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...ion auth.ip.brick-afr.allow * # Allow access to "brick-afr" volume option auth.ip.brick-locks.allow * # Allow access to "brick-locks" volume end-volume Thanks! P.S. Is there a way to search the mailing list archive? - Tony Bussi?res Valeurs mobili?res Desjardins - TI - L'int?grit? des informations transmises dans ce courriel n?est pas garantie par Valeurs mobili?res Desjardins, qui d?cline toute responsabilit? quant aux dommages caus?s par leur modification frauduleuse. Ce courriel est confidentiel et est ? l?usage exclusif de so...

Hi, I am trying to write a loop to recode my data from -999 to NA in R. What's the most efficient way to do this? Below is what I'm presently doing, which is inefficient. Thanks, Chris dat0 <- read.table("time1.dat") colnames(dat0) <- c("e1dq", "e1arcp", "e1dev", "s1prcp", "s1nrcp", "s1ints",

Hi, All, I am implementing real-time Rsync on Windows 2008 system. I set up Rsync server and Rsync client on two machines. An windows service is watching all the Windows file events with FileSystemWatcher. However, the service cannot tell the exactly what happened to folders such as create, delete, or modified. So, I ignored folder event, and only catch file changing events. After I catch

I have 3 vectors: p1, p2, and p3. I would like each vector to be any possible value between 0 and 1 and p1 + p2 + p3 = 1. I want to graph these and I've thought about using scatterplot3d(). Here's what I have so far. library(scatterplot3d) p1 <- c(1,0,0,.5,.5,0,.5,.25,.25,.34,.33,.33,.8,.1,.1,.9,.05,.05) p2 <- c(0,1,0,.5,0,.5,.25,.5,.25,.33,.34,.33,.1,.8,.1,.05,.9,.05) p3 <-

Is it possible to create a list or a vector with tags being numbers? e.g. a <- list(1=2, 3=4) thanks, miguel -.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.- r-help mailing list -- Read http://www.ci.tuwien.ac.at/~hornik/R/R-FAQ.html Send "info", "help", or "[un]subscribe" (in the "body", not the subject !) To:

Hi, I have longitudinal school suspension data on students. I would like to figure out how many students (id_r) have no suspensions (sus), i.e. have a code of '0'. My data is in long format and the first 20 records look like the following: > suslm[1:20,c(1,7)] id_r sus 11 0 15 10 16 0 18 0 19 0 19 0 20 0 21 0 21 0 22 0 24 0 24

...iendly, yet powerful vector drawing application for SVG, Krita - a rapidly maturing "natural" painting application, Open Clip Art Library - a large public domain collection of freely available artwork, and many other projects focussed on graphics creation and editing. According to Louis Desjardins, a 20 year veteran of pre-press and print production and organiser of the conference: "LGM is a sure demonstration of the maturity of free and open source applications - even at a professional level. Not only that, never before have I seen such a close and amicable working relationship between...

...ght problems) differs by this covariate. However, I have siblings in my data set (famid) and I would like to account for this shared variability. How might I do this in R? Can I do it with the survival library? If possible, I'd also like to control for sex. Thanks, Chris -- Christopher David Desjardins PhD student, Quantitative Methods in Education MS student, Statistics University of Minnesota 192 Education Sciences Building http://cddesjardins.wordpress.com

Hi, Let's say I have the following data: > a=matrix(c(1,2,4,4,2,1,1,2,4),nrow=3,byrow=T) > a [,1] [,2] [,3] [1,] 1 2 4 [2,] 4 2 1 [3,] 1 2 4 What syntax should I use to get R to tell me the column that corresponds to the maximum value for each row? For my example, I would like to get a vector that says 3, 1, 3 because the maximum value for row 1 is

...0 6 Is there some sort of way that I can overcome this? Is my model misspecified? Is this better suited to be run as a Bayesian model using priors to overcome the lack of a mixed response? Also, please cc me on an email as I am a digest subscriber. Thanks, Chris -- Christopher David Desjardins PhD student, Quantitative Methods in Education MS student, Statistics University of Minnesota 192 Education Sciences Building http://cddesjardins.wordpress.com

Hi, I am having trouble with syntax for a for loop. Here is what I am trying to do. class=c(rep(1,3),rep(2,3),rep(3,3)) out1=rnorm(length(class)) out2=rnorm(length(class)) out3=rnorm(length(class)) data=data.frame(class,out1,out2,out3) dat.split=split(data,data$class) for(i in 1:3){ sub[i]=dat.split[i] } However, the for loop doesn't work. I want to assign each split to a different

Hi, I am trying to recreate the right graph on page 524 of Gelman's 2006 paper "Prior distributions for variance parameters in hierarchical models" in Bayesian Analysis, 3, 515-533. I am only interested, however, in recreating the portion of the graph for the overlain prior density for the half-Cauchy with scale 25 and not the posterior distribution. However, when I try:

Hi, I am wondering if there is a way to call Gnuplot from R and/or if anyone can recommend a package on CRAN capable of doing this? Thanks, Chris PS - Please cc me on the response. [[alternative HTML version deleted]]

Hi, I have my data the following way: y A B C 0 1 1 2 0 1 2 1 1 1 1 2 0 1 1 2 1 1 1 2 1 1 2 1 0 1 2 2 . . . And so on. How can I make my data look like the following: y A B C 2 1 1 2 1 1 2 1 0 1 2 2 . . . In other words how can I change my ungrouped cases into grouped cases? Thanks! Chris [[alternative

I get the following error when I run qplot() qplot(grade, read,data = hhm.long.m, geom = c("point", "smooth")) Error in smooth.construct.cr.smooth.spec(object, data, knots) : x has insufficient unique values to support 10 knots: reduce k. I am not sure how to tackle this problem. When I take a subsample (< 1000) than I am able to run that function but with my sample

I have a data frame in long format and I would like to randomly divide this data frame in half. The data frame consists of 39622 rows and I initially tried ... randomsample1 <- data[sample(nrow(data),19811), ] Where allows me to randomly select half of the rows and assign them to randomsample1 but then I couldn't figure out how to select those rows that were not selected and assign

Hi, When I zoom into a graph created in ggplot2 with the coord_cartesian(ylim=c(0,5)) option, I have no values labelled on my y-axis. For this graph ggplot2 only puts labels the y-axis at intervals of 10 (i.e. 0, 10, 20, ...). However, the major portion of the graph I am interested in is located between the values of 0 and 5 on the y-axis (thus why I am zoooming). How can I coerce ggplot2 into

Hi, I am trying to replicate Lambert (1992)'s simulation with zero-inflated Poisson models. The citation is here: @article{lambert1992zero, Author = {Lambert, D.}, Journal = {Technometrics}, Pages = {1--14}, Publisher = {JSTOR}, Title = {Zero-inflated {P}oisson regression, with an application to defects in manufacturing}, Year = {1992}} Specifically I am trying to recreate Table 2. But my

..."rebal.new")]))) axis(side = 4, at = pretty.bar, line = 0, mgp = c(2, 2, 0), las = 2, col.axis = 1, cex.axis = 0.80) Any suggestions??? Thanks in advance, G?rald Jean Conseiller senior en statistiques, VP Actuariat et Solutions d'assurances, Desjardins Groupe d'Assurances G?n?rales t?lephone : (418) 835-4900 poste (7639) t?lecopieur : (418) 835-6657 courrier ?lectronique: gerald.jean at dgag.ca

Hi, I have the following data: > data[1:20,c(1,2,20)] idr schyear year 1 8 0 1 9 1 1 10 NA 2 4 NA 2 5 -1 2 6 0 2 7 1 2 8 2 2 9 3 2 10 4 2 11 NA 2 12 6 3 4 NA 3 5 -2 3 6 -1 3 7 0 3 8 1 3 9 2 3 10 3 3 11 NA What I want to do is