The severity of the liver disease is given by a number which is continuously
variable. I have referred to this number as "meld"--model for end stage
liver disease--which is the result of a mathematical calculation on
underlying laboratory values. So, for example, I can generate a Kapla...