search for: destruirlo

...onal, le informamos de que el presente mensaje contiene informaci?n confidencial, siendo para uso exclusivo del destinatario arriba indicado. En caso de no ser usted el destinatario del mismo le informamos que su recepci?n no le autoriza a su divulgaci?n o reproducci?n por cualquier medio, debiendo destruirlo de inmediato, rog?ndole lo notifique al remitente.

Dear All I would need to perform a MANOVA with both fixed (group, sex, group*sex) and random (brood) effects. I wonder if this is at all possible and if R does that. At the moment, I only know that I can run a classic MANOVA with R. Thank you David ______________________________________________ David Costantini, PhD http://www.davidcostantini.it NERC Postdoctoral research associate

...onal, le informamos de que el presente mensaje contiene informaci?n confidencial, siendo para uso exclusivo del destinatario arriba indicado. En caso de no ser usted el destinatario del mismo le informamos que su recepci?n no le autoriza a su divulgaci?n o reproducci?n por cualquier medio, debiendo destruirlo de inmediato, rog?ndole lo notifique al remitente.

...onal, le informamos de que el presente mensaje contiene informaci?n confidencial, siendo para uso exclusivo del destinatario arriba indicado. En caso de no ser usted el destinatario del mismo le informamos que su recepci?n no le autoriza a su divulgaci?n o reproducci?n por cualquier medio, debiendo destruirlo de inmediato, rog?ndole lo notifique al remitente.

...onal, le informamos de que el presente mensaje contiene informaci?n confidencial, siendo para uso exclusivo del destinatario arriba indicado. En caso de no ser usted el destinatario del mismo le informamos que su recepci?n no le autoriza a su divulgaci?n o reproducci?n por cualquier medio, debiendo destruirlo de inmediato, rog?ndole lo notifique al remitente.

...onal, le informamos de que el presente mensaje contiene informaci?n confidencial, siendo para uso exclusivo del destinatario arriba indicado. En caso de no ser usted el destinatario del mismo le informamos que su recepci?n no le autoriza a su divulgaci?n o reproducci?n por cualquier medio, debiendo destruirlo de inmediato, rog?ndole lo notifique al remitente. _______________________________________________ R-packages mailing list R-packages at r-project.org https://stat.ethz.ch/mailman/listinfo/r-packages

...onal, le informamos de que el presente mensaje contiene informaci?n confidencial, siendo para uso exclusivo del destinatario arriba indicado. En caso de no ser usted el destinatario del mismo le informamos que su recepci?n no le autoriza a su divulgaci?n o reproducci?n por cualquier medio, debiendo destruirlo de inmediato, rog?ndole lo notifique al remitente. _______________________________________________ R-packages mailing list R-packages at r-project.org https://stat.ethz.ch/mailman/listinfo/r-packages

Hello, I have created two boxplots with following R code. There is one outlier in B group. The outlier is 33. But the all other data are between 0 to 4. How can I skip y-axis around 5 to 25, and expand 0-4 for this case. Also I want keep the outlier in my boxplot. I want my boxplot look like the second one, keep the outlier, and make an interrupt of y-axis from 5 to 25. Thanks, Jianghong

Hello, When plotting a barchart with ggplot it drops the levels of the factor for which no counts are available. For example: library(ggplot) mtcars$cyl<-factor(mtcars$cyl) ggplot(mtcars[!mtcars$cyl==4,], aes(cyl))+geom_bar() levels(mtcars[!mtcars$cyl==4,]) This shows my problem. Because no counts are available for factorlevel '4', the label 4 dissapears from the plot. However, I

Hi All, I have data about seed predation (SP) in fruits of three differents colors (yellow, motted, dark) and in two fruiting seasons (2007, 2008). I performed a GLMM (lmer function, lme4 package) and the outcome showed that the interaction term (color:season) was significant, and some combinations of this interaction have significant Pr(>|z|), but I don't think they are the right

...onal, le informamos de que el presente mensaje contiene informaci?n confidencial, siendo para uso exclusivo del destinatario arriba indicado. En caso de no ser usted el destinatario del mismo le informamos que su recepci?n no le autoriza a su divulgaci?n o reproducci?n por cualquier medio, debiendo destruirlo de inmediato, rog?ndole lo notifique al remitente.

Dear R users, I have a very basic query, but was unable to find a proper anwser. I have the following data.frame x y 2 0.12 3 0.25 4 0.11 6 0.16 7 0.20 and, due to further calculations, I need the data to be stored as x y 1 0 2 0.12 3 0.25 4 0.11 5 0 6 0.16 7 0.20 8 0 How do

Hi, In the R console, I have the following: > runif(10) Error in runif(10) : '.Random.seed' is not an integer vector but of type 'list' > Can someone advise me of the solution of the problem? Mei-Yuan Chen Department of Finance NCHU, aiwan

Hello all, So I am using the (formula entry) method for randomForests: randomForest(y~x1+x2+...+x39+x40,data=xxx,...) but the issue is that some of the items in that package dont take a formula entry - you have to explicitly state the y and x vector: randomForest(x=xxx[,c('x1','x2',...,'x40')],y=xxx[,'y'],...) Now my question is whether there is a function/way

Dear all, I have a (probably very basic) question. I am imputing data with the mice package, using 10 chains. I can then write out the 10 final values of the chains simply by name1 <- complete(imp, 1) : : name10 <- complete(imp,10) Not a big deal, I just wanted to do that in a little loop as follows: for (i in 1:10){ set[i] <-

Hi all, I have been struggling with ANOVAs on R. I am new to R, so I created a simple data frame, and I do some analyses on R just to learn R and then check them on SPSS to make sure that I am doing fine. Here is the problem that I've run into: when we use the aov function, it uses SS Type I as default (on SPSS it is Type III). Then I used the Anova function under cars package using the

Hi All, I am frustrated by mixed-effects model! I have searched the web for hours, and found lots on the nested anova, but nothing useful on my specific case, which is: a random factor (C) is nested within one of the fixed-factors (A), and a second fixed factor (B) is crossed with the first fixed factor: C/A A B A x B My question: I have a functioning model using the aov command (see

Hi all, several packages print messages during loading. How do I avoid to see them when the packages are in the defaultPackages? Here is an example. With this in ~/.Rprofile ,----[ ~/.Rprofile ] | old <- getOption("defaultPackages") | options(defaultPackages = c(old, "filehash")) | rm(old) `---- I get as last line when starting R: ,---- | filehash: Simple key-value

...onal, le informamos de que el presente mensaje contiene informaci?n confidencial, siendo para uso exclusivo del destinatario arriba indicado. En caso de no ser usted el destinatario del mismo le informamos que su recepci?n no le autoriza a su divulgaci?n o reproducci?n por cualquier medio, debiendo destruirlo de inmediato, rog?ndole lo notifique al remitente.

To whom it may concern I made some analysis with R using the command Anova. However, I found some problmes with the output obtained by selecting type II o type III sum of squares. Briefly, I have to do a 2x3 mixed model anova, wherein the first factor is a between factor and the second factor is a within factor. I use the command Anova in the list below, because I want to obtain also the sum